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Edexcel IAL Chemistry A2 Topic 15 Carbonyls, Carboxylic Acids and Chirality

Edexcel IAL Chemistry A2 Topic 15 Carbonyls, Carboxylic Acids and Chirality

Question 2

[Maximum number: 10]

This question is about the identification of three organic compounds, X, Y and Z.
A molecule of each compound has only one type of functional group. Each compound contains six carbon atoms and two oxygen atoms.

In the mass spectrum of X, the molecular ion peak is at m / z=114.

Question 2(b)

(a)

Three chemical tests are carried out on X.

Test 1 When Brady's reagent (2,4-dinitrophenylhydrazine solution) is added to X, an orange precipitate is observed.

Test 2 When X is heated with an acidified solution of potassium dichromate(VI), no change is observed.

Test 3 When X is added to an alkaline solution of iodine, the formation of a pale yellow precipitate is observed.

Explain what can be deduced about the functional group present in X, by considering the results of each of these tests.
(b) Three chemical tests are carried out on X.

[ 3 ]

Question 2(c)

(b)

The high resolution proton NMR spectrum of X contains only two singlets with relative peak areas of 3: 2.

Draw the structure of X, identifying the two proton environments.

[ 2 ]

Question 2(d)

(c)

The molecular formula of Y is C6H12O2\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{2}.

[ 5 ]

Question 2(d)(i)

(i)

When aqueous sodium carbonate is added to Y, effervescence is observed. Identify, by name or formula, the functional group present in Y.

[ 1 ]

Question 2(d)(ii)

(ii)

The 13C{ }^{13} \mathrm{C} NMR spectrum of Y contains four peaks.

Give two possible structures for Y.

Table
[ 2 ]

Question 2(d)(iii)

(iii)

Explain how the low resolution proton NMR spectrum of Y would confirm which of your structures in (d)(ii) is correct. Chemical shifts are not required.

[ 2 ]

Question 12(a)

[Maximum number: 1]

Propanone reacts with iodine in both acidic and alkaline conditions.

The products of the reactions under the stated conditions include
□ A
□ B
□ C
□ D

Table

Question 6(a)

[Maximum number: 1]

Methylbenzene reacts with a mixture of concentrated nitric acid and concentrated sulfuric acid to form 2,4,6-trinitromethylbenzene.

Question image

What is the number of peaks in the 13C{ }^{13} \mathrm{C} NMR spectrum of methylbenzene?

A

seven

B

six

C

five

D

four

Question 19

[Maximum number: 8]

Propanal reacts very slowly with HCN at 298 K . To increase the rate of reaction potassium cyanide, KCN, is added.

Question 19(a)(i)

(a)

Complete the mechanism for this reaction by adding curly arrows, and relevant lone pairs and dipoles to Step 1 and Step 2.

Step 1

Question image
C N{ }^{-} \mathrm{C} \equiv \mathrm{~N}

Step 2

Question image
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⟶ products
intermediate

[ 4 ]

Question 19(a)(iii)

(b)

KCN is a homogeneous catalyst in this reaction.

Justify this description by referring to the mechanism.
(2)

[ 2 ]

Question 19(b)

(c)

The organic products of this reaction are enantiomers.

Draw the three-dimensional structures of these enantiomers.
(2)

[ 2 ]

Question 20

[Maximum number: 5]

This question is about compounds with the molecular formula C6H12O2\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{2}.

Question 20(a)

(a)

Hexanoic acid, C5H11COOH\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{COOH}, is a weak acid.

[ 3 ]

Question 20(a)(iii)

(i)

The solubility of hexanoic acid in water is 1.08 g per 100 g of water. The isomer of hexanoic acid, butyl ethanoate, CH3CO2C4H9\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{C}_{4} \mathrm{H}_{9}, has a solubility of 0.68 g per 100 g of water.

Explain the differences in these data in terms of the hydrogen bonding between hexanoic acid and water, and between butyl ethanoate and water.
(3)

[ 3 ]

Question 20(c)

(b)

Compound B, another isomer with the molecular formula C6H12O2\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{2}, contains a ring of six carbon atoms.

The carbon-13 NMR spectrum has only two peaks, one of which is at 69 ppm.
Draw the structure of compound B.
(2)

[ 2 ]

Question 21

[Maximum number: 6]

Esters are used in flavourings and perfumes.
They can be made by reactions involving alcohols.

Question 21(b)

(a)

An ester which smells of raspberries can be formed by either of two different reactions.

Reaction 1
catalyst

HCOOH+(CH3)2CHCH2OHHCOOCH2CH(CH3)2+H2O\mathrm{HCOOH}+\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCH}_{2} \mathrm{OH} \rightleftharpoons \mathrm{HCOOCH}_{2} \mathrm{CH}\left(\mathrm{CH}_{3}\right)_{2}+\mathrm{H}_{2} \mathrm{O}

Reaction 2

HCOCl+(CH3)2CHCH2OHHCOOCH2CH(CH3)2+HCl\mathrm{HCOCl}+\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCH}_{2} \mathrm{OH} \rightarrow \mathrm{HCOOCH}_{2} \mathrm{CH}\left(\mathrm{CH}_{3}\right)_{2}+\mathrm{HCl}
[ 6 ]

Question 21(b)(i)

(i)

Name the carboxylic acid, alcohol and catalyst used in Reaction 1.

HCOOH catalyst
(CH3)2CHCH2OH\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCH}_{2} \mathrm{OH}

[ 2 ]

Question 21(b)(ii)

(ii)

Explain one advantage and one disadvantage of using Reaction 2 rather than Reaction 1.

SECTION C

Answer ALL the questions. Write your answers in the spaces provided.

[ 4 ]

Question 15(b)

[Maximum number: 7]

A compound Q contains the elements carbon, hydrogen and oxygen only.

The high resolution proton NMR spectrum of Q is shown.

Question image

Deduce the structure of Q. Justify your answer by considering the relative peak areas, the chemical shifts and the splitting patterns.

You will find it helpful to refer to page 8 of the Data Booklet.
The peak at 3.6 ppm is due to a proton environment on a carbon bonded to the benzene ring. The peak is not where it might be expected from the general values in the Data Booklet.

SECTION C

Answer ALL the questions. Write your answers in the spaces provided.