3.2.2—Half-equations
- Syllabus
- First assessment 2025
- Objective
- 3.2.2
- Level
- SL
Separate oxidation and reduction, balance atoms, add H2O and H+ in acidic solution as needed, balance charge with electrons, then multiply to cancel electrons before adding.
A valid full redox equation conserves atoms and charge and contains no uncancelled electrons.
For MnO₄⁻ → Mn²⁺ in acid, balance O with 4H₂O, H with 8H⁺ and charge with 5e⁻: MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O. After combining halves, cancel electrons and any identical H⁺ or H₂O, then recheck both atoms and net charge.
To adapt an acidic half-equation to neutral or basic conditions, first balance it with H₂O, H⁺ and e⁻. Add the same number of OH⁻ to both sides to neutralize every H⁺, replace H⁺+OH⁻ by H₂O, then cancel water appearing on both sides. Recheck atoms and total charge; do not leave free H⁺ in a stated neutral medium unless the chemistry justifies it.
Representative question
The reaction continues until the violet colour disappears. The thiosulfate ion, S2O32−, is oxidized to SO2, and Fe3+ is reduced to Fe2+. Deduce the oxidation half-equation, and the overall redox equation for this second step of the reaction.
Oxidation half-equation:
Overall redox equation:
Oxidation half-equation:
S2O32−+H2O→2SO2+2H++4e−
Overall redox equation:
S2O32−+4Fe3++H2O→2SO2+4Fe2++2H+
Marking guidance:
Allow ECF for M2
Do not accept answers referring to transfer of electrons for M1.
Penalize missing electrostatic attraction once only.
Retrieve the route: assign oxidation states, balance half-equations, predict displacement, label cells, trace electrons and ions, follow organic redox pathways, calculate potentials and choose electrolysis products.
Check electron loss/gain, anode/cathode versus polarity, spontaneous sign, salt-bridge direction, ions present, organic functional-group direction and object-cathode placement.