4.1 Biological molecules

Syllabus
0610–2026–2027
Topic
4.1
Level

Learning objectives

Match biological molecules to their elements

Carbohydrates, fats and proteins contain characteristic sets of chemical elements.

Molecule group Elements present in all examples
carbohydrates carbon, hydrogen and oxygen
fats and oils carbon, hydrogen and oxygen
proteins carbon, hydrogen, oxygen and nitrogen

All three groups contain carbon, hydrogen and oxygen. Nitrogen distinguishes the required protein list from the carbohydrate and fat lists.

The element symbols are C, H, O and N. An exam asking for names requires carbon, hydrogen, oxygen and nitrogen rather than only the symbols.

Do not list nitrogen for every carbohydrate or fat. For this syllabus objective, protein contains C, H, O and N; carbohydrate and fat contain C, H and O.

Build large molecules from smaller units

Large biological molecules are made by joining many smaller molecules in specific combinations.

Large molecule Smaller molecule or molecules
starch glucose
glycogen glucose
cellulose glucose
protein amino acids
fat or oil fatty acids and glycerol

Starch, glycogen and cellulose are different large molecules but share glucose as their smaller unit. Proteins use amino acids, while fats and oils require two kinds of smaller molecule.

The mapping works in reverse for breakdown questions: starch, glycogen and cellulose yield glucose units; proteins yield amino acids; fats and oils yield fatty acids and glycerol.

Glycerol alone does not make a fat, and glucose does not make protein. Keep each large molecule paired with exactly the smaller units listed in the syllabus.

Carry out and interpret five food tests

Each food test uses a named reagent and a characteristic positive result to identify a biological substance.

Substance Method Positive result
starch add iodine solution orange-brown → blue-black
reducing sugar add Benedict’s solution and heat in a hot-water bath blue → green, yellow, orange or brick-red precipitate
protein add biuret solution; do not heat blue → lilac or purple
fat or oil add ethanol and shake, then add water white or milky emulsion
vitamin C add sample to blue DCPIP DCPIP is decolourised

Use separate clean samples and droppers to avoid contamination. Include a known positive and a negative control when evaluating an unfamiliar sample.

Record both the reagent and observed result. A final colour is meaningful only when compared with the reagent's starting colour and the correct method, including heat only for Benedict’s test.

Use a water bath for Benedict’s test. Ethanol is flammable, so keep the emulsion test away from flames and add water only after shaking with ethanol.

Benedict’s blue-to-red result does not test protein, and biuret does not require heating. DCPIP decolourisation indicates vitamin C, not reducing sugar.

Describe DNA structure and base pairing

A DNA molecule consists of two strands coiled together to form a double helix.

Each strand contains chemicals called bases. Bonds between pairs of bases hold the two strands together.

Base on one strand Base on the other strand
A T
T A
C G
G C

To complete a complementary strand, work one position at a time and replace each base with its fixed partner. For example, A–C–G–T pairs with T–G–C–A.

Bases pair across the two strands, not along one strand. A never pairs with C or G in this model: A pairs with T, and C pairs with G.