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A-Level CAIE Chemistry AS2.4 Reacting masses and volumes (of solutions and gases)Question Bank

[Maximum number: 1]

Sample X is added to water and made up to a total volume of 200 cm3200 \mathrm{~cm}^{3}. This gives a solution of 0.100 moldm3HCl0.100 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{HCl}.

What is X ?

A

10 cm310 \mathrm{~cm}^{3} of 1.00 moldm3HCl1.00 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{HCl}

B

30 cm330 \mathrm{~cm}^{3} of 0.90 moldm3HCl0.90 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{HCl}

C

50 cm350 \mathrm{~cm}^{3} of 0.40 moldm3HCl0.40 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{HCl}

D

100 cm3100 \mathrm{~cm}^{3} of 0.30 moldm3HCl0.30 \mathrm{~mol} \mathrm{dm}^{-3} \mathrm{HCl}

[Maximum number: 1]

Which contains the largest number of hydrogen atoms?

A

0.10 mol of pentane

B

0.20 mol of but-2-ene

C

1.00 mol of hydrogen molecules

D

6.02×10236.02 \times 10^{23} hydrogen atoms

[Maximum number: 3]

The elements in Group 17 are known as the halogens.

(a)

The concentration of NaClO in bleach S is xgdm3x \mathrm{gdm}^{-3}.

NaClO reacts with H2O2(aq)\mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{aq}) as shown.

H2O2(aq)+NaClO(aq)H2O(l)+NaCl(aq)+O2( g)\mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{aq})+\mathrm{NaClO}(\mathrm{aq}) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+\mathrm{NaCl}(\mathrm{aq})+\mathrm{O}_{2}(\mathrm{~g})

A 5.00 cm35.00 \mathrm{~cm}^{3} sample of S completely reacts with H2O2(aq)\mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{aq}). The volume of O2( g)\mathrm{O}_{2}(\mathrm{~g}) produced is 24.0 cm324.0 \mathrm{~cm}^{3} under room conditions.

Assume that only the NaClO in S reacts with H2O2(aq)\mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{aq}).
Calculate x. Show your working.

x=

gdm3\mathrm{g} \mathrm{dm}^{-3}

[ 3 ]
[Maximum number: 1]

In the Periodic Table, the p block contains elements whose outer electrons are found in the p subshell.

(a)

Sulfur-containing compounds, such as C2H5SH\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{SH}, are found in fossil fuels, and produce SO2\mathrm{SO}_{2} when they are burned.

[ 1 ]
(i)

Write the equation to show the complete combustion of C2H5SH\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{SH}.

[ 1 ]
[Maximum number: 4]

Iron pyrite, FeS2\mathrm{FeS}_{2}, has a yellow colour that makes it look like gold metal. The compound contains the ions Fe2+\mathrm{Fe}^{2+} and S22\mathrm{S}_{2}{ }^{2-}.

(a)

Iron pyrite is often called fool's gold because of its appearance. Impure samples of iron pyrite often contain a small amount of gold.

The gold can be obtained from impure iron pyrite. The impure iron pyrite is roasted in oxygen, to produce iron(III) oxide and sulfur dioxide. Gold does not react with oxygen.

[ 4 ]
(i)

A sample of impure iron pyrite was roasted in oxygen. The composition of the mixture of solid products is shown.

Table

Calculate the mass of FeS2\mathrm{FeS}_{2} present in the sample of impure iron pyrite.
Assume that all the FeS2\mathrm{FeS}_{2} was converted to Fe2O3\mathrm{Fe}_{2} \mathrm{O}_{3} during the roasting process.
( Mr:FeS2M_{r}: \mathrm{FeS}_{2}, 120.0; Fe2O3\mathrm{Fe}_{2} \mathrm{O}_{3}, 159.6)

 mass of FeS2=\text { mass of } \mathrm{FeS}_{2}=
[ 3 ]
(ii)

Use your answer to (iii) to calculate the percentage by mass of gold in this sample of impure iron pyrite. Assume that gold is the only impurity in this sample of impure iron pyrite.

Give your answer to two significant figures.
(If you were unable to calculate an answer to (iii), use 55.00 g as the mass of FeS2\mathrm{FeS}_{2} in this calculation. This is not the correct answer.)
percentage by mass of gold = \%

[ 1 ]
[Maximum number: 2]

Combustion data can be used to calculate the empirical formula, molecular formula and relative molecular mass of many organic compounds. Combustion data cannot distinguish between different structural isomers.

(a)

P is a hydrocarbon, CxHy\mathrm{C}_{x} \mathrm{H}_{y^{\prime}}. A gaseous sample of P occupied a volume of 25 cm325 \mathrm{~cm}^{3} at 37C37^{\circ} \mathrm{C} and 100 kPa .

The sample was completely burned in 200 cm3200 \mathrm{~cm}^{3} of oxygen (an excess).
The final volume, measured under the same conditions as the gaseous sample (so that the water produced is liquid and its volume can be ignored), was 150 cm3150 \mathrm{~cm}^{3}.

Treating the remaining gaseous mixture with concentrated alkali, to absorb carbon dioxide, decreased the volume to 50 cm350 \mathrm{~cm}^{3}.

The equation for the complete combustion of P can be represented as shown.

CxHy+(x+y4)O2xCO2+y2H2O\mathrm{C}_{x} \mathrm{H}_{y}+\left(x+\frac{y}{4}\right) \mathrm{O}_{2} \rightarrow x \mathrm{CO}_{2}+\frac{y}{2} \mathrm{H}_{2} \mathrm{O}
[ 2 ]
(i)

Use the data given to calculate the value of x.

x=
[ 1 ]
(ii)

Use the data given to calculate the value of (x+y4)\left(x+\frac{y}{4}\right).

