Edexcel IGCSE Physics 2.19 Series Circuit Calculations Questions
Apply Ohm’s law and voltage addition in series to find component values, then use the circuit results to compare lamp brightness.
- Syllabus
- First assessment 2019
- Course
- Physics 4PH1
Apply Ohm’s law and voltage addition in series to find component values, then use the circuit results to compare lamp brightness.
The circuit diagram shows a light dependent resistor (LDR) and a 73Ω resistor connected in series with a 1.5 V cell.
Calculate the voltage across the LDR.
voltage = ............ V
- idea that voltages of two resistors in series add up to the supply voltage
- calculation of correct voltage
Example:
- V_cell = 1.5 = V_LDR + V_resistor
- V_LDR = 1.5 - 0.5694
- V_LDR = 0.93 V
Accept:
- ECF from 6(b)(ii)
The graph shows how the resistance of the LDR changes with light intensity.
Explain why the voltage across the LDR decreases when the resistance of the LDR decreases.
larger current means larger voltage across fixed resistor;
total voltage remains constant;