IB Biology HL B3.1 Gas Exchange Questions
Practise IB Biology HL B3.1 by linking respiratory surfaces and ventilation to oxygen transport, dissociation curves and transpiration evidence.
- Syllabus
- First assessment 2025
- Course
- Biology HL
- Level
- HL
Practise IB Biology HL B3.1 by linking respiratory surfaces and ventilation to oxygen transport, dissociation curves and transpiration evidence.
Adult humans may absorb more than five hundred litres of oxygen per day. Explain how gas exchange is maintained in the human respiratory system.
a. ventilation/inhaling brings fresh air/air with high oxygen concentration to the lungs OR ventilation/exhaling gets rid of stale air/air with high concentration of carbon dioxide
b. ventilation due to muscle contractions causing pressure/volume changes in the thorax
c. contraction of external intercostal muscles AND diaphragm occurs during inspiration OR contraction of internal intercostal muscles/abdomen wall muscles during «forced» expiration
d. alveoli surrounded by «many» capillaries
e. blood flow/pumping of heart «brings blood to/takes blood away from alveoli/lungs»
f. concentration gradients «of oxygen/ CO2 » maintained «by ventilation/blood flow»
g. O2 AND CO2 diffuse
h. CO2 from capillaries/blood/vessel to alveolus/air AND O2 from alveoli into capillaries/blood/vessel
i. large numbers of alveoli increase surface area
j. short distance so rapid diffusion/gas exchange
k. type I pneumocytes/alveolus wall/capillary walls are one cell thick/very thin
l. alveoli «lining» moist for dissolving of gases/rapid diffusion OR
type II pneumocytes keep the «lining of» the alveolus moist
m. type II pneumocytes secrete surfactant to reduce surface tension/prevents alveoli from collapsing
Carbon dioxide and oxygen are essential gases in many biological processes.
Describe conditions necessary in the lungs for efficient gas exchange in humans.
a. alveoli provide a large surface area (for easy diffusion of gases);
b. thin walls/ 1 -cell thick walls /type 1 pneumocytes/cells lining the alveoli are (extremely) thin (to facilitate gas exchange);
c. a moist surface on the cells (to dissolve the gases/oxygen and carbon dioxide);
d. type II pneumocytes secrete surfactant to reduce surface tension/prevent sides of alveolus sticking together;
e. blood capillaries have thin walls/1-cell thick walls (for short path/easy diffusion of gases);
f. good supply of blood / blood flow through capillaries around alveoli to maintain the concentration gradients of gases/ higher oxygen concentration in alveoli than in blood capillaries/ higher CO2 concentration in blood capillaries than in alveoli;
g. ventilation/breathing maintains concentration gradients of gases (between air in alveoli and blood capillaries) (to facilitate diffusion);
Mpb. Refers to thin walls, not membranes.
Mpd. Requires function of surfactant.
3 marks
The graph shows the relationship between partial pressure of oxygen in air and altitude.
Explain the consequence of high altitude for gas exchange in humans.
a. lower oxygen partial pressure reduces oxygen availability (for the blood);
b. less oxygen diffuses/is exchanged with the blood OR less oxygen diffuses across the alveolar membrane/alveoli;
c. less saturation of hemoglobin with oxygen;
d. more CO2 remains in the blood OR less CO2 is exhaled;
e. breathing rate/depth is increased (in the short term);
f. (to compensate for the lack of oxygen) the body will produce more erythrocytes/RBCs/hemoglobin;
Mp a: Do not accept lower oxygen concentration at high altitude. Partial pressure must be mentioned.
Mp c: Do not accept increased hemoglobin affinity for oxygen instead of saturation.
Mp d: Allow higher CO2 decreasing hemoglobin affinity for oxygen.
Marking guidance:
3 max
A supply of oxygen is needed for aerobic respiration in mitochondria. Describe the features of alveoli in human lungs that adapt them for efficient absorption of oxygen.
large surface area from having many alveoli;
single/flattened layer of (thin) cells in wall;
(surrounded by) dense network of capillaries/capillary bed;
short distance for gases/oxygen/carbon dioxide to diffuse;
moist lining / film of moisture on inside of alveolus;
moisture allows oxygen/gases to dissolve;
diffusion of oxygen down concentration gradient;
Explain the mechanism of ventilation of human lungs.
ventilation is movement of air into and out of lungs;
volume of thorax/lungs/chest increased/decreased;
pressure in thorax/lungs/chest decreased/increased;
air flows from higher to lower pressure / air flows until the pressures are equal;
During inspiration/inhalation:
external intercostal muscles contract so ribcage moved up/out;
diaphragm contracts so moves down/becomes flatter;
internal intercostal/abdomen (wall) muscles relax;
During expiration/exhalation:
external intercostal muscles relax so ribcage moved down/in;
diaphragm relaxes;
recoil of elastic fibres that stretched during inspiration;
internal intercostal muscles contract (during forced ventilation);
abdomen (wall) muscles contract (during forced ventilation);
Measurements of the lung capacity of a student were recorded using a spirometer and displayed with a data logger. Initially the student was at rest, then changed to carrying out strenuous exercise. The results are displayed in the graph.
