2.2.13 (HL)—Arrhenius factor (A)
- Syllabus
- First assessment 2025
- Objective
- 2.2.13
- Level
- HL
A is the frequency factor: it represents the frequency of collisions with proper orientation. In the linear Arrhenius form, the y-intercept is ln A.
Read the intercept, find A by exponentiating ln A, and keep A distinct from Ea: Ea describes the energy barrier, while A describes collision frequency and orientation.
From a fitted line, intercept b gives A = eᵇ, while gradient m gives Ea = −mR. Check the pair against k = Ae^(−Ea/RT) at one data temperature. A has the same units as k for the stated rate law; it is not an activation energy or a universal constant.
Worked intercept example: for the same first-order Arrhenius line, use lnk=−6.02, 1/T=0.00296K−1 and gradient −Ea/R=−12500K. From lnk=(−Ea/R)(1/T)+lnA, −6.02=(−12500)(0.00296)+lnA, so lnA=30.98 and A=e30.98=2.85×1013s−1. The unit is s−1 because this reaction is first order and A has the same units as k.
Representative question
Calculate the numerical value of A.
lnA=23.2 (intercept on y-axis);
A=1.190imes1010;
Retrieve the route: measure a tangent rate, explain effective collisions, map rate factors, read Ea and energy profiles, evaluate mechanisms, determine molecularity and orders, calculate k, then use Arrhenius gradient and intercept for Ea and A.
Check tangent versus average slope, energy versus orientation, barrier labels, intermediate versus transition state, one-variable trial comparisons, order-dependent units, kelvin temperature and the signs of gradient and Ea.