A.2.10—Viscous drag

Syllabus
First assessment 2025
Objective
Level
SL

Model Viscous Drag on a Small Sphere

Stokes drag

For a small sphere moving slowly through a viscous fluid,

Fd=6πηrvF_d=6\pi\eta r v

where η\eta is viscosity, rr is sphere radius and vv is speed relative to the fluid.

Drag opposes motion

The drag force points opposite the sphere’s velocity. As speed increases, drag increases linearly in this model, reducing the resultant force when the driving force is fixed.

Approach to terminal speed

For a falling sphere, weight drives the motion and viscous drag grows with speed. When drag balances the effective weight, acceleration becomes zero and terminal speed is reached.

Common trap

Do not treat viscosity η\eta as the same quantity as drag force, and do not forget that the formula applies to the stated small-sphere, viscous-flow model.

A.2.10 Exam Analysis

Assessment in practice

1–2 marks
How it is assessed

The evidence asks why a droplet’s acceleration changes and asks for the shape of acceleration against velocity during a fall.

Command terms

Describe / Identify

What earns marks

As a droplet speeds up, use the given drag model to explain that drag increases, so the net force and acceleration change. At terminal speed, drag balances the driving force and acceleration is zero.

Watch for

Claiming that acceleration remains constant at g even after viscous drag becomes significant.

Representative question

Question 1

[Maximum number: 2]

Describe why the acceleration of the oil droplet changes.