CAIE IGCSE Mathematics Extended Geometry Question Bank
Practise geometric language, constructions, bearings, similarity, symmetry, angle properties, polygons and circle theorems across CAIE IGCSE.
- Syllabus
- 2028–2030
- Topic
- 4
- Level
- Extended
Practise geometric language, constructions, bearings, similarity, symmetry, angle properties, polygons and circle theorems across CAIE IGCSE.
The scale drawing shows two sides, AB and BC, of a field. The scale is 5 centimetres represents 200 metres.

Scale: 5 cm to 200 m
Measure angle ABC.
Angle A B C=
118
1
A bronze statue is 4.5 m high and has a mass of 195200 kg .
The density of bronze is 8000 kg/m3.
The volume of a mathematically similar model of the statue is 0.385 m3.
Calculate the height of the model.
[Density = Mass ÷ Volume ]
1.13 or 1.128 to 1.129
M4 for 4.531952000.385×8000 oe, or 31952004.53×0.385×8000 oe
or M3 for 3their 24.40.385 or 3195200their 3080, or their 24.40.385=4.53l3 oe
or M2 for 0.385their 24.4 or their 24.40.385 oe, or B2 for 24.4 or 3080 seen
or M1 for 195200÷8000 or for 0.385×8000
A lake has an area of 3 km2.
On a map the area of the lake is 18.75 cm2.
Find the scale of the map in the form 1: n.
40000
B2 for 1 cm to 0.4 km or 2.5 cm to 1 km or 1600000000
or M2 for 18.753×10k oe where k>5
or M1 for area conversion evidence listed in markscheme

NOT TO SCALE
In the diagram, S lies on PQ and T lies on PR.
ST is parallel to QR.
Explain why triangle PQR is mathematically similar to triangle PST.
Give a geometrical reason for each statement you make.
Three correct pairs with correct reasons
∠PQR=∠PST and corresponding angles
∠PRQ=∠PTS and corresponding angles
∠QPR=∠TPS and common angle
OR
Two correct pairs with correct reasons and correct similarity condition, e.g. AAA
B2 for two correct pairs with correct reasons
or B1 for one correct pair with correct reason
ST=3 cm,QR=9 cm and PS=5 cm.
Work out PQ.
15
M1 for 93=PQ5 oe or better
The area of triangle PST is 2k cm2.
Find, in terms of k, the area of quadrilateral QRTS. cm2
16k
M1 for 32 or (31)2 oe
The diagram shows three lines meeting at a point.
The ratio a: b: c=3: 4: 5.
Find the value of c.

NOT TO SCALE
150
M1 for 3+4+5k×p, where p=1,3,4 or 5, or 125 oe
B1 for 360 used
A regular pentagon has an exterior angle, d.
A regular hexagon has an interior angle, h.
Find the fraction hd.
Give your answer in its simplest form.
53 cao nfww
B3 for 12072, or B2 for d=72 or h=120, or M1 for 360÷5 oe or 180−(360÷6) oe
NOT TO SCALE
A, B and C are points on the circle, centre O.
DE is a tangent to the circle at C.
AC=10 cm, AB=9.5 cm and BC=7.7 cm.
Find
angle AOC
140.4
angle ACD.
70.2
FT 90−their (b)(ii)
The interior angle of a regular polygon with n sides is 150∘.
Calculate the value of n.
12
M1 for 150=n(n−2)×180 or 180−150360 oe.

NOT TO SCALE
A, B, C and D are points on the circle, centre O.
M is the midpoint of AB and N is the midpoint of CD.
O M=O N
Explain, giving reasons, why triangle OAB is congruent to triangle OCD.
OA=OB=OC=OD
Radii
AB=CD
Chords equidistant from the centre are equal.
SSS implies congruent.