A.2.17—Impulse
- Syllabus
- First assessment 2025
- Objective
- —
- Level
- SL
Impulse changes momentum
Impulse is the integral of resultant force over time. For a constant average force,
J=FnetΔt=Δp
Use the momentum change
Calculate Δp=pf−pi, including direction. A rebound reverses the velocity component and can make the momentum change larger than either momentum magnitude alone.
Average force
If the force varies, FΔt represents average resultant force over the contact interval. Use consistent units for impulse in N s or kg m s⁻¹.
Common trap
Do not use the initial momentum alone when the object rebounds or ends with a non-zero final velocity.
The evidence asks for contact time from average force and momentum change, or tests the magnitude of impulse for a change in velocity.
Determine / Calculate
Find the vector change in momentum and use J=Δp. For a rebound, choose a sign convention and subtract the initial momentum from the final momentum; then divide by contact time only if average force is requested.
Adding the initial and final momentum magnitudes without accounting for their opposite directions during a rebound.
Representative question
The ball rebounds from the ground with speed 7.8 ms−1. The ball is in contact with the ground for a time T. The average resultant force on the ball during this time is 1.1 N .
Determine T.
ALTERNATE 1
Δp=≪2.7×10−3×(7.8+9.5)=>0.0467<Ns>d≪1.1=ΔtΔp so T=1.10.0467⇒≫0.042≪s≫
ALTERNATE 2
a=≪mF⇒≫2.7×10−31.1=407≪ m s−2≫T=≪4079.5+7.8=≫0.042≪s≫
Watch for ECF from incorrect value of v in cii).
Award [1] for t=0.076≪s≫ using an impact speed of 23 m s−1.
[2]