D1.2.1—Transcription
Transcription produces an RNA copy of gene information when RNA polymerase uses one DNA strand as a complementary template for mRNA synthesis.
- Syllabus
- First assessment 2025
- Objective
- D1.2.1
- Level
- SL
Transcription produces an RNA copy of gene information when RNA polymerase uses one DNA strand as a complementary template for mRNA synthesis.

Coverage 2012–2025 · Updated 16 Jul 2026
Chromosomal DNA is the long-term information store. Protein synthesis instead uses a short-lived messenger RNA (mRNA) copy of a selected gene.
selected gene in DNA → complementary mRNA copy → mRNA reaches a ribosome → nucleotide sequence directs amino-acid order
A working copy solves two problems:
mRNA carries information; it is not converted into protein matter. The ribosome reads its sequence while amino acids are joined into a separate molecule.
RNA polymerase binds near the gene and opens a short region of the DNA double helix, exposing the template strand.

Free RNA nucleotides align by complementary base pairing: DNA A pairs with RNA U, DNA T with RNA A, and C with G.
RNA polymerase joins the RNA nucleotides into a sugar–phosphate backbone. The mRNA separates, and the DNA strands pair again.
| Strand | Relationship to the new mRNA |
|---|---|
| DNA template | antiparallel and complementary |
| DNA coding strand | same base order as mRNA, except DNA has T where RNA has U |
DNA template: 3′–TAC CTT GCG–5′
mRNA: 5′–AUG GAA CGC–3′
Codon tables are read from mRNA 5′→3′. Do not look up a DNA template triplet directly.

gene selected → DNA opens locally → RNA polymerase reads one template strand → complementary RNA nucleotides are joined → mRNA leaves → DNA re-forms unchanged
| Question | Correct check |
|---|---|
| Which DNA strand determines mRNA? | the template strand |
| Which base replaces thymine in RNA? | uracil |
| Which direction is mRNA written? | 5′→3′ |
| Why can the gene be reused? | DNA sequence and covalent backbones remain intact |
The mRNA now carries codons in an order that a ribosome can translate into an amino-acid sequence.
[ 8 ]
Explain the process of transcription in prokaryotes.