IB Biology HL Unity and Diversity Concepts

Unity and Diversity connects water, molecules, cells, classification, evolution and biodiversity into evidence-based explanations of shared life patterns and biological variation.

Syllabus
First assessment 2025
Section
Level
HL

Exam analysis

Published Concept evidence in Unity and Diversity repeatedly links cell structures, nucleic acids, organism diversity and evolution. The strongest pattern is not isolated recall, but explaining how molecular and cellular evidence supports biological unity, variation and classification.

Most tested topics

Practice this section

Recent 5 years · Updated 22 Jul 2026

In this section

Topic A1.1

A1.1 Water

Water’s polarity and hydrogen bonding create solvent, thermal, cohesive and adhesive properties that support metabolism, transport, cooling and aquatic life.

18% of analysed papers 21 papers · 25 questions

Objectives in this topic

Water Provides a Medium for Life

Water is the medium in which most life processes occur. The first cells originated in water, and modern cells still carry out most reactions in aqueous cytoplasm.

Water keeps many ions and polar molecules dissolved, so reactants can diffuse, collide and be acted on by enzymes. It also transports dissolved substances within organisms.

When explaining water as a medium, link three ideas: dissolved substances, movement or mixing, and a biological process such as metabolism or transport.

In cytoplasm, dissolved glucose and enzymes can move and interact, allowing enzyme-catalysed reactions to occur.

A medium is the environment in which a process occurs. Water does not have to be a reactant in every reaction that takes place in it.

Water as the medium for life

Assessment in practice

8 marks
How it is assessed

This objective is assessed through structured response, commonly using Explain.

Command terms

Explain

What earns marks

In exam answers, connect each biological role to the relevant molecular property rather than listing uses of water without explaining why they are possible.

Watch for

Describing water only as a habitat without explaining its role as a cellular reaction medium.

Representative question

Question 1

[Maximum number: 8]

Explain the relationship between the properties of water and its uses in living organisms as a coolant, a medium for metabolic reactions and a transport medium.

Polarity Leads to Hydrogen Bonds Between Water Molecules

Each O-H bond in water is polar covalent because oxygen attracts the shared electrons more strongly than hydrogen. Oxygen is partially negative (delta-) and each hydrogen is partially positive (delta+).

Because a water molecule is V-shaped, its bond dipoles do not cancel. The delta+ hydrogen of one molecule is attracted to the delta- oxygen of another, forming an intermolecular hydrogen bond.

To represent two water molecules: draw solid O-H covalent bonds within each V-shaped molecule, label O as delta- and H as delta+, then draw a dotted line from H(delta+) on one molecule to O(delta-) on the other and label it hydrogen bond.

Many individually weak hydrogen bonds act together. This collective attraction helps explain cohesion and the relatively high energy needed to separate water molecules.

Do not draw a hydrogen bond between O and H within the same water molecule: that connection is a polar covalent bond.

Hydrogen bonds in water

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, multiple choice, commonly using Identify / Describe / Explain.

Command terms

Identify / Describe / Explain / Outline / Draw

What earns marks

Build the answer around this relationship: Unequal electron sharing makes each O–H bond polar.

Watch for

Drawing a hydrogen bond between atoms within the same water molecule.

Representative question

Question 1

[Maximum number: 3]

Outline how hydrogen bonds form in water.

Turn a water molecule until attraction appears

Cohesion Keeps Water Molecules Together

Cohesion is attraction between molecules of the same substance; in water it supports continuous columns and surface tension.

Hydrogen bonding resists separation. This allows water to transmit tension through xylem and lets the surface support small organisms.

Distinguish cohesion from adhesion before explaining a transport or surface effect.; separate property, mechanism and biological use

A continuous water column in a plant xylem vessel can be pulled upward as leaves lose water, because water molecules cohere. This gives a concrete prediction from the stated water condition.

Cohesion alone does not lift water without transpiration, adhesion and a continuous pathway. Interpret the result within the stated evidence and scale limits.

Cohesion of water molecules

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, multiple choice, commonly using Identify / Explain / Outline.

Command terms

Identify / Explain / Outline

What earns marks

Strong exam answers begin with polarity or hydrogen bonding, name cohesion, and then link it to a specific biological outcome such as xylem transport or surface tension.

Watch for

Defining cohesion as attraction between water and another surface.

Representative question

Question 1

[Maximum number: 4]

Outline how the cohesive properties of water benefit living organisms.

Adhesion of water

Assessment in practice

1 marks
How it is assessed

This objective is assessed through multiple choice, commonly using Identify.

Command terms

Identify

What earns marks

A complete answer identifies the different surface involved and links the attraction to capillary movement.

Watch for

Using adhesion and cohesion as interchangeable terms.

Representative question

Question 1

[Maximum number: 1]

Which of the following is a consequence of the adhesive properties of water?

A

Stable temperatures of aquatic environments

B

Water movement by capillary action in soil

C

Transport of dissolved nutrients in blood plasma

D

Cooling effect of sweating

Water Dissolves Polar and Ionic Solutes

Water dissolves many ionic and polar substances because its partial charges attract ions and polar regions of molecules.

Water molecules form hydration shells around ions and hydrogen bonds with many polar solutes. Dissolved particles remain mobile, so they can be transported in blood, xylem or phloem and can take part in enzyme-catalysed reactions in aqueous solution.

Hydrophilic substances interact with water and tend to dissolve. Hydrophobic substances are non-polar and tend to remain separate; this insolubility is important for structures such as lipid membranes.

When sodium chloride dissolves, the oxygen side of water faces Na+ and the hydrogen sides face Cl-, producing hydration shells that keep the ions dispersed.

Water is not a literally universal solvent. Many non-polar substances dissolve poorly, and solubility does not mean that a substance is harmless.

Solvent properties of water

Assessment in practice

1–3 marks
How it is assessed

This objective is assessed through structured response, multiple choice, commonly using Identify / Explain.

Command terms

Identify / Explain

What earns marks

Exam questions commonly ask students to connect solvent behaviour to polarity, identify a biological transport example, or distinguish solvent properties from cohesion and thermal properties.

Watch for

Calling water a universal solvent that dissolves all substances.

Representative question

Question 1

[Maximum number: 3]

Water has important solvent properties. Explain these properties using an example to illustrate your answer.

Water and Air Present Different Physical Challenges

Compared with air, water is denser and more viscous, conducts heat more rapidly, and has a higher specific heat capacity. Each difference has a distinct consequence for aquatic animals.

Property Water compared with air Consequence for aquatic animals
Density and buoyancy Denser; provides more buoyant support Bodies are supported, but animals must control floating and diving
Viscosity Higher Movement creates greater drag, favouring streamlined shapes
Thermal conductivity Higher Heat is transferred from a warm body more rapidly, increasing the need for insulation
Specific heat capacity Higher Aquatic temperatures change more slowly, giving a more stable thermal environment

A streamlined ringed seal experiences less drag in viscous water, while blubber reduces heat transfer to the water.

Thermal conductivity is the rate of heat transfer; specific heat capacity is the energy needed to change temperature. Do not use the terms interchangeably.

Match Aquatic Adaptations to Water Properties

An aquatic adaptation should be explained by naming the water property, the challenge it creates, and how the feature improves survival or movement.

Ringed seal feature Water-related challenge Functional consequence
Streamlined body Water has high viscosity compared with air Reduces drag during swimming
Thick blubber Water conducts heat away faster than air Reduces heat loss and also increases buoyancy
Flippers Propulsion and steering are needed in a dense medium Produce controlled movement through water

A complete explanation is: water has higher thermal conductivity than air, so a seal loses heat rapidly; its blubber slows this heat transfer.

Do not claim that blubber is mainly an adaptation to high specific heat capacity. The direct challenge is water's higher thermal conductivity.

Physical properties of water for aquatic

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Describe / Distinguish.

Command terms

Identify / Describe / Distinguish

What earns marks

Credit depends on matching the adaptation to the correct physical challenge.

Watch for

Confusing thermal conductivity with specific heat capacity.

Representative question

Question 1

[Maximum number: 2]

Distinguish between the physical properties of water and air.

The ringed seal (Pusa hispida) can be found in the Arctic and sub-Arctic regions of the Pacific, Atlantic and Arctic Oceans.

Water summary

  • Water is life's medium because substances can dissolve, move and react in it.
  • Unequal electron sharing and bent geometry make water polar; hydrogen bonds form between molecules.
  • Many hydrogen bonds produce cohesion, maintaining xylem columns and creating surface tension.
  • Adhesion is water-to-surface attraction and contributes to movement through narrow soil spaces and cellulose walls.
  • Polarity lets water hydrate ions and interact with polar solutes; dissolved particles can be transported and react, while non-polar substances are hydrophobic.
  • Compared with air, water provides more buoyancy and drag, transfers heat faster and changes temperature more slowly. Aquatic adaptations respond to these consequences.

Asteroids, Cooling and Gravity Explain Earth's Water

HL only

Within the IB syllabus, the extraplanetary hypothesis is that water-rich asteroids delivered water to Earth. Its long-term presence helped provide conditions in which life could evolve.

Two conditions explain retention: temperatures became low enough for water vapour to condense, and Earth's gravity was strong enough to retain water over geological time.

Use the chain: asteroid delivery -> cooling and condensation -> gravitational retention -> persistent water available during the evolution of life.

If surface and atmospheric temperatures allow water vapour to condense, water can collect as liquid instead of remaining only as vapour; gravity helps keep that water associated with Earth.

Treat asteroid delivery as a hypothesis, not a proven statement that asteroids supplied all water. For this objective, do not expand the origin explanation to comets or internal sources.

Extraplanetary origin of water on Earth

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through multiple choice, commonly using Identify.

Command terms

Identify

What earns marks

Gravity, atmospheric development and continued geological cycling also contributed to long-term retention, but the available tagged exam evidence for this objective directly supports the importance of a suitable temperature range for condensation.

Watch for

Treating asteroid delivery as the only accepted source of Earth’s water.

Representative question

Question 1

[Maximum number: 1]

It has been hypothesized that asteroids were the primary source of Earth's water. What has caused the retention of water on Earth?

A

The gases of the early atmosphere absorbed water vapour.

B

High atmospheric pressure prevented water vapour from escaping.

C

Temperatures on Earth allowed condensation of water.

D

Water was trapped in the pores of newly formed rocks.

Liquid Water and the Goldilocks Zone Guide Life Searches

HL only

The search for extraterrestrial life often prioritizes places where liquid water could exist because water supports the chemical interactions required by known life.

A star's Goldilocks zone is the range of distances where temperatures may allow liquid water at a planet's surface. A planet that is too close may be too hot; one too far away may be too cold.

When interpreting planetary data, first identify whether the planet lies in the Goldilocks zone, then state that this makes liquid water and habitability possible rather than certain.

If a table shows one planet at a distance compatible with surface liquid water, that planet is the best candidate for further investigation, not evidence that life is already present.

Being in the Goldilocks zone is not proof of liquid water or life; other planetary conditions also affect whether surface water can persist.

Search for extraterrestrial life and water

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through multiple choice, commonly using Identify / Interpret.

Command terms

Identify / Interpret

What earns marks

Exam questions may provide planetary data and ask students to identify the best candidate.

Watch for

Treating location in the habitable zone as proof that life exists.

Representative question

Question 1

[Maximum number: 1]

Which planet in the table falls within the "Goldilocks zone" and may be capable of sustaining extraterrestrial life?

Planet

Temperature /C/{ }^{\circ} \mathrm{C}

Atmosphere

Gravity / g

Kepler-22b

-11 to 16

unknown

2.4

WASP-39b

750

hydrogen, helium and
other elements

25.0

Gliese 876d

50 to 80

high levels of toxic gases

20.0

Kepler-16b

-100

unknown

0.9

HL water summary

HL only
  • Asteroid and isotope evidence supports extraplanetary water delivery; cooling enabled condensation and gravity enabled retention.
  • Goldilocks zones and atmospheric water signatures identify promising worlds, but neither is proof of extraterrestrial life.

Topic A1.2

A1.2 Nucleic acids

Explore how nucleotide components, bonding, base pairing and sequence give DNA and RNA their structures, information capacity, shared code and experimental significance.

40% of analysed papers 46 papers · 62 questions

Objectives in this topic

DNA Is the Genetic Material of Living Organisms

DNA is the genetic material of all living organisms: its base sequence stores information that can be copied and inherited.

DNA occurs in chromosomes and also as smaller genomes in mitochondria and chloroplasts. Copying DNA allows cells and offspring to receive genetic information.

Apply the rule to living organisms, then handle the exception carefully: some viruses use RNA as genetic material, but viruses are not classified as living organisms.

A plant cell contains DNA in its nuclear chromosomes, mitochondria and chloroplasts; all of these DNA molecules carry heritable information.

The existence of RNA viruses does not contradict the statement about all living organisms, because viruses are not regarded as living organisms in this syllabus.

DNA as genetic material

Assessment in practice

1 marks
How it is assessed

This objective is assessed through multiple choice, commonly using State.

Command terms

State

What earns marks

Build the answer around this relationship: DNA as genetic material should be described using precise molecular vocabulary.

Representative question

Question 1

[Maximum number: 1]

The Human Genome Project completed the sequencing of the human genome by the year 2003. Which could have been a source of the entire genome in humans?

A

The contents of a red blood cell

B

The nucleus and mitochondria of a skin cell

C

The nucleus and acrosome of a sperm cell

D

The nucleus and ribosomes of any somatic cell

Build a Nucleotide from Three Parts

A nucleotide contains three components: a phosphate group, a pentose sugar and a nitrogenous base.

The sugar is the central connector: the base and phosphate are both attached to it. DNA nucleotides contain deoxyribose; RNA nucleotides contain ribose.

For the IB diagram convention, draw the phosphate as a circle, the pentose sugar as a pentagon and the base as a rectangle, with both phosphate and base connected to the sugar.

A DNA nucleotide can be represented as phosphate-circle -> deoxyribose-pentagon -> adenine-rectangle.

A nitrogenous base alone is not a nucleotide; the sugar and phosphate are also required.

Components of a nucleotide

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Draw.

Command terms

Identify / Draw

What earns marks

Build the answer around this relationship: Components of a nucleotide should be described using precise molecular vocabulary.

Representative question

Question 1

[Maximum number: 3]

Draw a labelled diagram to show the structure of a DNA nucleotide.

Link Nucleotides through the Sugar–Phosphate Backbone

Nucleotides join when a phosphate links the sugar of one nucleotide to the sugar of the next, forming a repeating backbone.