Calculate the ventilation rate at rest, giving the units.
12 breaths per minute/ 6 litres per minute
Accept answers from 11 to 12 breaths per minute.
Accept answers from 5.5 to 6 litres per minute.
Answer must include breaths or litres and a standard unit of time.
Correct:
eg: 12 breaths / minute
eg: 0.1 L sec⁻¹ or 6 L min⁻¹
Incorrect:
eg: but 12 breaths = 0 marks
The micrograph shows part of a lilac (Syringa vulgaris) leaf in vertical section.
Explain the roles of two leaf structures that help with the process of gas exchange in the leaf.
a. spongy mesophyll provides a large/moist/permeable surface area (for gas exchange);
b. guard cells form pores/stomata (through the epidermis) / open and close stomata OR stomata are pores (through the epidermis that) allow CO2/O2/ gases to enter/exit the leaf/to pass through the epidermis;
c. (air) spaces for diffusion/movement/transfer of gases (to/from spongy mesophyll cells and stomata);
Explain how the distribution of tissues in the leaf of a dicotyledonous plant is adapted to production and distribution of products of photosynthesis.
a. leaf has large surface area for absorption of light;
b. upper epidermis (thin) allowing light to pass;
c. (waxy translucent) cuticle to (allow light in and) prevent water loss;
d. palisade mesophyll contains many (cells with) chloroplasts;
e. palisade mesophyll close to upper layer to receive more light;
f. spongy mesophyll contains chloroplasts which allow photosynthesis;
g. spongy mesophyll (cells loosely packed) allows gaseous exchange;
h. stoma allow CO2 for photosynthesis to diffuse in;
i. stoma allow O2 produced in photosynthesis to diffuse out;
j. xylem brings water (for reactions);
k. phloem carries away products of photosynthesis/sucrose;
l. guard cells open and close stoma (for gas exchange);
The rate of transpiration can be measured using a data-logging pressure sensor connected to a plant cutting via a plastic tube. In an experiment, a control set-up was connected to the tube and placed in a well-lit room with normal humidity levels.
Outline how this control set-up could be modified to test the effect of either humidity or temperature on the rate of transpiration.
Alternative 1
humidity: [2 max]
a. outline of how independent variable is varied
b. outline of control treatment
c. control of other variable«s»
Alternative 2
temperature: [2 max]
d. outline of how independent variable is varied
e. outline of control treatment
f. control of other variable«s»
eg: cover experimental plant«s» with a plastic bag OR
mist the experimental plant«s». eg: control plant«s» is/are not covered/not misted. eg: light is kept constant.
eg: place set-up under/away from heat lamps at different distances.
eg: no heat lamp for control.
eg: use hygrometer to verify that heat lamp does not change humidity level.
The stomatal density is the number of stomata per area of leaf epidermis. A study was done on the stomatal density of the lower epidermis of leaves from Protium decandrum, a tree found in the Amazon forest.
The image shows the epidermis stripped from the lower surface of a leaf.
The mean stomatal density for the lower epidermis of P. decandrum was around 600 per mm2. Predict how the stomatal density for the upper epidermis would compare.
(upper surface/epidermis usually has) fewer stomata/lower stomatal density/no stomata
Oxygen dissociation curves show the percentage of oxygen saturation of adult haemoglobin (Hb) at different oxygen concentrations, as measured in partial pressure of oxygen ( pO2 ).
On the graph, sketch an oxygen dissociation curve for foetal haemoglobin.
curve should be the sigmoidal and drawn to the left of the oxygen dissociation curve;
Labels not necessary.
Not necessary that curves meet at high pO2.
Describe an adaptation of haemoglobin for the transport of oxygen.
a. oxygen binds to the haem group/iron;
b. haemoglobin structure / 4 haem groups allow for cooperative binding of oxygen;
c. when one oxygen binds to haemoglobin oxygen affinity increases due to change in conformation (of haemoglobin);
Identify the percentage of oxygen saturation of haemoglobin at a partial pressure of 40 mmHg .
73%;
Marking guidance:
Accept answers between 71 and 74 %.
Units required.
Describe the relationship between partial pressure of oxygen ( pO2 ) and percent saturation of haemoglobin.
a. as pO2 increases, \% saturation increases
OR
positive correlation/relationship;
b. \% saturation levels off/plateaus/OWTTE (at higher partial pressure);
c. sigmoidal relationship/S curve;
a., b. Accept quoting values for increase and levelling off.
c. Do not accept other terms than sigmoid or S shaped curve.
Marking guidance:
Do not accept 100\% saturation.
The graph shows the oxygen dissociation curve for adult hemoglobin.
Using the graph, draw a line to show how the oxygen dissociation curve changes with the Bohr shift.
partial pressure of oxygen
Explain the role of the Bohr shift during vigorous exercise.
a. more CO2 is produced which lowers the pH of the blood;
b. hemoglobin releases more oxygen (at lower pH ) for same partial pressure of oxygen;
c. more oxygen is available to respiring tissues;