1 correct genotype for person 3, i.e. (X)A(X)a;
2 correct genotype for person 4, i.e. XAY;
3 correct gametes from the parental genotypes ;
4 correct offspring genotypes from their gametes / parental genotypes (in any order) ;
5 correct offspring correct probability ;
MP3 ecf from MP1 and MP2 MP4 ecf from MP3
MP5 ecf from their offspring genotype
expected answer:
genotype (person 3) XAXa×( person 4) XAY
gametes XA,Xa+XA,Y
offspring genotypes XAXA,XAXa,XAY,XaY
offspring phenotypes female with normal colour vision female with normal colour vision male with normal colour vision male with colour blindness)
probability 0.25 / 25% / 1 in 4 / 41