The covalent sugar–phosphate links make the strand continuous and give it a direction. Bases project from the backbone, so their order can vary without breaking the structural chain.

When reading a strand, separate:

  • the stable sugar–phosphate backbone
  • the variable base sequence
  • the direction from one end to the other

Joining many nucleotides produces a strand with an alternating sugar–phosphate backbone and a base attached to each sugar.

The bases do not form the backbone; confusing the code with the support structure reverses the roles.

Sugar-phosphate bonding

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Outline.

Command terms

Identify / Outline

What earns marks

Build the answer around this relationship: Sugar-phosphate bonding should be described using precise molecular vocabulary.

Watch for

Mixing up covalent sugar-phosphate bonds with hydrogen bonds between complementary bases.

Representative question

Question 1

[Maximum number: 2]

Outline the bonding between DNA nucleotides.

Base sequences and RNA roles

Base sequence to codon to amino acid pathway.

The genetic code is stored in the order of nitrogenous bases, not in the repeating sugar–phosphate backbone. DNA uses A, T, G and C; RNA uses A, U, G and C. Groups of three bases form codons, and the order of codons carries the instructions for the amino-acid sequence of a polypeptide.

RNA is a single-stranded polynucleotide formed by condensation of nucleotide monomers. Its main types have different roles in protein synthesis:

  • mRNA carries a transcript of the DNA instructions to the ribosome.
  • tRNA carries amino acids to the mRNA sequence.
  • rRNA forms part of the ribosome and provides catalytic activity for joining amino acids.

Answer chain: base sequence → genetic instructions; condensation → RNA polymer; mRNA, tRNA and rRNA → different steps in gene expression.

RNA as a polymer

Assessment in practice

4 marks
How it is assessed

This objective is assessed through structured response, commonly using Draw.

Command terms

Draw

What earns marks

Build the answer around this relationship: RNA as a polymer should be described using precise molecular vocabulary.

Representative question

Question 1

[Maximum number: 4]

Draw labelled diagrams to show the structure of RNA nucleotides and how they are linked together to form a molecule of RNA.

The DNA Double Helix Stores Two Matching Copies

DNA consists of two antiparallel polynucleotide strands whose complementary bases pair inside a double helix.

Hydrogen bonding between paired bases holds the strands together, while the sugar–phosphate backbones face outward. Because each base has a partner, either strand can guide construction of the other during copying. This arrangement combines stability with a built-in template.

The helix depends on three linked features:

  • complementary base pairing
  • antiparallel strand direction
  • an external sugar–phosphate backbone

If one strand reads A–G–C, the opposite strand reads T–C–G at the matching positions.

The two strands are not identical copies in sequence; they are complementary and run in opposite directions.

DNA as a double helix

Assessment in practice

1–3 marks
How it is assessed

This objective is assessed through structured response, commonly using Describe / Explain / Deduce.

Command terms

Describe / Explain / Deduce / Draw / Sketch

What earns marks

Build the answer around this relationship: DNA as a double helix should be described using precise molecular vocabulary.

Watch for

Mixing up covalent sugar-phosphate bonds with hydrogen bonds between complementary bases.

Representative question

Question 1

[Maximum number: 6]

Draw a simple labeled diagram to show the structure of a double stranded DNA molecule, comprising four nucleotides.

DNA and RNA Differ in Three Useful Ways

DNA and RNA differ in sugar, one base and usual strand structure, and those differences fit their different cellular roles.

DNA uses deoxyribose and thymine and is usually double-stranded, making a stable long-term store. RNA uses ribose and uracil and is usually single-stranded, making temporary messages and folded functional molecules practical.

Compare the molecules:

  • sugar: deoxyribose / ribose
  • base: thymine / uracil
  • usual form: double-stranded / single-stranded

A cell can transcribe a DNA sequence into RNA: the RNA copy uses uracil and can leave the nucleus while the DNA template remains protected.

‘RNA is always single-stranded’ is a usual structural description, not a rule that forbids every paired region.

Differences between DNA and RNA

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / State / Distinguish.

Command terms

Identify / State / Distinguish / Determine

What earns marks

Build the answer around this relationship: Differences between DNA and RNA should be described using precise molecular vocabulary.

Watch for

Listing a DNA feature as an RNA feature, especially thymine, uracil, ribose, or deoxyribose.

Representative question

Question 1

[Maximum number: 3]

Distinguish between the structures of DNA and RNA.

Complementary Pairing Makes Copying Predictable

Complementary base pairing means each base has a specific partner, allowing a strand to determine the sequence of its partner.

Hydrogen bonds give the pairs selectivity: adenine pairs with thymine in DNA (uracil in RNA), while cytosine pairs with guanine. This matching is the mechanism behind faithful copying and template reading.

Apply the pairing rule in order:

  • A ↔ T (or U in RNA)
  • C ↔ G
  • preserve the strand positions while switching to the partner base

The DNA sequence A–C–G–T has the complementary sequence T–G–C–A.

Complementary does not mean identical: the partner strand has different letters in the opposite direction.

Complementary base pairing

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Deduce.

Command terms

Identify / Deduce

What earns marks

Build the answer around this relationship: Complementary base pairing should be described using precise molecular vocabulary.

Watch for

Mixing up covalent sugar-phosphate bonds with hydrogen bonds between complementary bases.

Representative question

Question 1

[Maximum number: 1]

Deduce the base indicated by X on the diagram.

DNA sequence diversity and genetic code

Sequence diversity and codon conservation.

DNA can vary in both length and base sequence. If a sequence has n positions and each position can contain one of four bases, there are 4ⁿ possible sequences. Even relatively short sequences can therefore store a very large number of different instructions.

Genome size and gene number vary widely between organisms, but neither is a simple measure of organismal complexity. The key idea is that variation in sequence length and order gives DNA an enormous capacity for information storage.

The genetic code is highly conserved across life: the 64 codons have nearly the same meanings in different organisms. Shared codon meanings, together with conserved genes involved in transcription, translation and ribosomes, support the inference that living organisms share a common ancestor.

“Nearly” matters because there are minor exceptions. A synonymous mutation can change a base or codon without changing the amino acid specified, so a change in DNA sequence does not always change the polypeptide sequence.

Diversity of DNA base sequences

Assessment in practice

1–4 marks
How it is assessed

This objective is assessed through structured response, commonly using Explain.

Command terms

Explain

What earns marks

Build the answer around this relationship: Diversity of DNA base sequences should be described using precise molecular vocabulary.

Representative question

Question 1

[Maximum number: 4]

Explain the diversity of possible base sequences in nucleic acids.

Conservation of genetic code

Assessment in practice

1 marks
How it is assessed

This objective is assessed through multiple choice, commonly using Explain.

Command terms

Explain

What earns marks

Exam questions often connect this idea to biotechnology or evolution.

Representative question

Question 1

[Maximum number: 1]

Some yeast genes can be replaced by human genes that then continue to produce the same human proteins in the yeast cells. Which statement helps to explain this evidence?

A

The DNA of yeast and humans is identical.

B

Yeast and humans have the same number of chromosomes.

C

The genetic code is universal.

D

Yeast and humans are both eukaryotes.

Retrieve The Core Rules

The core chain is: nucleotides have three parts; condensation builds the sugar-phosphate backbone; base order stores information; complementary pairing lets DNA copy and express that information.

  • Nucleotide parts: phosphate, pentose sugar, nitrogenous base.
  • Polymer rule: condensation forms a sugar-phosphate backbone.
  • Code rule: base order stores information and triplet codons specify amino acids.
  • Pairing rule: A-T or A-U, and C-G, enables replication and gene expression.
  • DNA/RNA contrast: DNA uses deoxyribose/T and is usually double-stranded; RNA uses ribose/U and is usually single-stranded.

Read Nucleic-Acid Direction from 5′ to 3′

HL only

Nucleic-acid strands have direction because the sugar-phosphate backbone links the 5' carbon of one nucleotide toward the 3' carbon of the next.

During replication and transcription, a new nucleic-acid strand is synthesized 5' to 3' while its template is read 3' to 5'. During translation, the ribosome reads mRNA codons in the 5' to 3' direction.

For any strand, label both ends, keep complementary DNA strands antiparallel, and write the direction before applying base pairing.

A DNA template written 3'-A-G-C-5' directs a new strand written 5'-T-C-G-3'.

Reversing only the 5' and 3' labels changes the sequence interpretation; direction is part of the strand's identity.

Directionality of RNA and DNA

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / State.

Command terms

Identify / State

What earns marks

Build the answer around this relationship: Directionality of RNA and DNA should be described using precise molecular vocabulary.

Representative question

Question 1

[Maximum number: 1]

Identify the terminal indicated by Y on the diagram.

Purines Pair with Pyrimidines to Fit the Helix

HL only

In DNA, each base pair combines one two-ring purine with one one-ring pyrimidine, so A-T and C-G pairs have equal length and the helix keeps a consistent width.

Adenine and guanine are purines; cytosine and thymine are pyrimidines. Complementary hydrogen bonding selects A-T and C-G and helps stabilize the two strands.

Classify first, then pair: A or G (purine) must face T or C (pyrimidine); the complementary pairs are A-T and C-G.

Replacing an A-T pair with a C-G pair changes the sequence but not the helix width, because both pairs contain one purine and one pyrimidine.

A purine-purine pair would be too wide and a pyrimidine-pyrimidine pair too narrow; equal pair length does not mean any purine can form the correct hydrogen bonds with any pyrimidine.

Nucleosomes Package DNA around Histones

HL only

A nucleosome consists of DNA wrapped around a core of eight histone proteins, called a histone octamer.

Linker DNA connects neighbouring nucleosomes. An additional histone, H1, attaches to linker DNA and helps hold the packaged structure together.

Identify four parts in a model: wrapped DNA, the eight-protein histone core, linker DNA, and the additional H1 histone.

Repeated nucleosomes give chromatin a beads-on-a-string appearance: each bead is DNA around a histone octamer and each connecting segment is linker DNA.

H1 is additional to the eight core histones; do not count it as one of the histone octamer.

Structure of a nucleosome

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / State / Outline.

Command terms

Identify / State / Outline / Describe

What earns marks

Build the answer around this relationship: Structure of a nucleosome should be described using precise molecular vocabulary.

Watch for

Treating a nucleosome as DNA alone instead of a DNA-protein packaging structure.

Representative question

Question 1

[Maximum number: 4]

Outline the structure and functions of nucleosomes.

Hershey–Chase and Chargaff evidence

HL only
Experiment-result comparison.

Hershey–Chase experiment (1952)

T2 bacteriophages were prepared with either ³²P-labelled DNA or ³⁵S-labelled protein. After infection of E. coli, the ³²P signal was associated with the bacterial pellet and was found in progeny phages, whereas the ³⁵S protein label remained outside the bacteria.

Observation → conclusion: DNA entered the bacterial cells and was passed to new viruses; protein did not. Therefore DNA, rather than protein, is the genetic material in this system.

Chargaff’s data

Across DNA samples, the amount of purines equalled the amount of pyrimidines, with A = T and G = C. These results supported complementary base pairing and falsified the tetranucleotide hypothesis of a repeating, fixed base pattern.

Evidence rule: state the result first, then explain what it allows us to conclude; do not present the isotope labels as the conclusion itself.

Hershey-Chase experiment

HL only

Assessment in practice

1–3 marks
How it is assessed

This objective is assessed through structured response, commonly using Outline / Describe / Explain.

Command terms

Outline / Describe / Explain

What earns marks

Build the answer around this relationship: Hershey-Chase experiment should be described using precise molecular vocabulary.

Watch for

Remembering the experiment name without explaining what each radioactive label tracked.

Representative question

Question 1

[Maximum number: 3]

Explain how this data provides evidence that DNA is the genetic material of cells.

Chargaff's data

HL only

Assessment in practice

2 marks
How it is assessed

This objective is assessed through structured response, commonly using Explain.

Command terms

Explain

What earns marks

Build the answer around this relationship: Chargaff's data should be described using precise molecular vocabulary.

Representative question

Question 1

[Maximum number: 2]

Explain the reasons for expecting a thymine percentage of 32.4 %.

Retrieve The HL Extensions

HL only

HL adds directionality, helix geometry, DNA packaging, and classic evidence. These ideas stay separate: 5′/3′ explains strand direction; purine-pyrimidine pairing explains width; nucleosomes explain packaging; Hershey-Chase and Chargaff explain evidence for DNA and base pairing.

  • Directionality: phosphodiester bonds create 5′ and 3′ ends, and DNA strands are antiparallel.
  • Helix stability: purine-pyrimidine pairing keeps width constant and hydrogen bonds stabilize base pairs.
  • Packaging: DNA wraps around histone octamers and H1 binds linker DNA.
  • Evidence: Hershey-Chase supports DNA as genetic material; Chargaff supports complementary pairing.
  • Chargaff found purines equal pyrimidines across DNA samples.

Topic A2.1

A2.1 Origins of cells

The origin of cells links prebiotic environments, abiotic organic synthesis, membrane compartments, self-replicating RNA, radiometric evidence, and the shared ancestry of modern cellular life.

7% of analysed papers 8 papers · 10 questions

Objectives in this topic

Early Earth Set the Chemical Starting Conditions

HL only

Early Earth had little free oxygen and therefore little ozone, but higher concentrations of carbon dioxide and methane. Warmer conditions and stronger ultraviolet penetration created a chemical setting unlike today's.

Without an ozone shield, more ultraviolet radiation reached the surface and supplied energy for reactions. Under these anoxic conditions, carbon compounds may have formed spontaneously by chemical pathways that are uncommon today.

Build the explanation as conditions -> consequence: little O2 -> little ozone -> more UV; more CO2 and methane -> higher temperatures; energy plus simple chemicals -> possible prebiotic carbon compounds.

An anoxic mixture containing carbon-bearing gases and water can be exposed to an energy source in a controlled experiment to test whether carbon compounds form.

Reconstructing plausible conditions tests chemical feasibility; it does not prove that early life followed the exact laboratory route.

Conditions on early Earth

Assessment in practice

1–3 marks
How it is assessed

This objective is assessed through data analysis, commonly using State / Evaluate / Outline.

Command terms

State / Evaluate / Outline

What earns marks

Build the answer around this relationship: Early Earth had little free oxygen and no protective ozone layer.

Watch for

Treating one proposed environment as the proven location where life began.

Representative question

Question 1

[Maximum number: 3]

This investigation was performed in a chamber at 85C85^{\circ} \mathrm{C} leading to total evaporation of the salt water within one day. The atmosphere inside the chamber consisted of nitrogen, carbon dioxide and water vapour. Evaluate the experiment on the basis of similarity with conditions that existed on the prebiotic Earth.