(x+y4)=\left(x+\frac{y}{4}\right)=

If you were unable to calculate values in (b)(i) and (b)(ii) then use the data in this box for the remaining parts of this question. These are not the correct values.

x=6(x+y4)=9x=6 \quad\left(x+\frac{y}{4}\right)=9
[ 1 ]
[Maximum number: 5]

A0.17 g sample of a Group 14 chloride, XCl4\mathrm{XCl}_{4}, reacted with water to produce an oxide, XO2\mathrm{XO}_{2}, and HCl.
equation 1

XCl4( s)+2H2O(l)XO2( s)+4HCl(aq)\mathrm{XCl}_{4}(\mathrm{~s})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{XO}_{2}(\mathrm{~s})+4 \mathrm{HCl}(\mathrm{aq})

The HC lproduced was absorbed in 100 cm3100 \mathrm{~cm}^{3} of 0.10 moldm30.10 \mathrm{~mol} \mathrm{dm}^{-3} sodium hydroxide solution (an excess).
In a titration, the unreacted sodium hydroxide solution required 30.0 cm330.0 \mathrm{~cm}^{3} of 0.20 moldm30.20 \mathrm{~mol} \mathrm{dm}^{-3} hydrochloric acid for complete neutralisation.

(a)

Calculate the amount, in moles, of hydrochloric acid used in the titration to neutralise the unreacted sodium hydroxide solution.
amount = mol

[ 1 ]
(b)

Calculate the amount, in moles, of sodium hydroxide neutralised in the titration.
amount = mol

[ 1 ]
(c)

Calculate the amount, in moles, of sodium hydroxide that reacted with the HCl produced by the reaction in equation 1 .
amount = mol

[ 1 ]
(d)

Calculate the amount, in moles, of HCl produced by the reaction in equation 1.
amount = mol

[ 1 ]
(e)

Calculate the amount, in moles, of XCl4\mathrm{XCl}_{4} in the original 0.17 g sample.

amount =mol [1]
[ 1 ]
[Maximum number: 2]

An experiment was carried out to determine the percentage of iron in a sample of iron wire.

(a)

A3.35 g piece of the wire was reacted with dilute sulfuric acid, in the absence of air, so that all of the iron atoms were converted to iron(II) ions. The resulting solution was made up to 250 cm3250 \mathrm{~cm}^{3}.

[ 2 ]
(i)

Calculate the amount, in moles, of dichromate(VI) ions used in the titration.

amount =mol
(ii)

Calculate the amount, in moles, of iron in the 3.35 g piece of wire.

amount =mol [1]
[ 1 ]
(iii)

Calculate the mass of iron in the 3.35 g piece of wire.

mass =g
(iv)

Calculate the percentage of iron in the iron wire.

percentage =% [1]
[ 1 ]
[Maximum number: 3]

Neon is a noble gas.

(a)

A mixture of neon and argon has a mass of 0.275 g . The mixture was placed in a gas syringe at a temperature of 25C25^{\circ} \mathrm{C} and a pressure of 100 kPa . Under these conditions the mixture was found to occupy a volume of 200 cm3200 \mathrm{~cm}^{3}.

[ 3 ]
(i)

Calculate the average MrM_{\mathrm{r}} of the mixture.
average Mr=M_{\mathrm{r}}=

[ 2 ]
(ii)

Use your answer to (i) to calculate the percentage of neon in the mixture. Give your answer to three significant figures.
percentage of neon = \%

[ 1 ]
(a)

10 cm310 \mathrm{~cm}^{3} of a gaseous hydrocarbon, CxHy\mathrm{C}_{x} \mathrm{H}_{y}, was reacted with 100 cm3100 \mathrm{~cm}^{3} of oxygen gas, an excess. The final volume of the gaseous mixture was 95 cm395 \mathrm{~cm}^{3}.

This gaseous mixture was treated with concentrated, aqueous sodium hydroxide to absorb the carbon dioxide present. This reduced the gas volume to 75 cm375 \mathrm{~cm}^{3}.

All gas volumes were measured at 298 K and 100 kPa .

[ 6 ]
(i)

Calculate the volume of carbon dioxide produced by the combustion of the hydrocarbon.

 volume of CO2 produced =.cm3\text { volume of } \mathrm{CO}_{2} \text { produced }=\ldots \ldots \ldots \ldots \ldots \ldots . \mathrm{cm}^{3}
[ 1 ]
(ii)

Calculate the volume of oxygen used up in the reaction with the hydrocarbon.

 volume of O2 used =..cm3\text { volume of } \mathrm{O}_{2} \text { used }=\ldots \ldots \ldots \ldots \ldots \ldots . . \mathrm{cm}^{3}
[ 1 ]
(iii)

Use your answers to (b)(ii) and (b)(iii), together with the initial volume of hydrocarbon, to balance the equation below.

.CxHy+.O2.CO2+zH2O\ldots \ldots \ldots \ldots . \mathrm{C}_{x} \mathrm{H}_{y}+\ldots \ldots \ldots \ldots . \mathrm{O}_{2} \rightarrow \ldots \ldots \ldots \ldots . \mathrm{CO}_{2}+z \mathrm{H}_{2} \mathrm{O}
[ 1 ]
(iv)

Deduce the values of x, y and z in the equation in (iv).
x=
y=
z=

[ 3 ]
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