Edexcel IGCSE Physics 1 Forces & motion Question Bank
Practise force and motion questions using units, motion graphs, speed and acceleration equations, practical data and momentum contexts.
- Syllabus
- First assessment 2019
- Course
- Physics 4PH1
Practise force and motion questions using units, motion graphs, speed and acceleration equations, practical data and momentum contexts.
Which of these is a device used to measure force?
newton meter
ruler
thermometer
voltmeter
A
Airbags are safety devices used in cars to protect the driver if there is a crash.
State the formula linking momentum, mass and velocity.
momentum = mass x velocity
Accept:
- standard symbols, e.g. p for momentum
Reject:
- m or M for momentum
A person inside a car has a mass of 72 kg and a velocity of 13 m/s.
Show that the momentum of the person is about 900 kgm / s.
72 x 13 = 936
Therefore the momentum is about 900 kg m/s.
The person experiences a crash and comes to rest in 0.29 s.
Calculate the force on the person.
force = ............ N
- substitution into given equation
- correct evaluation
Example:
- force = change in momentum / time taken
- force = 936 / 0.29 = 3200 N
Accept:
- use of change in momentum of 900, 936 or 940
- expected values of 3103, 3228 and 3241 N
Which statement explains how airbags protect the driver?
increase the force acting on the driver
increase the time taken for the driver to stop
increase the kinetic energy store of the driver
increase the momentum of the driver
B
The diagram shows a velocity-time graph for a car from the time the driver sees an obstacle in the road until the car comes to rest.

Calculate the acceleration of the car between 1.8 and 8.0 seconds.
acceleration = ............ m/s^2
Marking points:
- use of acceleration =timechange in velocity
- substitution
- evaluation
Example:
acceleration=6.2−30acceleration=−4.8 ms−2
Accept:
- clear indication that acceleration is gradient
- -4.8 to −5.0 ms−2
Ignore:
- minus sign
Calculate the braking distance of the car.
braking distance = ............ m
- clear indication that distance is area under the line
- understanding that braking distance is area of triangle section only
- evaluation
Example:
- distance = area
- distance = 0.5 x 30 x 6.2
- distance = 93 m
Accept:
- alternative method using ECF from 4(a)(i) and v^2 = u^2 + 2as, giving 93.75 m
- 54 m scores 1 mark
- 147 m scores 2 marks
Explain the effect, if any, of increased driver tiredness on the thinking distance and on the braking distance of the car.
thinking distance
braking distance
Thinking distance:
- increases
- due to increased reaction time
Braking distance:
- no effect on braking distance
- due to no effect on braking time / braking force
Accept:
- idea that braking distance does not depend on human factors
Which of these represents the distance-time graph for the car?




A
The diagram shows a child's toy for accelerating steel balls.

This is how the toy works.
- the toy uses three identical steel balls, each with a mass of 4.1 g
- ball A moves towards the magnet
- ball B is in contact with the magnet
- balls B and C are initially at rest and are in contact with each other
- when ball A collides with the magnet, ball C moves away from the magnet
Ball A moves towards the magnet with an initial velocity of 0.15 m/s.
Calculate the initial momentum of ball A.
initial momentum = ............ kg m/s
- substitution into momentum = mass x velocity
- evaluation
Example:
- p = 0.0041 x 0.15
- p = 0.00062 kg m/s
Accept:
- standard symbols, e.g. p = m x v
- decimal or standard form
- 0.000615
Marking guidance:
- Deduct 1 mark for a power-of-ten error.
Ball A is attracted to the magnet.
Explain how this attraction affects the momentum of ball A as it approaches the magnet.
- velocity of ball increases
- momentum increases
Accept:
- ball speeds up
When ball A collides with the magnet, a force of 1.3 N is exerted on ball C for a time of 0.0025 s.
This causes ball C to move away from the magnet.
Calculate the change in velocity of ball C due to this force.
change in velocity = ............ m/s
- substitution into F = (mv - mu) / t
- rearrangement
- evaluation
Example:
- 1.3 = 0.0041 x v / 0.0025
- v = 1.3 x 0.0025 / 0.0041
- v = 0.79 m/s
Accept:
- 0.79268...
Marking guidance:
- Deduct 1 mark for a power-of-ten error.
This question is about momentum.
Which of these is the correct unit for momentum?
kg / m / s
kg2 m/s
kgm/s2
kgm / s
D
The diagram shows an object before and after an explosion.
The object breaks into two parts, P and Q .
The parts move away from each other in opposite directions.

State what is meant by the principle of conservation of momentum.
idea that (total) momentum before (collision) = (total) momentum after (collision) (in the absence of external forces);
allow references to explosion/event, rather than
collision
'momentum is conserved' is
insufficient
Calculate the magnitude of the velocity of part P after the explosion.
velocity = ............ m/s
Marking points:
- setting up equation using conservation of momentum
- rearrangement
- evaluation
Example:
0=(1.9×3.7)+(2.9v)1.9×3.7=2.9vv=2.9−7.03=−2.4 ms−1
Final answer:
∣v∣=2.4 ms−1
Accept:
- 2.42… ms−1
Marking guidance:
- Ignore the sign of the final answer.
- Correct evaluation of object Q's momentum, i.e. −7.03 kgms−1, scores 1 mark if no other mark scored.
A child drops an egg from a height of 10 cm and the egg lands on the floor.
Explain why the egg is less likely to break if the floor is covered with a thick carpet than if the floor were covered in hard tiles.
idea of carpet increases impact time;
carpet reduces rate of change of momentum (for the same speed or momentum of egg);
(carpet) reduces force;
ignore references to hard/soft floors ignore references to absorbing force or reduction in 'impact' ignore references to energy
allow RA
allow RA allow reference to given equation or word equation allow reduces deceleration or acceleration
allow RA