A Cell Is the Smallest Self-Sustaining Unit

HL only

A cell is the smallest unit that can maintain a boundary, exchange matter and energy, and reproduce its information.

Life processes require coordinated chemistry. A membrane keeps useful gradients, internal reactions transform resources, and genetic information guides maintenance and reproduction; isolated molecules cannot perform the full integrated set.

Look for the minimum package:

  • boundary and internal chemistry
  • energy and matter exchange
  • information and reproduction

A bacterium can take in nutrients, use a proton gradient to make ATP, copy its DNA and divide; a purified enzyme cannot do all of these tasks alone.

A virus may contain genetic material and reproduce only inside a host, so “contains DNA” alone does not make it a fully independent cell.

Cells as smallest units of life

Assessment in practice

1 marks
How it is assessed

This objective is assessed through multiple choice, commonly using Identify.

Command terms

Identify

What earns marks

Build the answer around this relationship: A cell integrates the processes needed to maintain a living system.

Representative question

Question 1

[Maximum number: 1]

Which of the following characteristics found in a structure necessarily indicates that it is alive?

A

The presence of genetic material

B

The presence of a lipid bilayer

C

Metabolism

D

Movement

Abiogenesis Requires Several Linked Transitions

HL only

Spontaneous origin of cells is a sequence of chemical transitions from non-living compounds to bounded, self-maintaining systems.

A useful model separates formation of organic compounds, assembly into polymers or catalysts, enclosure in compartments, and inheritance with variation. Each step solves a different problem; no single experiment establishes the complete chain.

Keep stages distinct:

  • organic building blocks
  • larger functional molecules
  • membrane-like compartments
  • replication and selection

A vesicle that traps a catalytic molecule can persist longer than an empty vesicle, linking compartment formation to later selection.

“Spontaneous” means natural chemistry without a designed cell; it does not mean a complete cell appears instantly.

Spontaneous origin of cells

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using State / Describe.

Command terms

State / Describe

What earns marks

Build the answer around this relationship: Organic monomers had to form through non-living chemical processes.

Watch for

Replacing one of the required processes with a description of the early atmosphere.

Representative question

Question 1

[Maximum number: 3]

Describe processes needed for spontaneous origin of life on Earth.

Miller–Urey Evidence Is Specific, Not Complete

HL only

Miller and Urey tested whether carbon compounds could form abiotically under a model of early-Earth conditions.

Water was heated to make vapour, mixed with gases such as methane, ammonia and hydrogen, exposed to electrical sparks, then cooled so products accumulated. Amino acids and other organic compounds formed.

Strength: the controlled, repeatable result showed that biological monomers can form without living cells. Limitations: the chosen atmosphere is uncertain, the apparatus simplified Earth, and the experiment did not produce cells, heredity or metabolism.

Finding amino acids in the collection trap supports abiotic synthesis of building blocks; it does not demonstrate spontaneous formation of a protein or cell.

Organic means carbon-containing, not living. Evaluate the evidence for the specific claim it tests rather than treating it as a complete origin-of-life experiment.

Evidence for origin of carbon compounds

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through multiple choice, structured response, commonly using Discuss / State.

Command terms

Discuss / State

What earns marks

Build the answer around this relationship: Organic molecules can form abiotically under suitable chemical and energetic conditions.

Watch for

Claiming that the Miller-Urey experiment produced living cells or proved spontaneous generation.

Representative question

Question 1

[Maximum number: 1]

The Miller-Urey experiment carried out in 1952 tested the hypothesis of the chemical origin of life. What were the key findings?

A

Living cells could be produced from a mixture of chemicals.

B

Complex organic molecules could form under simulated primordial conditions.

C

Life could spontaneously emerge without external influence.

D

DNA and RNA could self-replicate in a prebiotic environment.

Vesicles Create a Useful Compartment

HL only

Vesicles can form spontaneously when amphipathic molecules arrange into a closed membrane-like boundary in water.

Hydrophilic parts face the water while hydrophobic parts cluster away from it, producing a bilayer or related compartment. A boundary can concentrate reactants and preserve gradients, making chemistry more effective and reducing dilution.

For a compartment to help, it needs:

  • a stable boundary
  • selective exchange
  • trapped contents or gradients

A fatty-acid vesicle can enclose a catalyst and keep its reactants nearby, increasing the chance of repeated reactions.

A vesicle is not automatically a living cell; it still needs sustained chemistry, information and reproduction.

Spontaneous formation of vesicles

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, multiple choice, commonly using State / Identify.

Command terms

State / Identify

What earns marks

Build the answer around this relationship: Amphipathic molecules can self-assemble in water.

Watch for

Treating protobionts as complete modern cells with nuclei and organelles.

Representative question

Question 1

[Maximum number: 1]

State the name for primitive, phospholipid-enclosed structures that may have preceded cells.

RNA Is a Plausible Early Information Molecule

HL only

RNA is a plausible first genetic material because its nucleotide sequence can store information and some folded RNA molecules can catalyse reactions.

RNA can be copied, allowing heredity and variation, while catalytic RNAs called ribozymes can accelerate reactions. RNA could therefore have performed roles now divided between DNA and protein enzymes.

Use two independent properties in the argument: replication/information storage and catalytic activity. Both are needed to explain why RNA is a stronger candidate than a molecule that performs only one job.

Ribosomal RNA still catalyses peptide-bond formation in the ribosome, providing a modern example of RNA acting catalytically.

The RNA-world model is a supported hypothesis, not a direct observation of the first genetic system; it must also explain how RNA formed and persisted prebiotically.

RNA as presumed first genetic material

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using Outline / State / Explain.

Command terms

Outline / State / Explain / Identify / Describe

What earns marks

Build the answer around this relationship: RNA nucleotide sequences can store hereditary information.

Watch for

Giving only RNA's informational role and omitting its catalytic activity.

Representative question

Question 1

[Maximum number: 5]

Describe the structure of RNA and the evidence that it was the first genetic material used to store information.

LUCA Is Inferred from Shared Molecular Features

HL only

LUCA is the inferred last population ancestral to all living organisms, supported by the universal genetic code and genes shared across the major lineages of life.

The same codon meanings and deeply conserved systems for information processing are best explained by inheritance from common ancestors. Other early life forms may also have evolved but later became extinct through competition with LUCA and its descendants.

Separate three claims: shared molecular features support common ancestry; LUCA is the last universal common ancestor, not the first life; competing early lineages need not have surviving descendants.

A translation-related gene found in bacteria, archaea and eukaryotes is stronger LUCA evidence than a gene restricted to one modern group.

LUCA describes an inferred ancestral population, not one preserved individual, and it need not have possessed every feature of modern cells.

Date Early Life with Multiple Evidence Types

HL only

Dates for the first cells and LUCA are estimates built by combining fossils, isotope signatures, molecular clocks and geological context.

Each method has assumptions: fossils require interpretable structures, isotope signals can have non-biological sources, and molecular clocks depend on mutation rates and calibration. Agreement across methods increases confidence.

Ask what a method actually dates:

  • a preserved structure or chemical signature
  • a divergence estimate
  • the age of the surrounding rock

A microfossil in a securely dated rock can constrain an early-cell minimum age, while a molecular clock estimates when lineages diverged rather than when the first cell existed.

The oldest evidence found is a minimum bound; absence of older evidence does not prove life was absent.

Dating first cells and LUCA

Assessment in practice

2 marks
How it is assessed

This objective is assessed through structured response, commonly using Outline / State / Describe.

Command terms

Outline / State / Describe

What earns marks

Build the answer around this relationship: Radioactive isotopes decay at predictable rates expressed by half-life.

Watch for

Using carbon-14 to date rocks or fossils billions of years old.

Representative question

Question 1

[Maximum number: 2]

Outline the use of two named radioisotopes for dating fossils.

Two Evidence Lines Place LUCA Near Hydrothermal Vents

HL only

The hydrothermal-vent hypothesis for LUCA is supported by two different evidence lines: fossilized signs of early life in ancient seafloor vent precipitates and conserved gene sequences used to reconstruct ancestral biology.

Geological evidence shows that very early organisms lived in vent environments. Genomic comparisons identify shared sequences whose inferred functions are compatible with anaerobic, chemically powered life near hydrogen-rich, hot vent systems.

Keep the inference chain explicit: ancient vent precipitate -> evidence of early life at vents; conserved sequences -> inferred ancestral traits; agreement -> stronger, but still indirect, support for LUCA near vents.

Tube-like microstructures in ancient vent minerals can support early life at vents, while conserved metabolism-related genes independently suggest an ancestor adapted to vent chemistry.

A fossil from a vent does not identify LUCA by itself, and genomic reconstruction is not a direct fossil. The conclusion depends on combining independent evidence.

Evolution near hydrothermal vents

Assessment in practice

2 marks
How it is assessed

This objective is assessed through structured response, commonly using Outline.

Command terms

Outline

What earns marks

Build the answer around this relationship: Hydrothermal circulation supplies heat and reactive inorganic chemicals.

Representative question

Question 1

[Maximum number: 2]

Outline how organic compounds may have been synthesized deep in the oceans.

Pull The Whole Origin Argument Together

A2.1 is usually tested as a connected argument, not as isolated facts. A strong answer builds a chain: early Earth conditions made abiotic organic synthesis plausible; origin models require small molecules, polymers, self-replication, and membranes; experiments and models support parts of the chain; LUCA, dating, and vents provide later evidence and constraints. The highest-scoring habit is to say “supports” when evidence supports, and avoid saying “proves” when it does not.

  • Conditions explain why prebiotic chemistry was possible.
  • Required transitions explain what a first cell-like system needed.
  • Miller-Urey, vesicles, and RNA world support specific steps.
  • LUCA, dating methods, and vents help evaluate when and where early cellular life may have existed.
  • Use careful evidence language: supports, suggests, plausible, not proves.

Topic A2.2

A2.2 Cell structure

Cell structure connects microscopy, universal cellular organization, prokaryotic and eukaryotic diversity, specialized exceptions, differentiation, and evolutionary explanations for complex cells and multicellularity.

41% of analysed papers 46 papers · 66 questions

Objectives in this topic

Cell Theory Connects Structure with Life

Cell theory states that living organisms are made of cells, the cell is the basic unit of life, and new cells arise from existing cells.

The theory links observations at different scales: tissues are organized from cells, and cell processes explain organismal functions. Modern evidence adds that cells share chemical continuity and pass genetic information during division.

Use the three core claims:

  • all organisms contain one or more cells
  • cells are the smallest functional units
  • cells come from pre-existing cells

A multicellular muscle works because each cell maintains membranes and ATP production; the tissue is not a separate unit replacing the cells.

Cell theory does not say cells are identical or that non-living particles are cells.

Cells as basic structural unit

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Outline.

Command terms

Identify / Outline

What earns marks

Build the answer around this relationship: All living organisms are composed of one or more cells.

Watch for

Treating a feature such as a cell wall or nucleus as a requirement of every cell.

Representative question

Question 1

[Maximum number: 2]

Outline the cell theory.

Prepare, Measure and Calculate with a Light Microscope

Microscopy skill combines specimen preparation, controlled focusing, calibrated measurement and a calculation that reports actual size.

Prepare a thin temporary mount, add a suitable stain if contrast is needed, place a coverslip, begin with low power and coarse focus, then use fine focus at higher power. Calibrate an eyepiece graticule against a stage micrometer at the selected objective.

magnification=imagesize/actualsize;actualsize=imagesize/magnificationmagnification = image size / actual size; actual size = image size / magnification

If a cell image is 40 mm long at 400x magnification, actual size = 40 mm / 400 = 0.10 mm = 100 micrometres. A scale bar must use the same calibrated relationship.

Convert image and actual size to the same units before calculating. Changing objective magnification requires recalibrating the eyepiece graticule.

Microscopy skills

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Determine / Calculate.

Command terms

Identify / Determine / Calculate / Outline / Deduce / State

What earns marks

Build the answer around this relationship: Magnification is image size divided by actual size when both use the same unit.

Watch for

Inverting the magnification relationship between image size and actual size.

Representative question

Question 1

[Maximum number: 3]

Outline the procedure for focusing a light microscope.

Match Each Microscopy Advance to Its Evidence

Microscopy advances improve resolution, preserve different structures or attach molecular identity; the best method depends on the evidence required.

Method Main advantage Typical evidence
TEM High-resolution electrons pass through a thin section Internal ultrastructure
SEM Electrons scan a surface Three-dimensional surface detail
Freeze fracture Frozen membranes split along the bilayer Membrane faces and embedded proteins
Cryogenic EM Rapid freezing preserves near-native structure High-resolution molecular or cellular structure without conventional staining
Fluorescent stain Fluorophore marks a selected structure Location of labelled material in a light microscope
Immunofluorescence Labelled antibodies bind a target antigen Location of a specific protein

A fluorescent antibody can locate one membrane protein, whereas freeze fracture can reveal particles embedded in the membrane face without identifying their molecular name.

Electron micrographs and fluorescence images may use false colour. Colour is not automatically part of the specimen.

Developments in microscopy

Assessment in practice

1 marks
How it is assessed

This objective is assessed through multiple choice, commonly using State / Identify.

Command terms

State / Identify

What earns marks

Build the answer around this relationship: Resolution is the ability to distinguish two nearby points as separate.

Watch for

Using magnification and resolution as if they describe the same property.

Representative question

Question 1

[Maximum number: 1]

What is a feature of immunofluorescence in light microscopy?

A

Can only be used on dead cells

B

Enables higher resolution

C

Attaches a fluorescent stain to an antibody

D

Attaches a fluorescent stain to an antigen

All Cells Share a Minimal Structural Toolkit

All cells have a plasma membrane, cytoplasm, ribosomes and genetic material, even though their shapes and internal compartments differ.

The membrane separates the internal reaction space, cytoplasm contains soluble chemistry, ribosomes make polypeptides, and DNA or equivalent genetic material stores instructions. These shared features support the cell-theory definition of a cell.

When identifying a cell, look for:

  • boundary and internal fluid
  • genetic material
  • ribosomes or ribosome-rich regions
  • a method of protein synthesis

A prokaryotic cell lacks a nucleus but still has DNA, ribosomes, cytoplasm and a plasma membrane.

A nucleus is not a universal cell feature; it is a eukaryotic compartment.

Structures common to all cells

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Compare / Contrast.

Command terms

Identify / Compare / Contrast

What earns marks

Build the answer around this relationship: A plasma membrane encloses every cell and regulates exchange.

Watch for

Naming a nucleus or membrane-bound organelle as a structure present in every cell.

