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IGCSE Math B8.E Vector sums and differencesTopic Practice

8.E Vector sums and differences

Sum and difference of two vectors

Question 1

[Maximum number: 2]

Given that a=(23)\mathbf{a}=\binom{2}{3} and b=(12)\mathbf{b}=\binom{1}{-2}
find, as a column vector, a-2 b

Question 5(a)(ii)

Figure 2 shows the triangle OAB in which OA=6a\overrightarrow{O A}=6 \mathbf{a} and OB=4b\overrightarrow{O B}=4 \mathbf{b}
The point C lies on OA such that O C: O A=2: 3

Find, in terms of a and b or a or b, simplifying your answer where possible,

AB\overrightarrow{AB}

Question 7(a)

[Maximum number: 1]
Figure 1

Figure 1

Figure 1 shows triangle OAB in which OA=12a\overrightarrow{O A}=12 \mathbf{a} and OB=8b\overrightarrow{O B}=8 \mathbf{b}.

Express AB\overrightarrow{AB} in terms of a\mathbf a and b\mathbf b.

Question 8

[Maximum number: 2]

Figure 1 shows triangle OAB in which OA=4a\overrightarrow{O A}=4 \mathbf{a} and OB=8b\overrightarrow{O B}=8 \mathbf{b}
P is the point on OA such that O P: O A=1: 4

Question 8(a)

(a)

Express in terms of a or bor a and b where appropriate,

[ 2 ]

Question 8(a)(i)

(i)

AB\overrightarrow{A B}

Question 8(c)

(b)

R is the point on AB such that AR : AB = 1 : n where n is a constant.

Find and simplify an expression for PR\overrightarrow{PR} in terms of n, a and b.

[ 2 ]

Question 21(a)

[Maximum number: 2]

21OX=(25)21 \overrightarrow{O X}=\binom{2}{5} and OY=(27)\overrightarrow{O Y}=\binom{-2}{7}

Express XY\overrightarrow{X Y} as a column vector.

XY=(\overrightarrow{X Y}=(

Question 9(b)(ii)

[Maximum number: 2]

The vectors
p=(2x1y),q=(y+3y)\mathbf p=\begin{pmatrix}2x-1\\y\end{pmatrix}, \qquad \mathbf q=\begin{pmatrix}y+3\\-y\end{pmatrix}
are such that p=98|\mathbf p|=\sqrt{98} and
p+q=(70).\mathbf p+\mathbf q=\begin{pmatrix}7\\0\end{pmatrix}.

Show that
y=235.y=2-3\sqrt5.

Question 9

Figure 4

Figure 4

Diagram NOT accurately drawn

Figure 4 shows quadrilateral OABC with CB parallel to OA.
OA=12aOB=6b\overrightarrow{O A}=12 \mathbf{a} \quad \overrightarrow{O B}=6 \mathbf{b} and CB=12OAC B=\frac{1}{2} O A

Question 9(a)

(a)

Write down in terms of a or b or a and b

[ 2 ]

Question 9(a)(i)

(i)

BC\overrightarrow{B C}

Question 9(a)(ii)

(ii)

OC\overrightarrow{OC}

Question 9

Question image

Figure 2 shows triangle OAB with OA=4a\overrightarrow{OA}=4\mathbf a and OB=3b\overrightarrow{OB}=3\mathbf b.
The point C lies on OB such that OC=2b\overrightarrow{OC}=2\mathbf b.
The point D is the midpoint of AB.
The point E lies on AC such that OED is a straight line.

Question 9(a)

(a)

Find, in terms of a\mathbf a and b\mathbf b, simplifying your answer where possible,

[ 4 ]

Question 9(a)(i)

(i)

CA\overrightarrow{CA}.

Question 9(a)(ii)

(ii)

AB\overrightarrow{AB}.

Question 9(a)(iii)

(iii)

OD\overrightarrow{OD}.

Question 9

Diagram NOT accurately drawn

Diagram NOT accurately drawn

Figure 3 shows three points A, B and C on a circle with centre O where AOB is a diameter of the circle.
D is the point on AC such that A D: D C=3: 2
Given that OA=a\overrightarrow{O A}=\mathbf{a} and AD=b\overrightarrow{A D}=\mathbf{b}

Question 9(a)

(a)

find, in terms of a or b or a and b where appropriate, a simplified expression for

[ 4 ]

Question 9(a)(ii)

(i)

CO\overrightarrow{C O}

Question 9(a)(iii)

(ii)

DB\overrightarrow{DB}

Question 10

Figure 4

Figure 4

Figure 4 shows a trapezium OACB in which OAC=AOB=90\angle O A C=\angle A O B=90^{\circ} so that OB and AC are parallel.
Given that OA=a,OB=b\overrightarrow{O A}=\mathbf{a}, \overrightarrow{O B}=\mathbf{b} and AC=2b\overrightarrow{A C}=2 \mathbf{b},

Question 10(a)

(a)

find in terms of a and b,

Question 10(a)(i)

(i)

AB\overrightarrow{A B},

Question 10(a)(ii)

(ii)

OC\overrightarrow{OC}.

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