EduNinja
[Maximum number: 2]

Iodine is found naturally in compounds in many different oxidation states.

(a)

Iodide ions, I\mathrm{I}^{-}, react with acidified H2O2(aq)\mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{aq}) to form iodine, I2\mathrm{I}_{2}, and water. This reaction mixture is shaken with cyclohexane, C6H12\mathrm{C}_{6} \mathrm{H}_{12}, to extract the I2\mathrm{I}_{2}. Cyclohexane is immiscible with water.

[ 2 ]
(i)

15.0 cm315.0 \mathrm{~cm}^{3} of C6H12\mathrm{C}_{6} \mathrm{H}_{12} is shaken with 20.0 cm320.0 \mathrm{~cm}^{3} of an aqueous solution containing I2\mathrm{I}_{2} until no further change is seen.
It is found that 0.390 g of I2\mathrm{I}_{2} is extracted into the C6H12\mathrm{C}_{6} \mathrm{H}_{12}.
The partition coefficient of I2\mathrm{I}_{2} between C6H12\mathrm{C}_{6} \mathrm{H}_{12} and water, KpcK_{\mathrm{pc}}, is 93.8.
Calculate the mass of I2\mathrm{I}_{2} that remains in the aqueous layer.
Show your working.
mass of I2I_{2} in aqueous layer =

(ii)

Suggest how the value of KpcK_{p c} of I2\mathrm{I}_{2} between hexan-2-one, CH3(CH2)3COCH3\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{3} \mathrm{COCH}_{3}, and water compares to the value given in (a)(ii). Explain your answer.

[ 2 ]
(a)
(i)

Explain what is meant by the term partition coefficient, Kpartition K_{\text {partition }}.

[ 2 ]
(ii)

The partition coefficient of organic compound H between dichloromethane and water is 4.75.
- 2.50 g of compound H was dissolved in water and made up to 100 cm3100 \mathrm{~cm}^{3} in a volumetric flask.
- 50 cm350 \mathrm{~cm}^{3} of this aqueous solution were shaken with 10 cm310 \mathrm{~cm}^{3} of dichloromethane.

Calculate the mass of compound H that was extracted into the dichloromethane.
mass of compound H extracted =

[ 2 ]
[Maximum number: 6]

Ethoxyethane, C2H5OC2H5\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OC}_{2} \mathrm{H}_{5}, can dissolve both in water and in octan-1-ol. The expression and numerical value for the partition coefficient of ethoxyethane between water and octan-1-ol are given. Water and octan-1-ol are immiscible.

Kpc= concentration of C2H5OC2H5 in octan-1-ol  concentration of C2H5OC2H5 in water =6.760 at 20CK_{\mathrm{pc}}=\frac{\text { concentration of } \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OC}_{2} \mathrm{H}_{5} \text { in octan-1-ol }}{\text { concentration of } \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OC}_{2} \mathrm{H}_{5} \text { in water }}=6.760 \text { at } 20^{\circ} \mathrm{C}
(a)

In an experiment, octan-1-ol at 20C20^{\circ} \mathrm{C} is added to a solution of ethoxyethane in water at 20C20^{\circ} \mathrm{C}. The mixture is analysed immediately and a value of KpcK_{p c} is calculated.

The calculation is performed correctly; the value calculated is 5.625 .
Explain why the value calculated is less than 6.760.

[ 2 ]
(b)

A second experiment is performed and the value of KpcK_{\mathrm{pc}} is found to be 6.760. The concentration of ethoxyethane in the octan-1-ol layer is 7.62 gdm37.62 \mathrm{~g} \mathrm{dm}^{-3}.

[ 4 ]
(i)

Calculate the concentration, in gdm3\mathrm{g} \mathrm{dm}^{-3}, of ethoxyethane in the aqueous layer. gdm3\mathrm{gdm}^{-3}

[ 1 ]
(ii)

100 cm3100 \mathrm{~cm}^{3} of the octan-1-ol layer is taken and shaken with 100 cm3100 \mathrm{~cm}^{3} of water.

Calculate the maximum amount, in mol, of ethoxyethane that can be extracted into the water.
mol

[ 3 ]
(a)

The partition coefficient, KpcK_{\mathrm{pc}}, of a substance, Q, between hexane and water is 7.84 at 298 K . Q is more soluble in hexane than it is in water.

[ 3 ]
(i)

Define partition coefficient, KpcK_{\mathrm{pc}}.

[ 1 ]
(ii)

5.00 g of Q is shaken with a mixture of 100.0 cm3100.0 \mathrm{~cm}^{3} of water and 100.0 cm3100.0 \mathrm{~cm}^{3} of hexane at 298 K and left until there is no further change in concentrations.
Calculate the mass of Q dissolved in the water.
mass of Q =

(iii)

A sample of Q is shaken with a different mixture of water and hexane and left until there is no further change in concentrations.

It is found that the mass of Q dissolved in each solvent is the same.
Use the KpcK_{p c} value to suggest possible values for the volume of water used and the volume of hexane used.
volume of water = cm3\mathrm{cm}^{3}
volume of hexane = cm3\mathrm{cm}^{3}

[ 1 ]
(iv)

Q is more soluble in hexane than it is in water.

It is suggested that Q is one of KCl,CH3(CH2)4OH\mathrm{KCl}, \mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{4} \mathrm{OH} or HCOOH .
Identify Q. Explain your answer.

[ 1 ]
(a)

Water and octan-1-ol form two layers when mixed.

