Question 4(d)

Figure 1
Information about the function f is shown in Figure 1.
Given that f is the mapping , where p and q are constants.
Hence find the value of x for which f(x)=ff(x).
Composite functions ‘fg’ will mean ‘do g first then f’

Figure 1
Information about the function f is shown in Figure 1.
Given that f is the mapping f:x↦px+q, where p and q are constants.
Hence find the value of x for which f(x)=ff(x).
The functions f and g are defined as
fg:x↦3x−1:x↦x3,x=0
The function h is such that
h(x)=2x−36.
Find gf(2).
The function f is defined for all values of x by f:x↦x2−2
The function g is given by
g:x↦x3+412,x=3−4.
Calculate fg(2).
The functions f, g and h are defined as
fgh:x↦x+3,:x↦x2−2x+3,:x↦x6,x=0.
Find
fh(−41)
Find the two values of x for which hgf(x)=2.
The functions f and g are defined as
Find the positive value of x for which gf(x)=36
The functions f and g are defined for all values of x by
f(x)=3x−5,g(x)=2x2+1.
Solve the equation
f(x)=gf(2).
The functions f, g and h are defined as
Solve fg(x)=54x−1.
The equation of the straight line L is
y=2-3x.
Find the values of x for which ff(x)+g(x)=0
Show your working clearly and give your answer in the form
where a, b and c are integers.
The function f is such that
f:x↦1−x1,x=0.Solutions of ax2+bx+c=0 are x=2a−b±b2−4ac.
Show that ff(x)=f−1(x).
Evaluate fff(2).
The function g is such that
g:x↦x−312.
Find hg(5).
Show that hg(x) can be written as
(x−3)24(45−6x+x2).