D4.1.14 (HL)—Hardy-Weinberg conditions

Hardy-Weinberg equilibrium requires no selection, mutation, migration, genetic drift or non-random mating in a large population in evolving populations in evolving populations.

Syllabus
First assessment 2025
Objective
D4.1.14
Level
HL

Exam analysis

Chance of appearing6%of analysed past papers
Latest appearanceMay 2025
Most common paperPaper3
Typical marks1–2

Common command terms

  • State
  • Identify

Recent exam appearances

May 2025Paper1A ["HL"] · TZ339[ 1 ]D4.1.14 (HL)—Hardy-Weinberg conditions
May 2015Paper3 ["HL"] · TZ12(c)(i)[ 2 ]D4.1.14 (HL)—Hardy-Weinberg conditions
May 2014Paper3 ["HL"] · TZ12(b)(ii)[ 1 ]D4.1.14 (HL)—Hardy-Weinberg conditions
November 2013Paper3 ["HL"] · TZ02(d)[ 1 ]D4.1.14 (HL)—Hardy-Weinberg conditions
May 2013Paper3 ["HL"] · TZ1D2(a)[ 2 ]D4.1.14 (HL)—Hardy-Weinberg conditions
Practice this objective

Coverage 2012–2025 · Updated 16 Jul 2026

Hardy–Weinberg Needs Restrictive Conditions

HL only

Hardy–Weinberg equilibrium assumes a large population, random mating, no migration, no mutation and no selection.

These conditions prevent systematic changes in allele frequencies or sampling noise. Violating one condition can make observed genotype frequencies depart from expectation.

Check each assumption before using an equilibrium calculation as a biological conclusion.; separate variation, selection, inheritance and time

A small isolated population can deviate because drift acts strongly even if no selection is present. This gives a concrete prediction from the stated population.

A departure does not reveal which assumption failed; independent evidence is needed. Interpret the result within the stated selection model and evidence limits.

Hardy-Weinberg conditions

HL only

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using State / Identify.

Command terms

State / Identify

What earns marks

Build the answer around this relationship: Hardy-Weinberg equilibrium is a null model for no evolution.

Representative question

Question 1

[Maximum number: 2]

State two assumptions made when using the Hardy-Weinberg equation.
1.

Retrieve the HL Population Genetics Route

HL only

HL D4.1 turns selection into measurable population genetics. A gene pool changes when allele frequencies shift. Hardy-Weinberg gives a no-evolution baseline; selection graphs, isolated populations, artificial selection, and resistance show how forces move populations away from that baseline.

  • all alleles in an interbreeding population
  • directional, stabilizing, or disruptive selection favours different phenotype ranges
  • p and q calculate allele and genotype frequencies in equilibrium
  • selection, mutation, migration, drift, or non-random mating may be acting

HL Population Genetics

HL only

HL population-genetics questions ask students to quantify or model evolution. The answer starts with the gene pool and allele frequencies, then uses the model or selection graph to decide whether the population is at equilibrium or being shifted by selection, mutation, migration, drift, artificial selection, or isolation.

  • Use gene pool and allele frequency language to define evolution quantitatively.
  • Interpret selection graphs and isolated populations as changes in phenotype or allele frequencies.
  • Apply Hardy-Weinberg equations and equilibrium assumptions, then explain what deviations mean.

Concept essentials

  • Hardy-Weinberg equilibrium is a null model for no evolution.
  • Random mating and a large population help maintain expected genotype frequencies.
  • Selection, mutation, migration and drift can disrupt equilibrium.