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IGCSE Math B5.G Combined transformationsTopic Practice

5.G Combined transformations

Combination of transformations The matrix AB represents the transformation represented by B followed by the transformation represented by A

Question 4(e)

[Maximum number: 3]
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Triangles A,D and F are shown on the grid.

In this question, ignore any labelling on the triangles.

Triangle E is transformed to triangle B under the transformation represented by matrix N\mathbf N.
Find the matrix N\mathbf N.

\text{If }A=\begin{pmatrix}a&b\c&d\end{pmatrix},\text{ then }A^{-1}=\frac{1}{ad-bc}\begin{pmatrix}d&-b\-c&a\end{pmatrix}.

Question 5(d)

[Maximum number: 2]
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The points with coordinates (3,1),(4,3),(6,3) and (6,1) are the vertices of a quadrilateral Q.

Find the matrix that represents the transformation that maps quadrilateral S onto quadrilateral Q.

Question 8(c)

[Maximum number: 4]
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The diagram shows kite A.
Kite B is the image of kite A under a reflection in the line with equation y=-1.

M=(0120),N=(0110).M=\begin{pmatrix}0&-1\\-2&0\end{pmatrix}, \qquad N=\begin{pmatrix}0&-1\\1&0\end{pmatrix}.
Kite A is transformed to kite D under the combined transformation with matrix MN.
On the grid opposite, draw and label kite D.

Question 6(d)

[Maximum number: 2]
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The points with coordinates (1,1),(3,1) and (4,3) are the vertices of triangle A.

Triangle A is transformed to triangle C under the transformation with matrix N.

Find matrix N.

Question 5(d)

[Maximum number: 3]
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Triangles A and B are drawn on the grid opposite.

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Triangle D is the image of triangle A under the transformation with matrix N.
Find the matrix N.

Only use this grid if you need to redraw your triangles.

Question 10(d)

[Maximum number: 7]

Triangle A and triangle B are drawn on the grid opposite.

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Triangle B is transformed to triangle E under the transformation with matrix P\mathbf P, where
P=(k1k30).\mathbf P=\begin{pmatrix}-k&1\\k-3&0\end{pmatrix}.
Triangle E is transformed to triangle F under the transformation with matrix Q\mathbf Q, where
Q=(k1k21k).\mathbf Q=\begin{pmatrix}k&1\\k^2-1&k\end{pmatrix}.
Triangle F is the image of triangle B under the matrix N\mathbf N.
Given that the determinant of N\mathbf N is 2, find the coordinates of the vertices of triangle F.

det(abcd)=adbc.\det\begin{pmatrix}a&b\\c&d\end{pmatrix}=ad-bc.

Question 9

[Maximum number: 5]

A=(3412),B=(3122).A=\begin{pmatrix}3&4\\-1&2\end{pmatrix}, \qquad B=\begin{pmatrix}3&-1\\2&-2\end{pmatrix}.
The transformation with matrix A is equivalent to the transformation with matrix B followed by the transformation with matrix C, where C is a 2×22\times2 matrix.
Find matrix C.

The inverse of matrix (abcd)\begin{pmatrix}a&b\\c&d\end{pmatrix} is
1adbc(dbca).\frac1{ad-bc}\begin{pmatrix}d&-b\\-c&a\end{pmatrix}.

Question 10(d)

[Maximum number: 3]

A=(2k2k93kk+1),B=(153k).\mathbf A=\begin{pmatrix}2k^2&k-9\\-3k&k+1\end{pmatrix}, \qquad \mathbf B=\begin{pmatrix}1&-5\\3&k\end{pmatrix}.
The determinant of matrix A\mathbf A is equal to the determinant of matrix B\mathbf B.

The transformation with matrix C\mathbf C, where C\mathbf C is a 2×22\times2 matrix, is equivalent to the transformation with matrix A\mathbf A followed by the transformation with matrix B\mathbf B.
Given that k is positive, find matrix C\mathbf C.

Determinant of matrix (abcd)=adbc.\text{Determinant of matrix }\begin{pmatrix}a&b\\c&d\end{pmatrix}=ad-bc.

Question 11(e)

[Maximum number: 5]
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Triangle A and triangle D are drawn on the grid opposite.
Triangle A is transformed to triangle B under a rotation of 180180^\circ about (3,1).
Triangle A is transformed to triangle C under a reflection in the line y=-0.5.
Triangle D is transformed to triangle E under the transformation with matrix
M=(2002).\mathbf M=\begin{pmatrix}-2&0\\0&-2\end{pmatrix}.

Triangle A is transformed to triangle F under a rotation of 9090^\circ anticlockwise about the origin.
Triangle F is transformed to triangle G under the matrix (72k224)\begin{pmatrix}7-2k&2\\2&4\end{pmatrix}.
Triangle G is the image of triangle A under the matrix N\mathbf N.
Given that N1=110(1321)\mathbf N^{-1}=\frac1{10}\begin{pmatrix}-1&3\\-2&1\end{pmatrix}, find the value of k.

Inverse of (abcd) is 1adbc(dbca).\text{Inverse of }\begin{pmatrix}a&b\\c&d\end{pmatrix}\text{ is }\frac1{ad-bc}\begin{pmatrix}d&-b\\-c&a\end{pmatrix}.

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