Representative question

Question 1

[Maximum number: 2]

List two structures that neurons have in common with prokaryotic cells.

Recognize the Required Gram-Positive Prokaryote Model

A typical Gram-positive eubacterium such as Bacillus or Staphylococcus has a cell wall outside a plasma membrane, cytoplasm with 70S ribosomes, and naked circular DNA in a nucleoid region.

Structure Recognition or role
Cell wall Rigid outer layer supporting cell shape
Plasma membrane Selective exchange and membrane-based processes
Cytoplasm Aqueous reaction space
70S ribosomes Protein synthesis
Naked DNA loop Main chromosome without a nuclear envelope
Plasmid, when present Small additional circular DNA molecule

A micrograph showing a small walled cell with dispersed ribosomes and no nucleus is consistent with a prokaryote; its DNA occupies a nucleoid rather than a membrane-bound nucleus.

Prokaryotic structure varies, but detailed exceptions such as wall-less bacteria are outside this objective. No nucleus does not mean no DNA.

Prokaryote cell structure

Assessment in practice

1–3 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Compare / Label.

Command terms

Identify / Compare / Label / Outline / State / Draw / Distinguish / Annotate

What earns marks

Build the answer around this relationship: Prokaryotic DNA occupies a nucleoid rather than a membrane-bounded nucleus.

Watch for

Assigning a nucleus or membrane-bound organelles to a prokaryotic cell.

Representative question

Question 1

[Maximum number: 9]

Escherichia coli is a unicellular organism, so each cell must carry out all of the processes required for life. Outline the functions of each of the structures in the cells of Escherichia coli.

Eukaryotic Compartments Divide Cellular Work

A eukaryotic cell has a plasma membrane enclosing compartmentalized cytoplasm with 80S ribosomes, a nucleus and membrane-bound organelles.

Structure Required feature or role
Nucleus DNA-histone chromosomes inside a double membrane with pores
Mitochondrion Aerobic respiration and ATP production
Rough / smooth ER Protein synthesis and processing / lipid-related synthesis
Golgi apparatus Modifies and sorts cell products
Vesicles, vacuoles, lysosomes Transport, storage or intracellular digestion
Cytoskeleton Microtubules and microfilaments organize shape and movement
80S ribosomes Protein synthesis in cytoplasm or on rough ER

A secreted protein is synthesized on rough-ER ribosomes, processed through ER and Golgi, then carried in a vesicle to the plasma membrane.

Not every eukaryotic cell displays every organelle equally clearly; identify the cell using a combination of visible structures.

Eukaryote cell structure

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Label / State.

Command terms

Identify / Label / State / Draw

What earns marks

Build the answer around this relationship: The nucleus encloses the chromosomes of a eukaryotic cell.

Watch for

Identifying an organelle from size alone while ignoring membranes and internal structure.

Representative question

Question 1

[Maximum number: 2]

Label structures I, II, III and IV.
I.
II.
III.
IV.

A Unicellular Organism Performs Every Life Process

A unicellular organism must perform all essential life processes within one cell: homeostasis, metabolism, nutrition, movement, excretion, growth, response to stimuli and reproduction.

Need One-cell solution
Nutrition and metabolism Takes in materials and converts them through enzyme-controlled reactions
Homeostasis and excretion Regulates internal conditions and removes wastes
Movement and response Uses a flagellum, cilia, pseudopodia or directed growth where applicable
Growth and reproduction Makes new cell material, copies genetic information and divides

Paramecium uses cilia for movement and feeding, food vacuoles for digestion, and contractile vacuoles for water balance and excretion.

A unicellular organism is a complete living organism, not one specialized cell waiting for a tissue to perform the remaining life processes.

Processes of life in unicellular organisms

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Outline / Compare.

Command terms

Identify / Outline / Compare / Contrast

What earns marks

Build the answer around this relationship: One cell performs all functions required by a unicellular organism.

Watch for

Including differentiation or meiosis among functions performed by every unicellular organism.

Representative question

Question 1

[Maximum number: 4]

Unicellular and multicellular organisms share the same functions of life. Outline four functions of life.

Plant, Animal and Fungal Cells Share a Core but Differ

Animal, fungal and plant cells share the eukaryotic core but differ in cell walls, vacuoles, plastids and motile structures.

Feature Plant Fungus Animal
Cell wall Cellulose Chitin Absent
Vacuoles Usually one large permanent sap vacuole Vacuoles present, variable size and roles Smaller temporary vesicles/vacuoles
Chloroplasts / plastids Present in photosynthetic tissues; other plastids may occur Absent Absent
Centrioles, cilia, flagella Variable; absent from many typical plant cells Variable Centrioles common; cilia or flagella in some cells

A cellulose wall, chloroplasts and a large sap vacuole together support a plant-cell identification more strongly than any single feature.

Specialized cells may lack a typical feature; for example, a plant root cell normally lacks chloroplasts. Use combinations and context.

Differences in eukaryotic cells

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / State / Explain.

Command terms

Identify / State / Explain / Distinguish

What earns marks

Build the answer around this relationship: Plant cell walls contain cellulose and support a regular cell outline.

Watch for

Claiming that every plant cell contains chloroplasts.

Representative question

Question 1

[Maximum number: 3]

Distinguish between structures in animal and plant cells.

Atypical Cell Structures Need a Careful Definition

Atypical eukaryotic cells show that one cell does not always contain exactly one nucleus.

Example Nuclear arrangement Functional consequence
Aseptate fungal hypha Many nuclei share continuous cytoplasm Cytoplasm and materials move along the hypha
Skeletal muscle fibre Multinucleate after cell fusion Supports a very large contractile cell
Mammalian red blood cell Loses nucleus at maturity More space for haemoglobin but no division
Phloem sieve tube element Loses nucleus at maturity More open transport pathway; depends on companion cells

A skeletal muscle fibre is one long multinucleate cell, whereas an aseptate fungal hypha contains many nuclei in a cytoplasm not divided by complete cross-walls.

Atypical does not mean non-cellular. Identify the continuous membrane boundary and explain the altered nuclear arrangement.

Atypical cell structure

Assessment in practice

1 marks
How it is assessed

This objective is assessed through essay response, commonly using Identify / Discuss / State.

Command terms

Identify / Discuss / State

What earns marks

Build the answer around this relationship: Striated muscle fibres contain many nuclei in a shared cytoplasm.

Watch for

Treating an atypical cell as evidence that the entire cell theory is false.

Representative question

Question 1

[Maximum number: 7]

Discuss the cell theory and its limitations.

Identify Cells by a Bundle of Visual Evidence

Identify a cell or organelle in a micrograph by combining visible structures, scale and context; never rely on outline alone.

Target Useful visible cues
Prokaryote Nucleoid region, prokaryotic wall, small size, ribosome-rich cytoplasm, no nucleus
Plant cell Cell wall, chloroplasts where present, large sap vacuole
Animal cell Plasma membrane without a cell wall; nucleus and other organelles where visible
Organelles Nucleus/chromosomes, mitochondrion, chloroplast, Golgi, rough or smooth ER, ribosomes, vacuole, microvilli

First read the scale bar, then identify boundaries, then require at least two compatible features. Section angle can hide organelles, so state uncertainty when evidence is incomplete.

A double-membrane organelle with internal cristae is a mitochondrion; a thick wall plus chloroplasts and a sap vacuole supports a plant cell.

Absence from one section is not proof that the whole cell lacks a structure. Use only what the micrograph and scale can support.

Cell identification in micrographs

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Determine / State.

Command terms

Identify / Determine / State / Outline

What earns marks

Build the answer around this relationship: Internal membrane patterns provide strong evidence for organelle identity.

Watch for

Naming an organelle from general shape without checking its membrane or internal pattern.

Representative question

Question 1

[Maximum number: 3]

Identify organelles I to III.

I:
II:
III:

Draw Only Evidence You Can Defend

A drawing from an electron micrograph records observed structure with clear lines, while an annotation adds a supported function to a labelled feature.

Use a sharp pencil or digital single lines, draw large proportional outlines without shading, include only visible structures, add a title and scale or magnification, and keep label lines ruled and non-crossing.

Annotations must pair structure with function, for example: cristae - membrane surface for aerobic ATP production; rough ER - ribosome-bearing membrane involved in protein synthesis; microvilli - increase exchange surface area.

If an electron micrograph shows a mitochondrion, draw its visible membranes and cristae, label them, and annotate the cristae with their respiratory function.

Do not add textbook structures that are not visible, and do not call a name-only label an annotation when a function is required.

Drawing and annotation

Assessment in practice

3 marks
How it is assessed

This objective is assessed through experimental design, commonly using Draw.

Command terms

Draw

What earns marks

Build the answer around this relationship: Biological drawings use clear single outlines without shading.

Representative question

Question 1

[Maximum number: 3]

Draw a labelled diagram of a nucleus from a eukaryotic cell, such as an onion epidermis cell, as seen using an electron microscope.

SL Retrieval: Read, Identify, Draw

The SL core is a practical chain. First, understand cells as structural and functional units. Then use microscopes correctly: prepare, stain, calibrate, measure, and choose a method based on resolution and the detail needed. Finally, identify cell types from visible evidence and draw only what the micrograph shows. This is how the topic turns from definitions into exam performance.

  • Cell theory: cells are structural and functional units.
  • Microscopy: resolution, calibration, magnification, actual size, and scale bars.
  • Cell identity: universal parts, prokaryote/eukaryote differences, and plant/animal/fungal evidence.
  • Micrograph work: justify from visible structures, scale, and context.
  • Drawing: clear lines, no shading, visible labels only, scale/magnification included.

Endosymbiosis Explains Mitochondria and Chloroplasts

HL only

Endosymbiosis explains mitochondria and chloroplasts as descendants of bacteria incorporated into early eukaryotic cells.

A common unicellular eukaryotic ancestor already had a nucleus and sexual reproduction. Mitochondria then arose by endosymbiosis; chloroplasts arose later in some eukaryotic lineages.

Observation in mitochondria/chloroplasts Endosymbiotic inference
70S ribosomes Resemble bacterial translation machinery
Naked circular DNA Resembles bacterial chromosomes
Replication within the cell Retains bacterial-like division capacity
Double membrane and bacterial sequence similarity Consistent with engulfment and bacterial ancestry

Mitochondrial circular DNA and 70S ribosomes are independent evidence lines; together they support bacterial ancestry more strongly than organelle shape alone.

Modern organelles are dependent parts of eukaryotic cells, not free-living bacteria. Chloroplast endosymbiosis occurred only in lineages that possess plastids.

Endosymbiosis origin of eukaryotes

HL only

Assessment in practice

1–3 marks
How it is assessed

This objective is assessed through essay response, commonly using Discuss / Explain / Outline.

Command terms

Discuss / Explain / Outline / Identify / Describe

What earns marks

Build the answer around this relationship: Mitochondria descend from aerobic bacterial endosymbionts.

Watch for

Listing organelle features without explaining how they support bacterial ancestry.

Representative question

Question 1

[Maximum number: 6]

Explain the endosymbiotic theory for the origin of eukaryotes and the evidence for it.

Differentiation Uses the Same Genome in Different Ways

HL only

Cell differentiation produces specialized cell types mainly by changing which genes are expressed, not by giving each cell a completely different genome.

Signals and transcription factors open or silence particular genes. The resulting proteins alter structure and function, so cells with the same DNA can become neurons, muscle cells or secretory cells.

Trace the causal chain:

  • signal or transcription factor
  • gene expression change
  • protein production
  • specialized structure/function

A muscle precursor expresses contractile-protein genes, while a neuron expresses ion-channel and neurotransmitter genes; both retain the same genome.

Different cell types are not usually created by losing unrelated genes; selective expression is the key mechanism.

Cell differentiation

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Determine / Outline.

Command terms

Identify / Determine / Outline

What earns marks

Build the answer around this relationship: Differentiated cells usually retain the same genome.

Watch for

Explaining differentiation by claiming that specialized cells contain different sets of genes.

Representative question

Question 1

[Maximum number: 4]

Outline the reasons for differences between the proteomes of cells within a multicellular organism.

Multicellularity Enables Division of Labour

HL only

Multicellularity evolved independently many times, including in fungi and eukaryotic algae and in the ancestors of plants and animals.

Cells had to remain attached, communicate and coordinate different patterns of gene expression. Once cooperation was stable, larger body size and specialized cell types could evolve.

Use the sequence: adhesion -> communication and coordination -> differentiation -> tissues or larger bodies. Repeated origins show multicellularity is not one inherited event shared by all multicellular groups.

A plant leaf combines specialized epidermal, mesophyll and vascular cells, allowing gas exchange, photosynthesis and transport to be divided among cell types.

Multicellularity brings dependence and coordination costs; its syllabus advantages are larger body size and cell specialization, not automatic superiority in every environment.

Complex Cell Origins

HL only

The HL extension asks how complex cell organization could arise and become useful. Endosymbiosis explains the origin of mitochondria and chloroplasts using bacterial evidence. Differentiation explains how cells with the same genome become specialized through different gene expression and proteomes. Multicellularity explains why adhesion, communication, and differentiation allowed larger bodies and division of labour.

  • Endosymbiosis: organelle origin supported by bacterial-style evidence.
  • Differentiation: same genome, different gene expression, different proteome.
  • Multicellularity: adhesion, communication, differentiation.
  • Advantages: larger body size and cell specialization.

Topic A2.3

A2.3 Viruses [HL only]

Viruses are structurally diverse, acellular parasites whose host-dependent replication cycles, multiple evolutionary origins, and rapid genetic change shape infection and immune escape.

11% of analysed papers 12 papers · 14 questions

Objectives in this topic

Viruses Share a Basic Genetic Package

HL only

All viruses are small particles of fixed size with a DNA or RNA genome enclosed by a protein capsid. They are non-cellular and can reproduce only inside host cells.

Viruses have no cytoplasm or ribosomes and few or no metabolic enzymes, so they depend on host energy, nutrients, protein synthesis and other life functions. Some, but not all, viruses also have a host-derived lipid envelope.

Features shared by all viruses: nucleic-acid genome, protein capsid, small fixed particle size and absence of cytoplasm. Envelope, spikes and many enzymes are variable rather than universal.

A virus particle can carry genes and a protective capsid yet cannot translate its own proteins because it has no ribosomes.

Do not define every virus as enveloped or as containing both DNA and RNA. A viral genome is DNA or RNA, and an envelope is optional.

Common structural features

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using State / Label / Describe.

Command terms

State / Label / Describe / Justify

What earns marks

Build the answer around this relationship: Every virus has genetic material enclosed by a protein capsid.

