CAIE A-Level Chemistry 1.4 Ionisation Energy
Practise definitions, gas-phase equations, periodic trends and successive-ionisation data using nuclear attraction and shielding.
- Syllabus
- 2028–2030
- Course
- Chemistry 9701
- Level
- AS
Practise definitions, gas-phase equations, periodic trends and successive-ionisation data using nuclear attraction and shielding.
Define first ionisation energy.
energy required
- when one electron is removed
- from each atom in one mole of
- gaseous atoms
two or three points for one mark, four points for two marks
Successive ionisation energies for element A are shown in Table 1.1.

Table 1.1
Use Table 1.1 to deduce the group of the Periodic Table that A belongs to. Explain your answer. Group
Group VI / 16 AND large increase (in IE) after 6th
Across Period 3 there is a general trend for first ionisation energies to increase due to the increase in attraction between the nucleus and the outer electron.
Explain why the first ionisation energy of sulfur is less than the first ionisation energy of phosphorus.
M1 reference to spin pair repulsion in (3)p orbital (in S)
OR due to repulsion of two electrons in a (3)p orbital (in S)
M2 outweighs increased nuclear charge (in S)
In an Al2+ ion the nuclear attraction for the outer electron is stronger than in an atom of Na .
Compare the electronic structures of Al2+ and an atom of Na and explain why the third ionisation energy of aluminium is greater than the first ionisation energy of sodium.
M1 similarity in electronic structure / shielding of Al2+ and Na both remove electron from (3)s 1 / single electron in (3)s (sub-level / orbital)
OR Al2+ and Na have same electronic configuration
OR shielding (of outer electron) is the same
M2 greater nuclear charge / number of protons
All(2+) has greater nuclear charge
OR 13p compared to 11p
Nitrogen and phosphorus are elements in Group 15 of the Periodic Table.
Fig. 3.1 shows a sketch of some of the ionisation energies of phosphorus, P.

Fig. 3.1
Construct an equation to represent the third ionisation energy of P.
P2+(g)→P3+(g)+e(−)
Complete the graph in Fig. 3.1 to show the third to sixth ionisation energies of P.
general increase
increase in IE between IE5 and IE6 is noticeably the largest increase between IEs shown
The Periodic Table is arranged such that the properties of the elements show a number of trends.
A plot of the first ionisation energies for the first 18 elements is shown.

Explain why the values show a general increase from atomic number 11 to 18 .
Increasing nuclear attraction
Increasing nuclear charge / number of protons AND constant/similar shielding / same shell
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1
Explain the decreases in first ionisation energies between
- atomic numbers 12 and 13,
- atomic numbers 15 and 16 .
From 12 / Mg to 13 / Al :
(Outer) electron in ' 13 ' / Al in (3)p (whereas outer electron in ' 12 ' / Mg in (3)s) ( 3 p= ) higher energy level/more shielded
From 15/P to 16 / S electron repulsion
('16'/S has a) pair of electrons in a (3)p orbital/a (3)p orbital is full ORA
1
1
1
1
Suggest an explanation for the trend in the first ionisation energies of the elements with atomic numbers 2, 10 and 18.
(decreasing IE down Group 0) due to decreasing nuclear attraction
increasing shielding/increasing number of shells/energy levels/increasing distance of (outer) electrons (from nucleus)
1
1