CourseCourseConceptConceptDocumentDocument

CAIE A-Level Chemistry AS 1.3.5 Electronic Configurations Questions

Practise explaining electron configurations for atoms and ions by applying shell, subshell and orbital notation, ionisation principles, and electron-count calculations.

Syllabus
2028–2030
Course
Chemistry 9701
Level
AS

Exam points

  • Explain electron configurations for atoms and ions using shell, subshell and orbital notation, including ionisation and electron counts.

CAIE A-Level Chemistry AS 1.3.5 Electronic Configurations Questions question 1

[Maximum number: 2]

The electronic configuration of a sulfur atom is 1s22s22p63s23p41 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{4}.

During the process of ionisation a sulfur atom loses an electron.

S( g)→S+(g)+e−ΔH=1000 kJ mol−1\mathrm{S}(\mathrm{~g}) \rightarrow \mathrm{S}^{+}(\mathrm{g})+\mathrm{e}^{-} \quad \Delta H=1000 \mathrm{~kJ} \mathrm{~mol}^{-1}

Identify the orbital from which this electron is removed. Explain your answer.
orbital
explanation

All question bank results loaded