CAIE A-Level Chemistry AS 11.3 Some Reactions of the Halide Ions Questions
Practise halide reducing-strength trends, silver-ion tests and reactions with concentrated sulfuric acid.
- Syllabus
- 2028–2030
- Course
- Chemistry 9701
- Level
- AS
Practise halide reducing-strength trends, silver-ion tests and reactions with concentrated sulfuric acid.
The solids sodium chloride and sodium iodide both react with concentrated sulfuric acid at room temperature.
With NaCl , the products are NaHSO4 and HCl .
With NaI , the products are NaHSO4,HI,I2,SO2,H2O,S and H2 S.
What is the explanation for this difference in products?
Chloride ions will displace iodine from the solution.
Hydrogen chloride is more volatile than hydrogen iodide.
lodide ions are better reducing agents than chloride ions.
Sulfuric acid is able to act as a dehydrating agent with NaI .
C
Hydrogen halides are compounds formed when halogens (Group 17 elements) react with hydrogen. The bond polarity of the hydrogen halides decreases from HF to HI.
Some relevant data are shown in the table.
The equation for the preparation of hydrogen chloride using concentrated sulfuric acid is shown.
Explain why the reaction of concentrated sulfuric acid and sodium iodide is not suitable for the preparation of hydrogen iodide.
H2SO4 is (too strong) an oxidising agent
I2 would be formed instead
Chlorine is bubbled through a cylinder containing aqueous sodium iodide and an immiscible layer of hexane.
As the bubbles pass through the cylinder, what is observed in the lower and upper layers?
lower aqueous layer
upper hexane layer
colourless solution becomes brown
colourless liquid becomes coloured
colourless solution becomes brown
colourless liquid is unchanged
brown solution becomes colourless
colourless liquid becomes coloured
brown solution becomes colourless
colourless liquid is unchanged
A