x2−6x+8[=0]
or y2−6y+5[=0]
M2
M1 for x2−4x+5=2x−3
or y=(2y+3)2−4(2y+3)+5(x-4)(x-2)[=0]
or (y-1)(y-5)[=0]
OR quadratic formula method
M1 FT their 3-term quadratic but not if x2−4x+5[=0][x=]2, [y=]1[x=]4, [y=]5
B2
B1 for one correct pair or two correct x-values or two correct y-values
If B0 scored and at least 2 method marks scored, SC1 for correct substitution of both of their values.