Watch for

Describing viruses as cells that merely lack a nucleus instead of recognizing that they are acellular.

Representative question

Question 1

[Maximum number: 1]

Describe one reason that viruses are not considered to be living.

Compare Genome, Capsid and Envelope Diversity

HL only

Viruses vary in genome type, capsid shape and whether they carry a host-derived membrane envelope.

Example Genome Outer structure Distinctive form
Bacteriophage lambda Double-stranded DNA Non-enveloped protein capsid with tail Complex head-tail particle that infects E. coli
Coronavirus Single-stranded RNA Enveloped with projecting spike proteins Roughly spherical enveloped particle
HIV Two copies of single-stranded RNA Enveloped Conical capsid inside the envelope

Across viruses, genetic material may be DNA or RNA and single- or double-stranded. Capsids can adopt different geometries, and envelopes are present in some lineages but absent in others.

An envelope can aid fusion with a host membrane but is more easily disrupted by detergents or drying than a protein capsid.

Shape alone does not determine host range or identify a species; receptor matching and replication compatibility also matter.

Diversity of virus structure

HL only

Assessment in practice

2 marks
How it is assessed

This objective is assessed through structured response, commonly using Outline / State / Describe.

Command terms

Outline / State / Describe

What earns marks

Build the answer around this relationship: Viral genomes may be DNA or RNA and may be single- or double-stranded.

Watch for

Claiming that a virus contains both DNA and RNA instead of one type of nucleic acid genome.

Representative question

Question 1

[Maximum number: 7]

Describe, with examples, the diversity of structure in viruses.

The Lytic Cycle Makes New Virions Quickly

HL only

In lambda's lytic cycle, the phage attaches to E. coli, injects its double-stranded DNA, redirects host resources, assembles new phages and lyses the bacterium.

The viral DNA remains separate from the bacterial chromosome. Viral genes use host energy, nutrients, ribosomes and enzymes to copy phage DNA and synthesize capsid and tail proteins; host DNA may be degraded.

Sequence: attachment -> DNA injection -> viral genome replication and protein synthesis -> assembly of heads, tails and genomes -> bacterial lysis and release.

One infected E. coli cell can assemble many lambda particles before the cell wall ruptures and releases them to infect neighbouring bacteria.

Lytic replication makes components before release; a phage does not grow larger and split like a bacterial cell.

Lytic cycle

HL only

Assessment in practice

1–3 marks
How it is assessed

This objective is assessed through multiple choice, commonly using Identify / Compare / Contrast.

Command terms

Identify / Compare / Contrast

What earns marks

Build the answer around this relationship: Lambda phage attaches to E. coli and injects its DNA into the host.

Watch for

Reversing the cycles by placing viral DNA integration in the lytic cycle.

Representative question

Question 1

[Maximum number: 1]

What is a difference between the lytic and the lysogenic cycle of the bacteriophage lambda?

A

Only in the lytic cycle is lambda DNA inserted into the host DNA.

B

Only in the lysogenic cycle is the host metabolism used to replicate.

C

Only in the lytic cycle is the host metabolism used to replicate.

D

Only in the lysogenic cycle is lambda DNA inserted into the host DNA.

The Lysogenic Cycle Hides a Viral Genome

HL only

In lambda's lysogenic cycle, phage DNA integrates into the E. coli chromosome as a prophage instead of immediately producing new virions.

The prophage is copied whenever the bacterial chromosome replicates and is passed to daughter cells during binary fission. Stress such as DNA damage can induce excision and entry into the lytic cycle.

Sequence: attachment and injection -> integration as prophage -> copying with the host genome -> induction -> excision and lytic replication.

A lysogenic bacterium can divide repeatedly without bursting; after induction, the same viral DNA directs phage assembly and eventual lysis.

A prophage is not an inactive virus particle hidden inside the cell; it is viral DNA integrated into the host chromosome.

Lysogenic cycle

HL only

Assessment in practice

3 marks
How it is assessed

This objective is assessed through structured response, commonly using Explain.

Command terms

Explain

What earns marks

Build the answer around this relationship: Lambda DNA integrates into the bacterial chromosome during lysogeny.

Representative question

Question 1

[Maximum number: 3]

Explain how the bacteriophage lambda reproduces in the lysogenic cycle.

Viruses May Have Multiple Evolutionary Origins

HL only

The diversity of viruses is consistent with more than one evolutionary origin, rather than one simple family tree from a single first virus.

Some viruses resemble escaped genetic elements, some may descend from reduced cellular organisms, and others may have assembled from ancient replicators. Similar functions can evolve independently, so shared genes must be interpreted with context.

When comparing origins, ask:

  • what genes and structures are shared
  • whether cellular ancestors are plausible
  • whether similarity could be convergent
  • how host association changed

A capsid gene shared by distant viruses may indicate transfer or convergent function; it does not alone prove one direct ancestor.

‘All viruses evolved from one virus’ is stronger than the evidence supports.

Viral Populations Can Evolve Rapidly

HL only

Some viruses evolve rapidly because short generation times, very large populations, mutation and recombination continually create heritable variation.

RNA-copying enzymes often lack effective proofreading. Influenza changes by antigenic drift through accumulated mutations and can change abruptly by antigenic shift through genome-segment reassortment. HIV reverse transcriptase is error-prone, producing many variants.

Virus Rapid-change mechanism Consequence
Influenza Antigenic drift; occasional antigenic shift Immunity may recognize new strains poorly, so vaccine composition requires review and updating
HIV Frequent reverse-transcriptase errors plus selection Drug-resistant variants can rise, supporting combination therapy and careful adherence

If one HIV variant resists a drug, treatment suppresses susceptible variants and the resistant lineage can leave more descendants; using multiple drugs makes simultaneous resistance less likely.

Mutation is not directed by treatment, and an individual virion does not adapt. Selection changes variant frequencies in the viral population.

Rapid evolution in viruses

HL only

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using Suggest / Outline.

Command terms

Suggest / Outline

What earns marks

Build the answer around this relationship: Error-prone replication creates mutations especially rapidly in many RNA viruses.

Watch for

Attributing rapid viral evolution only to mutation while omitting replication rate, recombination, or selection.

Representative question

Question 1

[Maximum number: 2]

Outline two reasons for the very rapid rates of evolution in some viruses.

Build A Virus Answer

HL only

A strong HL virus answer usually combines two moves: define the boundary, then explain the mechanism or consequence. Viruses have DNA or RNA plus a capsid but lack the machinery for independent metabolism. Their diversity is described by genome, capsid, and envelope. Lambda phage lets you contrast lytic takeover with lysogenic integration. Origin questions require competing hypotheses and polyphyly. Evolution questions require mutation, recombination, short cycles, large populations, and examples such as influenza or HIV.

  • Definition: non-cellular obligate parasite with genome plus capsid, lacking cytoplasm/ribosomes/metabolic enzymes.
  • Structure: compare genome, capsid shape, and envelope status.
  • Replication: lytic = takeover and lysis; lysogenic = prophage integration and induction.
  • Origins: likely polyphyletic, with virus-first, escaped-gene, and regressive hypotheses.
  • Evolution: rapid variation explains vaccine updates and treatment resistance.

Topic A3.1

A3.1 Diversity of organisms

Diversity of organisms links variation, species concepts, classification tools, chromosome evidence, and genome comparisons to explain biological similarity and difference.

32% of analysed papers 36 papers · 47 questions

Objectives in this topic

Variation Makes Populations Non-identical

Variation means members of a species differ in traits, and it is a defining feature of life because populations are not exact copies.

Differences can arise from mutation, recombination, gene flow and environmental effects. Heritable variation supplies material for evolution; non-heritable differences can still affect an individual without changing the next generation’s gene pool.

Separate sources of variation:

  • genetic and potentially heritable
  • environmental and usually acquired
  • continuous or discontinuous traits
  • variation within or between populations

Two genetically similar plants can grow to different heights in different light, while a DNA mutation can create a heritable difference in pigment.

Variation is not automatically an adaptation; it must be heritable and affect reproductive success to drive selection.

Variation as defining feature of life

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using State.

Command terms

State

What earns marks

Build the answer around this relationship: Variation occurs between individuals within every species.

Watch for

Describing visible differences without naming a genetic or reproductive cause of variation.

Representative question

Question 1

[Maximum number: 2]

State, giving a reason, the type of variation shown by shell length.

Classify Species and Write Binomial Names

Morphology and naming rules.

The morphological species concept groups organisms as one species when they share a characteristic set of observable, inherited structural traits.

This original Linnaean approach is practical for field observations, preserved specimens and fossils. However, natural variation, life stages and sexual dimorphism can make members of one species look different, while unrelated species can look similar.

Binomial nomenclature gives every species a universal two-part name: the genus begins with a capital letter, the second word is lowercase, and both words are italicized when typed or underlined when handwritten. Species placed in the same genus share similar traits.

In Panthera leo and Panthera tigris, Panthera is the shared genus and the lowercase second words distinguish lion from tiger.

A shared appearance supports a morphological classification but does not by itself demonstrate interbreeding. The biological species concept uses reproductive evidence instead.

Species as groups with shared traits

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using Distinguish / State / Identify.

Command terms

Distinguish / State / Identify / Outline

What earns marks

Build the answer around this relationship: Shared traits can support classification when they distinguish the target group from alternatives.

Watch for

Using broad traits that fit many groups instead of traits diagnostic for the requested group.

Representative question

Question 1

[Maximum number: 2]

List two anatomical features of humans that are characteristic of primates.
1.
2.

Binomial system

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using Outline / Identify / State.

Command terms

Outline / Identify / State / Suggest

What earns marks

Build the answer around this relationship: The genus is the first word of a binomial name.

Watch for

Using the second word of a binomial to infer closest relatedness when the genus differs.

Representative question

Question 1

[Maximum number: 4]

Outline the binomial system of classification.

Use the Biological Species Concept Carefully

The biological species concept defines a species as a group of organisms that can breed with one another and produce fertile offspring.

Successful reproduction allows gene flow within the species, whereas reproductive isolation limits gene flow between species. During speciation, separated populations usually diverge gradually rather than becoming different species in one step.

To apply the concept: identify whether breeding is possible, determine whether offspring are viable and fertile, and distinguish actual reproductive isolation from populations merely being unable to meet. Because divergence is continuous, the point at which two populations receive different species names can be partly arbitrary.

Two geographically isolated populations may never meet in nature but could still produce fertile offspring if brought together. Their separation alone therefore does not prove that they are different biological species.

The concept is difficult to test for fossils, asexual organisms and geographically isolated populations, and competing species definitions may give a different boundary.

Biological species concept

Assessment in practice

1–3 marks
How it is assessed

This objective is assessed through structured response, commonly using Discuss / Outline / State.

Command terms

Discuss / Outline / State / Define

What earns marks

Build the answer around this relationship: Members of the same biological species can produce fertile offspring.

Watch for

Using interbreeding alone without stating that offspring must be fertile.

Representative question

Question 1

[Maximum number: 3]

Outline the criteria that should be used to assess whether a group of organisms is a species.

Difficulties in distinguishing species

Assessment in practice

1 marks
How it is assessed

This objective is assessed through data analysis, commonly using State.

Command terms

State

What earns marks

Build the answer around this relationship: Speciation is gradual, so boundaries between diverging populations can be uncertain.

Representative question

Question 1

[Maximum number: 1]

State with a reason whether the genetic evidence shows that the western coyote and the grey wolf have overlapping ranges.

Read Chromosome Number and Karyograms as Evidence

A clean chromosome-number comparison above a human karyogram with chromosome 2 fusion highlighted and labeled by length, banding pattern, and centromere position.

Chromosome number is usually constant within a species but varies widely between species. Humans have 46 chromosomes and chimpanzees have 48; diploid chromosome numbers are normally even because chromosomes occur as homologous pairs.

Karyotyping records the number and structural appearance of chromosomes. A karyogram is the ordered image produced by pairing homologous chromosomes and arranging them using length, banding pattern and centromere position.

A karyogram can reveal chromosome-number differences and structural similarities. Evidence for human chromosome 2 fusion includes its correspondence to two ancestral ape chromosomes, internal telomeric sequences at the predicted fusion site and remnants of a second centromere.

When pairing chromosomes in a karyogram, first match banding patterns, then confirm comparable length and centromere position rather than relying on size alone.

The observations support a testable fusion hypothesis; they should not be described as proof based only on humans having two fewer chromosomes than chimpanzees.

Diversity in chromosome numbers

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using State.

Command terms

State

What earns marks

Build the answer around this relationship: Diploid chromosome number is usually constant within a species.

Watch for

Treating chromosome number as a measure of organism complexity or evolutionary progress.

Representative question

Question 1

[Maximum number: 1]

State the chromosome number in this gorilla.

Karyotyping and karyograms

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using State / Determine / Explain.

Command terms

State / Determine / Explain / Analyse / Identify / Outline / Compare / Distinguish / Justify / Describe / Draw

What earns marks

Build the answer around this relationship: Karyograms arrange homologous chromosomes by size, banding pattern, and centromere position.

Watch for

Treating karyotyping as a test for individual gene mutations rather than chromosome-level abnormalities.

Representative question

Question 1

[Maximum number: 8]

Explain the use of karyotyping in human genetics.

Genome variation within and between species

Two DNA molecules with a single nucleotide polymorphism highlighted at one base position.

A genome is all the genetic information of an organism: protein-coding genes, non-coding DNA and, where present, non-nuclear DNA such as plasmids or organelle genomes.

Members of the same species share most genes and genome organisation but differ in variants. A single-nucleotide polymorphism (SNP) is a one-base difference that can act as a genetic marker. Variation between species is generally much greater than variation within one species, although the two distributions can overlap.

Across eukaryotes, genomes differ in total size, base sequence and chromosome organisation. A larger genome does not automatically mean a more complex organism because much DNA is non-coding and genome size can be affected by repeated sequences or polyploidy. In comparisons, state both the level (within or between species) and the feature being compared (sequence, size or organisation).

Unity and diversity of genomes within

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through essay response, commonly using Compare / Discuss / Determine.

Command terms

Compare / Discuss / Determine / Contrast / State / Distinguish / Calculate

What earns marks

Build the answer around this relationship: A genome includes all DNA in the organism, including organelle DNA where present.

Watch for

Assuming every SNP changes the proteome rather than recognising that it always changes the genome.

Representative question

Question 1

[Maximum number: 7]

Discuss the role of genes and chromosomes in determining individual and shared character features of the members of a species.

Diversity of eukaryote genomes

Assessment in practice

1 marks
How it is assessed

This objective is assessed through multiple choice.

