Edexcel IGCSE Physics C Work and Power Questions
Practise using work, energy and power equations in mechanical contexts, with unit conversions, graph evidence and store changes.
- Syllabus
- First assessment 2019
- Course
- Physics 4PH1
Practise using work, energy and power equations in mechanical contexts, with unit conversions, graph evidence and store changes.
A student uses this apparatus to investigate the force needed to pull a block along a ramp.
State the formula linking work done, force and distance moved in the direction of the force.
work done = force x distance travelled
Accept:
- accepted symbols
The student pulls the block 0.89 m along the ramp with a force of 26 N . Show that the work done on the block by the 26 N force is about 23 J .
- substitution
- evaluation
Example:
- work done = 0.89 x 26
- work done = 23.1 J
The block has a mass of 1.3 kg and moves vertically upwards 0.11 m.
Calculate the increase in the gravitational potential energy (GPE) store of the block between the bottom and the top of the ramp.
increase in GPE = ............ J
- recall of formula GPE = mgh
- substitution
- evaluation
Example:
- GPE = 1.3 x 10 x 0.11
- GPE = 1.4 J
Marking guidance:
- Deduct 1 mark for a power-of-ten error if use of g is seen.
Explain why the work done to move the block along the ramp is greater than the increase in the GPE store of the block.
Any two from:
- reference to friction / air resistance
- energy transferred to the surroundings by mechanical work
- block not necessarily at constant speed
The student suggests it is better to use a less steep ramp to raise the block through the same vertical height.
Discuss an advantage and a disadvantage of using a less steep ramp.
Advantage, any two from:
- lower force required
- prevents the block from slipping down / helps move the block
Disadvantage, any two from:
- longer distance required, with a lower force
- more inefficient
- greater proportion of energy transferred to the surroundings
Accept:
- to overcome friction
- easier to move block for 2 marks
- more work required for the same increase in GPE
The photograph shows a toy car. When the toy car is pulled backwards, energy is stored in the elastic store as the rubber band is twisted.
When the car is released, some of the energy from the elastic store is transferred to the kinetic store of the car.
The remaining energy is transferred into the thermal store of the surroundings.
The car is pulled backwards again.
When released, 45 J of energy transfers into the car's kinetic store.
The car travels a distance of 7.5 m during this energy transfer.
State the useful work done on the car.
work done = ............ J
45 (J);
Calculate the mean accelerating force acting on the car.
accelerating force = ............ N
- substitution into work done = force x distance
- rearrangement
- evaluation
Example:
- 45 = force x 7.5
- force = 45 / 7.5
- force = 6.0 N
Accept:
- 6 N
A student uses this apparatus to investigate how the efficiency of an electric motor varies with its input voltage.
This is the student's method.
- connect the electric motor to a d.c. power supply and a joulemeter
- attach a 1.0 kg mass to the electric motor using a length of string
- set the voltage of the power supply to 10 V and switch on the power supply
- switch off the power supply when the mass has been lifted through a distance of 50 cm
- record the input energy to the motor from the joulemeter
- calculate the energy transferred to the gravitational store of the mass
- calculate the efficiency of the motor
The student repeats this process, setting the power supply to a different voltage each time.
Show that the gravitational store of the 1.0 kg mass increases by 5.0 J when it is lifted through a distance of 50 cm .
- conversion of cm to m
- substitution into GPE = mass x g x height
Example:
- 50 cm = 0.5 m
- GPE = 1 x 10 x 0.5 = 5 J
Accept:
- 0.5 seen anywhere
- use of g = 9.8 or 9.81 m/s^2
The photograph shows a toy car. When the toy car is pulled backwards, energy is stored in the elastic store as the rubber band is twisted.
When the car is released, some of the energy from the elastic store is transferred to the kinetic store of the car.
The remaining energy is transferred into the thermal store of the surroundings.
The car is pulled backwards again.
When released, 45 J of energy transfers into the car's kinetic store.
The car travels a distance of 7.5 m during this energy transfer.
State the useful work done on the car.
work done = ............ J
45 (J);
A student uses a computer simulation to investigate the motion of particles in a gas.
He records the pressure of the gas and the mean speed of the particles in the gas at different temperatures.
The graphs show his results.
Graph 1
Graph 2
The student then calculates the kinetic energy of a single gas particle at each temperature.
The mass of a single gas particle is 5.3×10−26 kg.
Calculate the average kinetic energy of a gas particle when the temperature of the gas is 100∘C.
Marking points:
- recall of kinetic energy formula
- substitution
- evaluation
Example:
KE=21×mass×speed2KE=0.5×5.3×10−26×5202KE=7.2×10−21 J
Accept:
- ECF from part (i)
- 7.16×10−21 to 7.31×10−21 J
Marking guidance:
- power-of-ten error scores -1
A student uses this apparatus to investigate the force needed to pull a block along a ramp.
Explain why the work done to move the block along the ramp is greater than the increase in the GPE store of the block.
Any two from:
- reference to friction / air resistance
- energy transferred to the surroundings by mechanical work
- block not necessarily at constant speed
Kori Nuclear Power Plant in South Korea is one of the world's largest nuclear fission power stations.
Kori has a maximum power output of 7.49×109 W.
State what is meant by the term power.
rate of energy transfer / doing work
Accept:
- energy transferred per unit time / second
Reject:
- energy transferred in a unit time
- P = current x voltage
Energy is transferred from the Sun to the Earth.
Solar panels use energy from the Sun to heat water.
The total area of the solar panels is 15 m2.
Each 1.0 m2 of the solar panels receives 1000 J of energy per second from the Sun. Show that the total energy transferred to the solar panels in 2 hours is about 100 MJ .
- evaluation of total power / conversion of hours to seconds
- evaluation of energy in J
- evaluation of energy in MJ
Example:
- power = 1000 x 15 = 15000 W
- time = 2 x 60 x 60 = 7200 s
- energy = 15000 x 7200 = 108000000 J
- energy = 108 MJ
Accept:
- x 3600 seen anywhere in working