1.1.4—Standard enthalpy change (ΔH⦵)
- Syllabus
- First assessment 2025
- Objective
- 1.1.4
- Level
- HL
Q=mcΔTandΔH=−Q/n
At constant pressure, calculate heat transferred from mass, specific heat capacity, and temperature change, then divide by reacting moles and apply the sign convention. Check standard conditions and units.
Worked calculation: if 100.0 g of solution warms by 6.0 K and c=4.18Jg−1K−1, q(solution)=mcΔT=(100.0)(4.18)(6.0)=2.51×103J=+2.51kJ. Therefore q(reaction)=−2.51kJ. If 0.0500mol of limiting reactant reacted, ΔH=−2.51/0.0500=−50.2kJmol−1: the negative sign means the reaction released energy. Heat loss or ignored calorimeter heat capacity usually makes the measured magnitude too small.
A standard molar enthalpy change belongs to the balanced reaction as written, with substances in their stated standard states under standard conditions. A classroom calorimetry value is an experimental estimate: report its conditions and uncertainty separately from a data-book or theoretical standard value. Heat loss to the surroundings or ignored calorimeter heat capacity commonly makes the measured magnitude too small.
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What is the standard enthalpy change, ΔHcombustion ⊖, according to the data?
Amount of fuel burned =0.110 mol
Mass of water =200 g
Initial temperature of water =21.0∘C
Final temperature of water =25.0∘C
Specific heat capacity of water, cw=4.18 J g−1 K−1
Q=mcΔT
Retrieve the route: define system/surroundings transfer, classify endothermic or exothermic, read stability from energy profiles, then calculate Q and ΔH with the correct sign.
Check the energy direction, surroundings temperature, reactant/product levels, moles, units, and ΔH sign.