What earns marks

Build the answer around this relationship: Eukaryote genomes vary in gene number and DNA sequence.

Representative question

Question 1

[Maximum number: 1]

The table shows the estimated total number of genes in several organisms.

SpeciesEstimated number of genes
Saccharomyces cerevisiae (a yeast)6000
Escherichia coli (a bacterium)3200
Drosophila melanogaster (fruit fly)14000
Canis familiaris (domestic dog)19000
Oryza sativa (rice)51000
Homo sapiens (human)25000

What can be deduced from the information in this table?

A

Throughout evolution, the number of genes increases.

B

The domestic dog is more closely genetically related to the fruit fly than to the human.

C

The number of genes does not determine evolutionary success.

D

Humans produce about half as many proteins as rice.

Compare Genome Size and Use Whole-Genome Sequences

Genome size comparison and sequencing uses.

Genome size is the total amount of DNA in one haploid chromosome set. It can be compared across taxonomic groups, but a larger genome does not necessarily indicate a more complex organism.

Non-coding repeated DNA and polyploidy can increase genome size without adding a proportional number of functional genes. Database comparisons must therefore use consistent units and distinguish haploid from diploid measurements.

The Human Genome Project helped establish large-scale whole-genome sequencing. As sequencing has become faster and less expensive, current uses include studying evolutionary relationships and identifying genes or variants; a potential expanding use is personalized medicine.

A researcher can compare homologous genome sequences from several species, measure their sequence differences and use the pattern as evidence for closer or more distant evolutionary relationships.

A genome sequence provides data, not a diagnosis or treatment by itself. An interpretation must connect a validated genetic difference to evidence about function, ancestry or health.

Comparison of genome sizes

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through essay response, commonly using Discuss.

Command terms

Discuss

What earns marks

Build the answer around this relationship: Genome size means total DNA amount, not total gene number.

Watch for

Equating genome size with gene number or chromosome number.

Representative question

Question 1

[Maximum number: 2]

Using the data provided in the table, discuss whether genome size positively correlates to organism complexity.

Whole genome sequencing

Assessment in practice

2–3 marks
How it is assessed

This objective is assessed through essay response, commonly using Suggest / Describe / Discuss.

Command terms

Suggest / Describe / Discuss

What earns marks

Build the answer around this relationship: Whole genome sequencing produces complete DNA sequence information for an organism.

Representative question

Question 1

[Maximum number: 3]

Discuss the current and potential future uses of whole genome sequencing.

SL Transfer: Classify With Evidence

For SL, A3.1 is really one evidence map. Variation explains why individuals differ. Morphology and binomial nomenclature help group and name organisms. The biological species concept uses interbreeding and fertile offspring, but boundaries can be difficult during gradual speciation. Chromosomes and karyograms add cellular evidence. Genomes, SNPs, genome size, and whole genome sequencing add molecular evidence. The skill is choosing the right evidence for the question.

  • Variation supports natural selection.
  • Morphology groups by structure; binomial nomenclature names species universally.
  • Biological species concept uses interbreeding and fertile offspring.
  • Karyograms compare chromosome number and structure.
  • Genome evidence includes SNPs, between-species differences, genome size, and sequencing uses.

Repair Species Boundaries with HL Evidence

HL only
A compact contrast panel. Left side: bacteria exchanging genes by transformation, plasmids, and recombination, showing why interbreeding is the wrong test. Right side: horse and donkey producing an infertile mule, with a note that chromosome-number mismatches can block fertile hybrids.
Bacterial horizontal gene transfer by transduction, transformation and conjugation.

The biological species concept is based on sexual reproduction, so it does not work well for asexual organisms or for bacteria that exchange genes horizontally.

Bacteria gain diversity through mutation and horizontal gene transfer, including transformation, plasmid transfer and recombination. Genes can therefore cross lineage boundaries without the organisms breeding as animals or plants do.

In many sexually reproducing species, haploid and diploid chromosome numbers are shared traits because meiosis and fertilization conserve chromosome number across generations. If closely related parents have different chromosome numbers, homologous pairing in a hybrid's meiosis can fail, reducing fertility.

A horse and donkey can produce a mule, but mismatched parental chromosome sets disrupt homologous pairing during meiosis, so the hybrid is usually infertile.

Chromosome number can support a species distinction but is not a universal definition: different species can share a chromosome number, and bacterial boundaries require evidence other than interbreeding.

Difficulties with biological species concept

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Outline.

Command terms

Outline

What earns marks

Build the answer around this relationship: Bacteria usually reproduce asexually by binary fission.

Representative question

Question 1

[Maximum number: 1]

Outline a difficulty in applying the biological species concept to bacteria.

One additional mark is available for the construction of your answers for each question.

Chromosome number as shared trait

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using State / Suggest.

Command terms

State / Suggest

What earns marks

Build the answer around this relationship: Haploid chromosome number is usually fixed for a species.

Watch for

Confusing haploid, diploid, and autosome counts.

Representative question

Question 1

[Maximum number: 1]

Sex is determined in the same way in pangolins as in humans. State how many autosomes there are in somatic cells of M. pentadactyla.

Dichotomous keys and DNA identification

HL only
A split workflow visual. Left side: a branching dichotomous key built from observable local traits. Right side: an eDNA barcoding pipeline showing environmental sample, PCR amplification, barcode sequence, and database match.

Choose the identification tool that matches the available evidence.

  • Dichotomous key: repeatedly choose between paired statements based on observable traits. Use reliable, relatively immutable features such as structures or reproductive processes; size, colour and behaviour may vary with age or environment. Each choice should lead to one narrower group until the specimen is identified.
  • DNA barcoding: amplify and sequence a short standard region of DNA from a specimen, then compare it with a reference database to identify the species.
  • Environmental DNA (eDNA): collect DNA traces from water, soil or another habitat, amplify barcode regions by PCR and match sequences to a database; it can detect organisms that are not directly observed.

Keys are useful when visible features are intact and reliable. Barcoding or eDNA is more useful when specimens are damaged, partial, cryptic or absent. Local plant or animal species can be used to build and test a key, but a database match is evidence of sequence similarity, not automatically proof that every individual in the habitat was sampled.

Dichotomous key development

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify.

Command terms

Identify

What earns marks

Build the answer around this relationship: Dichotomous keys use paired contrasting choices.

Watch for

Choosing an organism from appearance alone instead of following each key branch.

Representative question

Question 1

[Maximum number: 2]

Parts of a dichotomous key to organisms A, B, C and D are shown. Design missing parts of the key using features visible in the following diagrams.

1. Body with tentacles ..... A
Body without tentacles ..... go to 2
2. ..... B
……go to 3
3. ..... C
.....D

Environmental DNA barcodes

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through multiple choice.

What earns marks

Build the answer around this relationship: DNA barcodes are short diagnostic sequences used for species identification.

Representative question

Question 1

[Maximum number: 1]

What is one application of DNA barcoding?

A

Selective breeding

B

Preserving an endangered species

C

Analysing environmental DNA

D

Sequencing a genome

Boundaries And Identification

HL only

The HL extension connects two problems: species boundaries and species identification. Bacteria challenge the biological species concept because they are asexual and exchange genes horizontally. Chromosome number can help define boundaries in many sexual species because meiosis conserves it and mismatches can produce infertile hybrids. Dichotomous keys identify visible organisms using paired choices. DNA barcoding and eDNA identify species using short sequences, PCR, and databases when visible traits are limited.

  • Bacterial boundaries are blurred by mutation and horizontal gene transfer.
  • Chromosome number is usually conserved within sexual species by meiosis.
  • Different chromosome numbers can prevent fertile hybrids, as in mules.
  • Dichotomous keys use observable traits and paired choices.
  • DNA barcoding/eDNA use PCR and database comparison for damaged, partial, hidden, or difficult specimens.
  • Local plant or animal species can be used to build and test dichotomous keys.

Topic A3.2

A3.2 Classification and cladistics [HL only]

Classification and cladistics use hierarchy, molecular evidence, clades, cladograms, molecular clocks, and domains to organize evolutionary relationships across biodiversity accurately.

27% of analysed papers 31 papers · 39 questions

Objectives in this topic

Classification Makes Biological Diversity Usable

HL only

Classification organizes organisms into named groups so observations, communication and evolutionary relationships can be compared consistently.

A useful classification reduces ambiguity in common names and links new evidence to existing groups. The best system reflects both observable traits and shared ancestry rather than relying on one convenient feature.

A classification should help with:

  • identification
  • communication
  • prediction of traits
  • testing evolutionary hypotheses

Grouping organisms by homologous structures can predict that newly found relatives share developmental features, even before their genomes are sequenced.

Classification is a model for organizing evidence, not a claim that every boundary is permanent.

Need for classification

HL only

Assessment in practice

4 marks
How it is assessed

This objective is assessed through structured response, commonly using Outline.

Command terms

Outline

What earns marks

Build the answer around this relationship: Classification makes biodiversity easier to identify, compare, and study.

Representative question

Question 1

[Maximum number: 4]

Outline the principles used by scientists to classify organisms.

Traditional Hierarchies Can Hide Evolutionary History

HL only

The traditional taxonomic hierarchy places organisms in kingdom, phylum, class, order, family, genus and species, but its fixed ranks do not always match evolutionary branching.

Ranks impose discrete levels on a continuous history of divergence. Convergent evolution can make distantly related organisms look similar, while unequal rates of change can make close relatives look different.

When auditing a traditional group, ask whether its defining traits are homologous or analogous, whether it includes a common ancestor and all descendants, and whether molecular evidence supports the same grouping.

Bird and bat wings perform the same function but evolved independently as wings. Grouping birds and bats together from wings alone would confuse convergence with recent common ancestry.

A named rank can remain convenient for communication without representing a clade; fixed rank labels are human conventions rather than measured amounts of divergence.

Difficulties with traditional hierarchy

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Deduce.

Command terms

Deduce

What earns marks

Build the answer around this relationship: Genus is narrower than family, order, and class.

Watch for

Assuming morphological similarity always indicates close evolutionary ancestry.

Representative question

Question 1

[Maximum number: 1]

Based on the taxa shown, deduce a difficulty in gathering data to study turtle ancestry.

Evolutionary Classification Tracks Shared Ancestry

HL only

Evolutionary classification groups organisms by common ancestry and shared derived characteristics, making the branching history explicit.

A shared derived character appears in a common ancestor and is inherited by its descendants. Molecular sequences, fossils and morphology can be combined to test whether a proposed group is monophyletic.

Prefer evidence that is:

  • homologous rather than analogous
  • derived rather than ancestral
  • shared by the proposed clade
  • supported by independent data

If two species share a novel DNA insertion absent from their relatives, that insertion can support a recent common ancestor.

Similarity alone is not enough; the character must be inherited from the relevant ancestor rather than evolved independently.

Advantages of evolutionary classification

HL only

Assessment in practice

1–4 marks
How it is assessed

This objective is assessed through structured response, essay response, commonly using Explain.

Command terms

Explain

What earns marks

Build the answer around this relationship: Natural classification aims to match evolutionary relationships.

Watch for

Using analogous appearance as evidence for close ancestry when molecular evidence contradicts it.

Representative question

Question 1

[Maximum number: 8]

Explain how evolutionary relationships and cladograms can be used for classification.

A Clade Contains an Ancestor and All Its Descendants

HL only

A clade is a group consisting of a common ancestor and all of its descendants.

Clade membership is supported by shared characteristics inherited from the common ancestor. Base sequences of genes and amino-acid sequences of proteins provide especially objective comparisons; homologous morphology can provide additional evidence.

To test a proposed clade: locate one ancestral node, include every branch descending from it, and identify shared derived evidence. Excluding a descendant makes the group paraphyletic; combining separate lineages by superficial similarity makes it polyphyletic.

If several taxa share a derived DNA sequence change absent from the outgroup, that change supports their placement in one clade when the simplest tree assigns it to their common ancestor.

A group of organisms with similar habitats or lifestyles may be an ecological category without being a clade.

Clades exam focus

HL only

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using Define / Label / Identify.

Command terms

Define / Label / Identify / State / Explain / Outline

What earns marks

Build the answer around this relationship: A clade includes a common ancestor and all of its descendants.

Watch for

Selecting a partial branch group as a clade even though it excludes descendants.

Representative question

Question 1

[Maximum number: 3]

Outline the types of evidence that can be used to place a species in a particular clade.

A Molecular Clock Estimates Divergence Time

HL only

A molecular clock estimates when clades diverged by relating differences in homologous DNA or amino-acid sequences to an independently calibrated rate of change.

After two lineages split, sequence differences can accumulate in both. A calibration from fossils or another dated event connects genetic distance to time, allowing an estimated divergence date.

The estimate is uncertain because mutation rates can differ with generation time, population size, selective pressure, gene and lineage. A suitable sequence, evolutionary model, calibration and uncertainty range must all be stated.

If two candidate clades show fewer differences in the same calibrated gene than another pair, the clock model supports a more recent divergence for the first pair, assuming comparable rates.

A molecular clock gives an estimate, not a direct timestamp. Genetic distance cannot be converted to time reliably without calibration and rate assumptions.

Molecular clock

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Outline / State.

Command terms

Outline / State

What earns marks

Build the answer around this relationship: Sequence differences can be counted to estimate time since divergence.

Watch for

Saying only that the relationship is linear without stating that substitutions increase with divergence time.

Representative question

Question 1

[Maximum number: 1]

State the relationship between divergence time and number of substitutions.

Construct a Parsimonious Cladogram from Sequences

HL only

A sequence-based cladogram is a hypothesis that groups taxa according to shared differences in aligned DNA, RNA or amino-acid sequences.

Homologous sequences are aligned so each position can be compared. Candidate trees place the observed changes on branches, and parsimony selects the tree that explains the data with the smallest total number of sequence changes.

Procedure: align homologous sequences; record variable positions; use an outgroup where provided to infer ancestral states; propose alternative branching patterns; count the minimum changes required by each; select the most parsimonious supported tree.

If taxa B and C share two sequence states absent from A and the outgroup, a tree pairing B with C may require fewer independent changes than trees pairing either taxon with A.

Parsimony identifies the simplest explanation for the supplied data, not a guaranteed true history. Different genes or criteria can support a different hypothesis.

Constructing cladograms

HL only

Assessment in practice

1–3 marks
How it is assessed

This objective is assessed through essay response, structured response, commonly using Explain / State / Describe.

Command terms

Explain / State / Describe / Discuss / Outline

What earns marks

Build the answer around this relationship: Cladograms can be built from traits, DNA sequences, RNA sequences, or protein sequences.

