Question 4(b)
[Maximum number: 5]
Given that (x-3) is a factor of where k is a constant,
Given that, for all values of x,
where a, b and c are constants,
find the value of a, the value of b and the value of c.
Algebraic division of a cubic by a linear factor
Given that (x-3) is a factor of 5x3+2x2+kx+36 where k is a constant,
Given that, for all values of x,
5x3+2x2−63x+36=(x−3)(ax2+bx+c),
where a, b and c are constants,
find the value of a, the value of b and the value of c.
21(x+2) is a factor of 6x3+31x2+kx+30
Factorise fully 6x3+31x2+53x+30
Answer parts (a) and (b).
Hence, factorise completely 2x3+9x2−11x−30.
Show clear algebraic working.
f(x)=2x3+9x2−14x−9.
Express 2x+1f(x) in the form (x+a)2+b, where a and b are integers to be found.
28(x+2) is a factor of 6x3−x2+kx−10, where k is a constant.
Hence, factorise completely 6x3−x2−31x−10
27(x+1) is a factor of x3+kx2+x+6 where k is a constant.
Using this value of k, factorise completely x3+kx2+x+6

Diagram NOT accurately drawn