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CAIE A-Level Chemistry AS 19 Nitrogen Compounds Questions

Practise preparing amines and nitriles, forming hydroxynitriles and hydrolysing nitriles to carboxylic acids.

Syllabus
2028–2030
Course
Chemistry 9701
Level
AS

Covered syllabus points

19.1 Primary amines19.2 Nitriles and hydroxynitriles

Question 1

[Maximum number: 1]

Compounds P, Q and R have all been found in the atmosphere of one of Saturn's moons.
P

Figure for Question 1 — CAIE A-Level Chemistry AS
Q

Q

R

R

The flow chart shows some reactions of R.

R

Figure for Question 1 — CAIE A-Level Chemistry AS
Figure for Question 1 — CAIE A-Level Chemistry AS
CH3CH2CH2NH2\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{NH}_{2}

T can also be formed by the reaction of CH3CH2CH2Br\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{Br} with ammonia.

State the necessary conditions of this reaction.

Question 2

[Maximum number: 2]

Compounds P and Q are structural isomers.

Fig. 4.1

Fig. 4.1

Question (a)

(a)

Fig. 4.3 shows a synthesis starting from T, a different isomer of R and S.

Fig. 4.3

Fig. 4.3

[ 2 ]

Question (i)

(i)

Identify the reagent and conditions for reaction 1.

[ 1 ]

Question (ii)

(ii)

Reaction 2 is a hydrolysis reaction.

Construct an equation for reaction 2 .
(C2H5)2CHCN\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)_{2} \mathrm{CHCN}

[ 1 ]

Question 3

[Maximum number: 1]

The structure of coniine is shown.

Figure for Question 3 — CAIE A-Level Chemistry AS

Coniine can be synthesised by reacting ammonia with a dibromo compound, X .

XNH3+C8H16Br2→ coniine +2HBr\begin{gathered} \mathrm{X} \\ \mathrm{NH}_{3}+\mathrm{C}_{8} \mathrm{H}_{16} \mathrm{Br}_{2} \rightarrow \text { coniine }+2 \mathrm{HBr} \end{gathered}

What is compound X ?

A

1,1-dibromo-2-propylcyclopentane

B

1,2-dibromo-2-propylcyclopentane

C

Br(CH2)3CHBr(CH2)3CH3\mathrm{Br}\left(\mathrm{CH}_{2}\right)_{3} \mathrm{CHBr}\left(\mathrm{CH}_{2}\right)_{3} \mathrm{CH}_{3}

D

Br(CH2)4CHBr(CH2)2CH3\mathrm{Br}\left(\mathrm{CH}_{2}\right)_{4} \mathrm{CHBr}\left(\mathrm{CH}_{2}\right)_{2} \mathrm{CH}_{3}

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