Watch for

Choosing a cladogram from visual layout rather than shared trait or sequence evidence.

Representative question

Question 1

[Maximum number: 3]

Discuss the use of amino acid sequences of proteins as the basis for constructing cladograms.

Read a Cladogram by Branch Points

HL only

A cladogram represents relative evolutionary relationships: the root is the ancestral starting point, each node represents a hypothetical common ancestor, and terminal branches end at the taxa being compared.

Taxa whose branches meet at the most recent node are sister groups. An outgroup diverges outside the ingroup and can help identify which character states are ancestral.

Read a tree by tracing from each terminal branch back to the most recent shared node. Use node order to infer relative divergence, identify every descendant branch when naming a clade, and track labelled character changes along branches.

If B and C join at one node before their branch joins A, B and C are sister taxa and share a more recent common ancestor with each other than either shares with A.

Tip spacing and left-to-right order have no evolutionary meaning, and rotating branches around a node does not change the relationships. One modern species is not the ancestor of another tip.

Analysing cladograms

HL only

Assessment in practice

1–6 marks
How it is assessed

This objective is assessed through structured response, commonly using Discuss / Explain / Deduce.

Command terms

Discuss / Explain / Deduce / Outline / Identify

What earns marks

Build the answer around this relationship: The root is the common ancestor of all taxa shown in a cladogram.

Watch for

Reading terminal positions as closeness instead of using the most recent shared node.

Representative question

Question 1

[Maximum number: 2]

Outline what is meant by the "root" and "node" with reference to a cladogram.

Test a Classification against Independent Evidence

HL only

Cladistics tests whether a traditional taxonomic group corresponds to evolutionary relationships by comparing its membership with a tree built from independent evidence.

Traditional classifications often emphasized morphology, but similar traits can evolve independently. Conserved gene sequences can reveal that a familiar family is not one clade, prompting species to be transferred between families.

In the figwort-family case, chloroplast sequence comparisons produced clades that conflicted with the traditional morphology-based Scrophulariaceae. The classification was revised so named families more closely matched common ancestry.

When several gene sequences consistently place a plant outside its traditional family, researchers can reclassify it rather than preserving a grouping based on convergent flower form.

Students need the logic of testing and revision, not memorized details of every transferred plant. A new tree remains a testable hypothesis that can change with better sampling or evidence.

Testing classification correspondence

HL only

Assessment in practice

1 marks
How it is assessed

This objective is assessed through multiple choice.

What earns marks

Build the answer around this relationship: Cladistics can test whether traditional taxa reflect evolutionary ancestry.

Representative question

Question 1

[Maximum number: 1]

The figwort family is a large one consisting of many flowering plants that look similar. For what reason have some members of the family been reclassified into a new family?

A

Cladistic analysis shows the differences in flower structure to be fewer than the shared similarities.

B

DNA analysis shows the similarities in flower shape to be a product of convergent evolution.

C

DNA analysis shows some of the families to have suffered recent mutations in only one gene.

D

DNA analysis shows the similarities between the seed dispersal strategies to be a product of divergent evolution.

Three Domains Separate Deep Cellular Lineages

HL only

The three-domain system classifies cellular life as Bacteria (also called Eubacteria), Archaea and Eukarya, chiefly from comparisons of ribosomal RNA base sequences.

rRNA is present in all cellular organisms and changes gradually enough to compare deep lineages. Sequence evidence showed that organisms once grouped together as prokaryotes contain two profoundly different lineages, Bacteria and Archaea.

The extra rank above kingdoms was proposed in 1977. Supporting distinctions include rRNA sequences and differences in information-processing machinery, membrane lipids, cell walls, histone associations and introns.

An organism can resemble a bacterium in shape and lack a nucleus, yet its rRNA sequence and membrane chemistry can place it in Archaea.

The absence of a nucleus distinguishes both Bacteria and Archaea from eukaryotic cells but cannot distinguish those two prokaryotic domains from each other.

Three domains classification

HL only

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, multiple choice, commonly using State / Explain / Distinguish.

Command terms

State / Explain / Distinguish / Suggest

What earns marks

Build the answer around this relationship: The three domains are Archaea, Eubacteria, and Eukaryotes.

Watch for

Confusing domain with kingdom, phylum, class, or ecological role.

Representative question

Question 1

[Maximum number: 2]

Distinguish between the two domains of prokaryotes.

Read And Defend A Cladogram

HL only

A3.2 exam answers are strongest when they sound like evidence arguments. Classification organizes diversity, but fixed ranks and morphology can mislead. Evolutionary classification should match phylogeny using monophyletic clades supported by synapomorphies. Molecular clocks estimate divergence time from calibrated sequence differences. Cladograms are built from aligned sequence data and interpreted by nodes, not tip positions. Cladistics can reclassify old taxa, and rRNA evidence supports the three-domain system.

  • Classification should reveal relationships, not just names.
  • Fixed ranks and convergence can mislead.
  • Monophyletic clades include an ancestor and all descendants and are supported by synapomorphies.
  • Molecular clocks need calibration and can vary in rate.
  • Cladograms are built from aligned sequences using computer analysis and parsimony.
  • Read relatedness from most recent common ancestors, not tip positions.
  • Figwort and three-domain examples show molecular evidence changing classification.

Topic A4.1

A4.1 Evolution and speciation

Evolution and speciation explain how heritable variation, molecular evidence, selection, isolation, and chromosome change produce population divergence and new species over time.

36% of analysed papers 41 papers · 50 questions

Objectives in this topic

Evolution Changes Heritable Characteristics

Evolution is a change in heritable characteristics of populations across generations.

Mutation and recombination create variation, while selection, drift and gene flow change allele frequencies. Individuals do not evolve because a population-level frequency changes over time. This population-level definition is essential when separating evolution from an individual’s lifetime acclimation.

Trace the population process:

  • heritable variation
  • different survival or reproduction
  • changed allele frequencies
  • inheritance across generations

If a drought-resistant allele becomes more common after repeated dry years, the population has evolved; one plant becoming drought-resistant during its life has not.

Evolution is not progress toward perfection; it is change relative to a particular environment.

Evolution as change in heritable characteristics

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through essay response, commonly using Define / Explain / Outline.

Command terms

Define / Explain / Outline

What earns marks

Build the answer around this relationship: Evolution is cumulative change in heritable characteristics of a population across generations.

Watch for

Treating evolution as a change acquired by an individual during its lifetime rather than a heritable population change.

Representative question

Question 1

[Maximum number: 8]

Explain how the process of evolution occurs.

Sequences Reveal Common Ancestry

Similarity in DNA or protein sequences can provide evidence that organisms share a common ancestor.

Homologous genes retain inherited sequence features, while substitutions and insertions accumulate after lineages split. The strength of an inference depends on sequence choice, alignment, sampling and the possibility of gene transfer.

Use sequence evidence carefully:

  • compare homologous regions
  • align equivalent positions
  • inspect shared derived changes
  • report uncertainty and alternative histories

A conserved gene with fewer differences between species A and B than between A and C supports a closer relationship between A and B.

Sequence similarity supports ancestry; it does not prove that one modern species descended directly from another.

Evidence from sequences

Assessment in practice

1–4 marks
How it is assessed

This objective is assessed through essay response, commonly using Explain / Discuss / Identify.

Command terms

Explain / Discuss / Identify / Describe

What earns marks

Build the answer around this relationship: The universality of DNA and the genetic code supports common ancestry among living organisms.

Watch for

Equating sequence similarity with identical whole organisms rather than using it as evidence of recent common ancestry.

Representative question

Question 1

[Maximum number: 6]

Discuss how variations in proteins can indicate phylogeny and be used as an evolutionary clock.

Selective Breeding Demonstrates Heritable Variation

Artificial selection is evidence for evolution because humans repeatedly breed individuals with desired heritable traits, changing trait and allele frequencies across generations.

Domesticated animal breeds and crop varieties differ greatly from one another and from their original wild species. These changes can occur rapidly when strong selection acts on existing heritable variation.

A response requires variation in the trait, a heritable component, preferential reproduction of selected individuals and repeated selection. Correlated traits may also change because genes and traits are not always independent.

If farmers repeatedly propagate seeds from plants with a heritable high-yield trait, that trait can become more common over generations and the crop variety can diverge from its wild ancestor.

Selective breeding changes a population across generations; feeding one animal well can change its growth but is not inherited evolution. It also does not show that every trait is controlled by one gene.

Evidence from selective breeding

Assessment in practice

1 marks
How it is assessed

This objective is assessed through structured response, commonly using Outline.

Command terms

Outline

What earns marks

Build the answer around this relationship: Selective breeding is artificial selection for desired heritable traits.

Watch for

Calling selective breeding natural selection when the selecting agent is human choice.

Representative question

Question 1

[Maximum number: 3]

Outline the evidence for evolution provided by selective breeding.

Separate Homology From Convergence

A split visual. Left side compares vertebrate pentadactyl limbs with the same basic bone plan adapted for different functions such as grasping, flight, running, and swimming. Right side compares bat and insect wings to show similar function but different evolutionary origins.

Homologous and analogous structures answer different evolutionary questions. Homologous structures share a basic structural pattern and common ancestry, even when their functions differ. The pentadactyl limb in vertebrates has the same underlying arrangement of bones adapted for grasping, flight, running or swimming; it is evidence of divergent evolution.

Analogous structures have similar functions but different structural origins and ancestry. Bat wings and insect wings both support flight, but their underlying construction and evolutionary origins differ. They are evidence of convergent evolution: similar selection pressures produced similar functions independently. In an exam, compare structure and ancestry, not function alone.

Evidence from homologous structures

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using Describe / Outline.

Command terms

Describe / Outline

What earns marks

Build the answer around this relationship: Homologous structures share ancestral origin and underlying anatomy.

Watch for

Confusing homologous structures with analogous structures that share a function but not evolutionary origin.

Representative question

Question 1

[Maximum number: 4]

Describe the evidence for evolution from homologous structures.

Convergent evolution

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through essay response, commonly using Compare / Distinguish / State.

Command terms

Compare / Distinguish / State / Outline / Explain

What earns marks

Build the answer around this relationship: Convergent evolution produces similar adaptations in lineages with different evolutionary origins.

Watch for

Calling analogous structures homologous because they have the same function.

Representative question

Question 1

[Maximum number: 4]

Explain how analogous structures can evolve.

Trace Species Splitting from Isolation to Divergence

Gene flow reduction and divergence.

Speciation is the splitting of one pre-existing species into two or more species; it increases the total number of species, whereas extinction decreases it.

Reduced gene flow lets separated gene pools diverge. Mutation supplies variation, differential selection changes allele frequencies under different conditions, and drift can add chance divergence until reproductive isolation prevents fertile gene flow.

Geographic isolation can begin the process. The Congo River separated populations ancestral to bonobos and common chimpanzees; different conditions on either side supported differential selection and divergence.

If two isolated populations accumulate different mating traits and eventually cannot produce fertile offspring when reunited, one ancestral species has split into two.

Geographic separation alone is not speciation, and gradual evolutionary change within one continuing lineage does not increase species number. The defining outcome is reproductive isolation after splitting.

Speciation by splitting of pre-existing species

Assessment in practice

2–5 marks
How it is assessed

This objective is assessed through structured response, commonly using Discuss / Outline / Suggest.

Command terms

Discuss / Outline / Suggest / Explain / Describe

What earns marks

Build the answer around this relationship: Speciation forms new species by splitting a pre-existing species into diverging populations.

Watch for

Naming geographic separation without explaining gene-pool divergence or reproductive isolation.

Representative question

Question 1

[Maximum number: 5]

Describe the changes that occur in gene pools during speciation.

Reproductive isolation and differential selection

Assessment in practice

1–3 marks
How it is assessed

This objective is assessed through structured response, commonly using Identify / Analyse / State.

Command terms

Identify / Analyse / State / Describe / Outline / Distinguish / Explain

What earns marks

Build the answer around this relationship: Reproductive isolation reduces or prevents gene flow between populations.

Watch for

Listing a barrier but not connecting it to reduced gene flow.

Representative question

Question 1

[Maximum number: 7]

Explain how isolation leads to speciation.

SL Transfer: Evidence To Speciation

The core A4.1 answer moves from evidence to mechanism. Define evolution as heritable population change across generations. Use molecular universals and sequence differences, selective breeding, homology, and convergence as evidence for common ancestry and divergence. Then explain speciation as reduced gene flow followed by divergence of isolated gene pools through selection, mutation, and drift.

  • Evolution is cumulative change in heritable characteristics of a population.
  • Molecular evidence supports common ancestry and divergence.
  • Selective breeding shows heritable traits can change rapidly under selection.
  • Homology supports common ancestry; analogy/convergence shows similar selection pressures can mislead.
  • Speciation needs reduced gene flow and divergence of isolated gene pools.

Allopatric and Sympatric Speciation Differ by Geography

HL only

Allopatric speciation begins with a geographic barrier; sympatric speciation occurs while populations remain in the same geographic area. Both require reduced gene flow and eventual reproductive isolation.

In allopatry, physical separation stops or sharply reduces mating before differential selection and drift drive divergence. In sympatry, behavioural, temporal or ecological differences reduce mating within the shared area; chromosome changes can also isolate plant lineages.

Compare the routes by asking: Is there a geographic barrier? Which barrier reduces gene flow? What different selection pressures act? Is reproductive isolation established? Geographic, behavioural and temporal isolation can all contribute.

A river dividing a population is an allopatric starting point. Two populations breeding in different seasons in the same habitat can begin a sympatric route because temporal isolation reduces gene flow.

Sharing a location does not by itself demonstrate sympatric speciation, and physical separation does not by itself complete allopatric speciation; evidence of divergence and reproductive isolation is needed.

Sympatric vs. allopatric speciation

HL only

Assessment in practice

1–3 marks
How it is assessed

This objective is assessed through structured response, commonly using Outline / Compare / Distinguish.

Command terms

Outline / Compare / Distinguish

What earns marks

Build the answer around this relationship: Allopatric speciation occurs when populations are geographically separated.

Watch for

Defining both processes only as isolation without stating whether geography separates the populations.

Representative question

Question 1

[Maximum number: 3]

Compare allopatric speciation and sympatric speciation using the table below.

AllopatricSympatric

Adaptive Radiation Fills Many Ecological Roles

HL only

Adaptive radiation is rapid diversification of one ancestral lineage into multiple species adapted to different ecological niches.

When competitors are absent or new habitats become available, populations experience different selection pressures. Divergence in feeding, timing or habitat use can reduce gene flow and produce a cluster of related species.