Ethanamide is more soluble in water than it is in octan-1-ol. When 1.00 g of ethanamide is added to 50.0 cm350.0 \mathrm{~cm}^{3} of water and this is then shaken with 50.0 cm350.0 \mathrm{~cm}^{3} of octan-1-ol, it is found that the water layer contains 0.935 g of ethanamide at equilibrium.

[ 3 ]
(i)

Calculate the partition coefficient, KpcK_{\mathrm{pc}}, for ethanamide in water and octan-1-ol.

Kpc=K_{p c}=
[ 1 ]
(ii)

The 50.0 cm350.0 \mathrm{~cm}^{3} of water containing 0.935 g of ethanamide is then shaken with 100.0 cm3100.0 \mathrm{~cm}^{3} of pure octan-1-ol under the same conditions.

Calculate the mass of ethanamide that is dissolved in the 100.0 cm3100.0 \mathrm{~cm}^{3} of octan-1-ol at equilibrium.
mass of ethanamide = g

[ 2 ]
(a)

A sample of butanoic acid, CH3(CH2)2COOH\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{2} \mathrm{COOH}, is shaken with a mixture of two immiscible solvents, ethoxyethane and water. The solvents form two layers. The butanoic acid is distributed between the two layers, its concentration in ethoxyethane being higher than its concentration in water.

[ 3 ]
(i)

State what is meant by partition coefficient.

[ 1 ]
(ii)

The partition coefficient, KpcK_{\mathrm{pc}}, for butanoic acid between ethoxyethane and water is 3.50 .

A solution of 2.00 g of butanoic acid in 100 cm3100 \mathrm{~cm}^{3} ethoxyethane is added to water. This mixture is left until there is no further change in the concentration of butanoic acid in either solvent. The mass of butanoic acid dissolved in the ethoxyethane layer is now 1.62 g .

Calculate the volume of water used.
volume of water used = cm3\mathrm{cm}^{3}

[ 2 ]
(a)
(i)

State what is meant by the term partition coefficient.

Ammonia is soluble in both water and organic solvents.
An aqueous solution of ammonia is shaken with the immiscible organic solvent trichloromethane. The mixture is left to reach equilibrium.

Samples are taken from each layer and titrated with dilute hydrochloric acid.
- A 25.0 cm325.0 \mathrm{~cm}^{3} sample from the trichloromethane layer requires 13.0 cm313.0 \mathrm{~cm}^{3} of 0.100moldm30.100 \mathrm{moldm}^{-3} HCl to reach the end-point.
- A 10.0 cm310.0 \mathrm{~cm}^{3} sample from the aqueous layer requires 12.5 cm312.5 \mathrm{~cm}^{3} of 0.100 moldm3HCl0.100 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{HCl} to reach the end-point.

[ 1 ]
(ii)

Calculate the partition coefficient, Kpartition K_{\text {partition }}, of ammonia between trichloromethane and water.

Kpartition =K_{\text {partition }}=
[ 2 ]
(iii)

Butylamine, C4H9NH2\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{NH}_{2}, is also soluble in both water and organic solvents.

Suggest how the value of Kpartition K_{\text {partition }} of butylamine between trichloromethane and water would compare to the value of Kpartition K_{\text {partition }} calculated in (ii). Explain your answer.

[ 2 ]
[Maximum number: 2]

Nitrobenzene, C6H5NO2\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NO}_{2}, can be reduced to phenylamine, C6H5NH2\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}, in acid solution in a two step process.

(a)

Following the reaction in (b), an excess of NaOH(aq) was added to liberate phenylamine from phenylammonium chloride.

[ 2 ]
(i)

Use the data to calculate the partition coefficient, Kpartition K_{\text {partition }}, of phenylamine between dichloromethane and water.

[ 2 ]
(a)

Define the term partition coefficient, KpcK_{\mathrm{pc}}.

[ 2 ]
(b)

KpcK_{\mathrm{pc}} of benzoic acid between octan-1-ol and water is 79.4.

[ 1 ]
(i)

A solution of 0.400 g of benzoic acid in 25.0 cm325.0 \mathrm{~cm}^{3} octan-1-ol is shaken with 125 cm3125 \mathrm{~cm}^{3} of water. Calculate the mass of benzoic acid extracted into the water layer.
mass of benzoic acid extracted =

(ii)

Kpc\mathrm{K}_{\mathrm{pc}} of benzophenone, C6H5COC6H5\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COC}_{6} \mathrm{H}_{5}, between octan-1-ol and water is different from the value of KpcK_{\mathrm{pc}} of benzoic acid given in (b)(i).

Explain why.

[ 1 ]
(a)
(i)

State what is meant by partition coefficient, KpcK_{\mathrm{pc}}.

[ 1 ]
(ii)

The partition coefficient, KpcK_{p c}, for a compound, X, between carbon disulfide, CS2\mathrm{CS}_{2}, and water is 10.5 .
1.85 g of X is dissolved in water and made up to 100.0 cm3100.0 \mathrm{~cm}^{3} in a volumetric flask. 40.0 cm340.0 \mathrm{~cm}^{3} of this aqueous solution is shaken with 25.0 cm325.0 \mathrm{~cm}^{3} of CS2\mathrm{CS}_{2}.
The mixture is left to reach equilibrium.
Calculate the mass of X, in g , extracted into the CS2\mathrm{CS}_{2} layer.

mass of X =
[ 3 ]
0