Edexcel IGCSE Physics 5.21 Pressure Temperature Relationship Questions

Convert Celsius readings to kelvin, rearrange the pressure–temperature ratio, and report the calculated pressure or temperature in the units requested.

Exam points

Convert each Celsius reading to kelvin before substituting values into p₁/T₁ = p₂/T₂.
Rearrange p₁/T₁ = p₂/T₂ to find a missing pressure or temperature, then report the requested unit.
Confirm the gas mass and volume remain constant before applying the pressure–temperature ratio.

[Maximum number: 4]

The diagram shows a manometer, a device used for measuring differences in pressure.

Figure for Question Edexcel IGCSE Physics 5.21 Pressure Temperature Relationship Questions question 1 — Edexcel IGCSE Physics

The temperature and pressure of the trapped gas increase when it is warmed.

The pressure of the trapped gas in the manometer is $9.95 \times 10^{4} \mathrm{~Pa}$ and the temperature is $16^{\circ} \mathrm{C}$ .

Calculate the new pressure of the trapped gas if the temperature increases to $32^{\circ} \mathrm{C}$ .
[assume volume of the trapped gas remains constant]
new pressure = Pa

Marking points:
- conversion of temperatures to kelvin
- substitution
- rearrangement
- evaluation

Example:
$T_1=289\ \mathrm{K},\qquad T_2=305\ \mathrm{K}$ $\frac{9.95\times10^{4}}{289}=\frac{p_2}{305}$ $p_2=\frac{9.95\times10^{4}\times305}{289}$ $p_2=1.1\times10^{5}\ \mathrm{Pa}$

Marking guidance:
- not converting to kelvin giving $199000\ \mathrm{Pa}$ gains 2 marks maximum

Accept:
- $1.05\times10^{5}\ \mathrm{Pa}$
- $105008.65\ldots\ \mathrm{Pa}$

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Edexcel IGCSE Physics 5.21 Pressure Temperature Relationship Questions question 1