Question 11(c)[Maximum number: 4]The table shows some values for y=x3−2x+3y=x^{3}-2 x+3y=x3−2x+3.Where appropriate, values of y are given correct to 2 decimal places.By drawing a suitable straight line on the grid, solve the equation x3−2.5x+1=0x^3-2.5x+1=0x3−2.5x+1=0.x= or x= or x=Show AnswerAdd to Test