Look for the combination:

  • one ancestral lineage
  • several ecological opportunities
  • divergent traits
  • reproductive separation

Finches colonizing islands may evolve different beaks for seeds, insects or nectar, with mating patterns that maintain the new lineages.

Many species in one area are not automatically an adaptive radiation; shared ancestry and niche divergence are required.

Adaptive radiation

HL only

Assessment in practice

3 marks
How it is assessed

This objective is assessed through structured response, commonly using Outline.

Command terms

Outline

What earns marks

Build the answer around this relationship: Adaptive radiation produces multiple related species from one ancestral species.

Watch for

Describing adaptive radiation as unrelated species becoming similar rather than related lineages diverging.

Representative question

Question 1

[Maximum number: 5]

The human hand is an example of adaptive radiation. Outline adaptive radiation.

Reproductive barriers and polyploidy

HL only
A compact two-part visual: prezygotic versus postzygotic barrier examples on one side, and an autopolyploid/allopolyploid chromosome-doubling pathway with Persicaria on the other.

Reproductive barriers prevent gene flow and can act before or after fertilization. Prezygotic barriers prevent mating or fertilization, so no zygote forms: geographic separation, different habitats, different breeding times and different courtship behaviours are examples. Postzygotic barriers act after fertilization: the hybrid may be non-viable or may survive but be infertile, as in a mule.

Polyploidy is more than two complete chromosome sets and can produce abrupt sympatric speciation in plants. Autopolyploidy arises when chromosome number doubles within one species, often after meiotic failure; a fertile tetraploid can no longer produce fertile offspring with the original diploid population. Allopolyploidy begins with hybridization between two species followed by chromosome doubling, which can restore pairing and fertility in the hybrid.

If the new polyploid is viable and fertile but reproductively isolated from the parent population, it is a new species. Knotweeds/smartweeds in the genus Persicaria provide the named example. The scoring chain is chromosome change → incompatible meiosis with parent → reproductive isolation → speciation.

Abrupt speciation in plants

HL only

Assessment in practice

1–5 marks
How it is assessed

This objective is assessed through structured response, commonly using Explain / Describe / Discuss.

Command terms

Explain / Describe / Discuss

What earns marks

Build the answer around this relationship: Polyploid organisms have more than two complete sets of chromosomes.

Watch for

Confusing polyploidy with aneuploidy involving one extra chromosome rather than whole chromosome sets.

Representative question

Question 1

[Maximum number: 7]

Research suggests that many living plant species are polyploid. Explain how polyploidy occurs and, using a named example, how polyploidy can lead to speciation.

Routes, Niches, And Barriers

HL only

HL speciation questions usually ask you to choose the right layer. Route layer: allopatric means geographic isolation; sympatric means no spatial separation. Niche layer: adaptive radiation produces many related species from one ancestor as they occupy different niches, as in Darwin’s finches. Barrier layer: prezygotic barriers act before fertilization, postzygotic barriers act after hybrid formation. Chromosome layer: plant polyploidy can abruptly create reproductive isolation and fertile new lineages.

  • Allopatric speciation involves geographic isolation.
  • Sympatric speciation occurs without spatial separation.
  • Adaptive radiation produces many related species from one ancestor in different niches.
  • Prezygotic barriers prevent mating/fertilization; postzygotic barriers include infertile hybrids.
  • Polyploidy can cause abrupt plant speciation by chromosome-number change.

Topic A4.2

A4.2 Conservation of biodiversity

Conservation of biodiversity connects biodiversity measurement, human-driven losses, ecosystem evidence, and targeted conservation strategies for protecting species, communities, and evolutionary history.

14% of analysed papers 16 papers · 25 questions

Objectives in this topic

Biodiversity Has Several Levels

Biodiversity is the variety of life in all its forms, levels and combinations. It includes genetic diversity within populations, species diversity in communities and ecosystem diversity across habitats and processes.

Species diversity depends on both richness (the number of species) and evenness (how evenly individuals are distributed). A community with many species can still have low diversity if nearly all individuals belong to one species.

D=N(N1)/Σn(n1),whereNisthetotalnumberoforganismssampledandnisthenumberbelongingtoeachspecies;alargerDindicatesgreaterdiversityforcomparablesamples.D = N(N - 1) / Σn(n - 1), where N is the total number of organisms sampled and n is the number belonging to each species; a larger D indicates greater diversity for comparable samples.

Two fields may have the same richness, but the field whose individuals are distributed more evenly among species has the higher Simpson's reciprocal index and greater measured species diversity.

Species count alone does not measure genetic or ecosystem diversity. Compare index values only when sampling method and effort are sufficiently comparable.

Biodiversity definition

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, commonly using State / Discuss / Calculate.

Command terms

State / Discuss / Calculate / Analyse / Compare / Evaluate / Distinguish / Suggest

What earns marks

Build the answer around this relationship: Biodiversity includes ecosystem diversity, species diversity and genetic diversity.

Watch for

Equating richness with overall biodiversity when evenness also affects diversity.

Representative question

Question 1

[Maximum number: 4]

Entire communities need to be conserved in order to preserve biodiversity. Suggest different quantitative methods to measure changes in biodiversity in a community over time.

Biodiversity Changes through Time

Millions of living species have been discovered, named and described, and many more remain undiscovered. Fossil evidence suggests that more species may be alive now than at any earlier time in Earth's history.

Present-day surveys sample living organisms directly, whereas past biodiversity is reconstructed from fossils and dated rock layers. Fossilization is rare and uneven, so soft-bodied, small or poorly sampled organisms are underrepresented.

A fair comparison states the time interval, separates number of species from abundance, considers changes in taxonomic definitions and acknowledges unequal sampling. Speciation raises diversity through time; extinction lowers it.

A diverse fossil assemblage can establish that many lineages existed in one period, but missing fossils cannot establish that no additional species were present.

The fossil record supports a comparison but is incomplete. 'Currently more species' is an evidence-based inference, not an exact census of all past and present species.

Trace Human Pressure to Species Extinction

Anthropogenic extinction occurs when human activity causes the last individuals of a species to die. The current rapid, widespread losses are described as a sixth mass extinction.

Direct killing and habitat alteration reduce abundance; small populations then become more vulnerable to reproductive failure, inbreeding and chance events. Extinction is global, whereas disappearance from one area is extirpation.

Case Human pressure Evidence-based lesson
North Island giant moa (Dinornis novaezealandiae) Overhunting after human arrival Large terrestrial species with slow replacement can be removed faster than populations recover
Caribbean monk seal (Neomonachus tropicalis) Human exploitation and other human pressures on a marine species Marine range does not protect a species from sustained human-caused mortality

For a third case from a region familiar to the learner, record the named species, verified human cause, population pathway and evidence source; do not infer global extinction from a local absence.

A plausible human pressure is not enough: the case study must connect that pressure to population decline and distinguish extinction from extirpation.

Anthropogenic species extinction

Assessment in practice

1 marks
How it is assessed

This objective is assessed through multiple choice, commonly using Identify.

Command terms

Identify

What earns marks

Build the answer around this relationship: Anthropogenic extinction is extinction caused by human activities.

Representative question

Question 1

[Maximum number: 1]

The North Island giant moa (Dinornis novaezealandiae) went extinct some time between the arrival of humans in New Zealand and the 1800s.

What do scientists believe to be the cause of this extinction?

A

Deforestation

B

New diseases

C

Competition with other megafauna

D

Overhunting

Explain Ecosystem Loss through Causal Chains

Ecosystem loss is an anthropogenic reduction in habitat area, structure, species interactions or ecological function, caused directly by conversion or indirectly by environmental change.

Ecosystem Human drivers Causal chain
Mixed dipterocarp forest, Borneo Logging and conversion to oil-palm plantations Tree removal and land conversion → fragmentation and altered microclimate → habitat and species loss
Great Barrier Reef Greenhouse-gas-driven warming and acidification, pollution and fishing pressure Heat stress/bleaching and reduced calcification plus local stress → coral loss → reduced reef habitat and function

Separate direct area loss from degradation of what remains. Fragmentation increases edge effects and isolates populations; persistent pollution, invasive species or climate stress can prevent functional recovery.

Satellite images showing declining Borneo forest cover become stronger causal evidence when land-use records independently show logging and oil-palm expansion in the same places and times.

Protecting a small remnant does not by itself restore an ecosystem if connectivity, species interactions or the original abiotic conditions remain lost.

Ecosystem loss causes

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through multiple choice, structured response, commonly using Outline / Explain / Describe.

Command terms

Outline / Explain / Describe / Suggest

What earns marks

Build the answer around this relationship: Deforestation reduces biodiversity by removing habitat and essential resources.

Watch for

Naming deforestation without explaining loss of habitat, food, shelter or breeding sites.

Representative question

Question 1

[Maximum number: 1]

The satellite images show changes in the area covered by forest, much of which is mixed dipterocarp forest, on the island of Borneo in Southeast Asia.

Which human activities are most likely to have caused the changes shown in the map?

A

Logging and palm oil plantation

B

Logging and rewilding

C

Mining and afforestation

D

Afforestation and palm oil plantation

Evaluate Evidence for a Biodiversity Crisis

Evidence for a biodiversity crisis comes from repeated, comparable surveys showing declines in species richness, evenness, abundance, ranges, genetic diversity or ecosystem integrity across many habitats.

A single survey provides a snapshot; repeated standardized sampling reveals change. IPBES assessments combine many published datasets and lines of evidence, so their broad conclusions are stronger than one isolated observation.

Check the baseline, time span, sampling effort, method, geographic and taxonomic coverage, uncertainty and alternative explanations. Richness and evenness—and, where appropriate, Simpson's reciprocal index—allow communities to be compared through time.

Citizen scientists can supply frequent observations over a wide area, but training, validation, repeated sites and correction for changing observer effort are needed before a decline is inferred.

Peer review permits methods and analysis to be checked but does not make a dataset flawless. A crisis claim should report scale and uncertainty rather than imply that every species declines equally.

The Biodiversity Crisis Has Interacting Drivers

Human population growth is an overarching driver of the biodiversity crisis because it increases demand for food, housing, land, energy and materials.

Demand is translated into habitat loss through urbanization, deforestation, agriculture and mining; direct mortality through hunting, fishing and other overexploitation; and environmental stress through pollution and climate change.

Global transport spreads pests, diseases and invasive alien species. These drivers interact: fragmented native populations may be less able to withstand pollution, warming, a new pathogen or an introduced competitor.

Water hyacinth can spread rapidly as an invasive alien plant, block waterways and reduce light or oxygen available to native aquatic organisms.

Do not stop at a list of threats. Link each human activity to the mechanism that changes survival, reproduction, habitat or species interactions.

Causes of biodiversity crisis

Assessment in practice

1–3 marks
How it is assessed

This objective is assessed through structured response, commonly using Outline / State.

Command terms

Outline / State

What earns marks

Build the answer around this relationship: Urbanization and agricultural land clearance reduce habitat and fragment ecosystems.

Representative question

Question 1

[Maximum number: 3]

List human actions that could threaten populations of insect pollinators such as bees.

Conservation Matches the Threat to the Scale

No single conservation method is sufficient because species, ecosystems and threats differ. Effective plans combine approaches and monitor whether populations and ecological functions recover.

Approach Main role Examples
In situ Protect species in natural habitats and retain interactions/evolution Nature reserves, corridors, anti-poaching and active habitat management
Ecosystem recovery Restore lost processes and habitat Rewilding and reclamation of degraded ecosystems
Ex situ Protect organisms or genetic material outside the threatened habitat Zoos, captive breeding, botanic gardens, seed banks and tissue/germ-plasm banks

In-situ conservation retains natural selection and food webs but may not control an immediate threat. Ex-situ programmes can protect a very small population, yet require genetic management and a safe habitat before reintroduction.

A threatened amphibian may need a protected and restored wetland, disease control, connected habitat and a carefully managed captive-breeding population rather than one isolated action.

A reserve without enforcement, connectivity or threat removal may protect only a map boundary; captive breeding without genetic management and a viable release site cannot restore a wild population.

Conservation approaches

Assessment in practice

2–4 marks
How it is assessed

This objective is assessed through essay response, structured response, commonly using Discuss / Outline / Distinguish.

Command terms

Discuss / Outline / Distinguish / Explain / Suggest

What earns marks

Build the answer around this relationship: In situ conservation protects species within their natural habitats and communities.

Watch for

Defining in situ and ex situ without linking each approach to its conservation advantages and limits.

Representative question

Question 1

[Maximum number: 4]

Discuss in situ and ex situ conservation of endangered species.

EDGE Prioritizes Unique and Threatened Species

The EDGE of Existence approach prioritizes species that are both evolutionarily distinct and globally endangered.

Evolutionary distinctiveness estimates how much unique evolutionary history a species represents; global-endangerment status estimates extinction risk. Combining them directs limited conservation resources toward irreplaceable branches and urgent threats. Use the evidence scale and context before drawing a broad conclusion.

Interpret an EDGE priority:

  • distinct lineage contribution
  • evidence of high threat
  • feasible conservation action
  • local communities and governance

Protecting a highly distinct, critically endangered mammal can preserve more unique evolutionary history than protecting a common close relative.

EDGE ranking does not mean other species have no value; it is a prioritization tool under limited resources.

EDGE of Existence programme

Assessment in practice

1–2 marks
How it is assessed

This objective is assessed through structured response, multiple choice, commonly using Outline / Describe.

Command terms

Outline / Describe

What earns marks

Build the answer around this relationship: EDGE species are both evolutionarily distinct and globally endangered.

Watch for

Explaining EDGE only by expanding the initials without linking distinctiveness to extinction risk.

Representative question

Question 1

[Maximum number: 2]

Outline the importance of the EDGE of Existence programme.

Build A Conservation Argument

A strong conservation answer follows a chain: define biodiversity, measure evidence of decline, identify human drivers, then justify conservation action. Biodiversity includes ecosystem, species, and genetic diversity; species diversity uses richness and evenness. Evidence comes from estimates, fossils, repeated surveys, IPBES reports, and indices. Drivers include extinction pressure, ecosystem conversion, population-driven resource demand, pollution, and invasive species. Responses include in situ, ex situ, and EDGE prioritization.

  • Define biodiversity across ecosystem, species, and genetic levels.
  • Measure species diversity using richness, evenness, and Simpson’s reciprocal index.
  • Use evidence cautiously: modern estimates, fossil gaps, repeated surveys, IPBES reports, and reliability checks.
  • Explain drivers using named examples: moa, Caribbean monk seal, Borneo, Great Barrier Reef, lionfish, water hyacinth.
  • Choose conservation responses: in situ, ex situ, and EDGE priorities.