IB Biology HL D2.3 Water Potential Questions
Calculate water potential, interpret plant-tissue osmosis data and explain plant and animal cell responses in IB Biology HL D2.3.
- Syllabus
- First assessment 2025
- Course
- Biology HL
- Level
- HL
Calculate water potential, interpret plant-tissue osmosis data and explain plant and animal cell responses in IB Biology HL D2.3.
Hydrogen bonds can exist both within and between molecules in living organisms and have an impact on their structure and function. Explain the importance of hydrogen bonding for living organisms.
a. cohesion in water/water molecules stick together (due to hydrogen bonds)
b. cohesion helps transport under tension of water/sap in xylem / transpiration stream
c. adhesion between water and cell walls/cellulose/polar molecules
d. adhesion/capillary action helps water to rise in plants/stems/xylem / helps keep leaf walls moist
e. solvent properties (due to hydrogen bonds) with polar/hydrophilic molecules
f. solvent properties exemplified by glucose/other example of a polar solute
g. high latent heat of evaporation / (much) energy required for evaporation so water useful as coolant/for sweating
h. high (specific) heat capacity so water temperature changes less
i. base pairing between bases/nucleotides/strands in DNA by hydrogen bonding
j. base pairing between bases in RNA and DNA for transcription/between codon and anticodon for translation
k. proteins have hydrogen bonding in secondary structure/α helix/β pleated sheet
I. proteins have hydrogen bonding between R groups/in tertiary structure/to maintain conformation
m. habitats because water is liquid due to high boiling point/due to water freezing on the surface
n. habitats on water surface due to surface tension
Excessive irrigation can cause increased salinity in the soil. What effect does this have on water transport in the plant roots?
Decreases movement of water from soil into the root
Absorption of water with a higher solute concentration
Increases movement of water from soil into the root
Absorption of water with a lower solute concentration
A
What would result from drinking large quantities of water?
D
Data was collected on rabbit red blood cells that were exposed to sodium chloride (NaCl) and scorpion venom. Under some osmotic conditions red blood cells swell and burst, releasing hemoglobin (hemolysis). The graph shows the response of red blood cells to different concentrations of sodium chloride, with and without scorpion venom.
Describe how the variables would be controlled in an experiment to estimate the osmolarity of plant tissue.
a. weigh all pieces to ensure same amount of plant material/allow comparisons
b. control surface area by having same shape/ size
c. carry out experiment at same temperature e.g. using a water bath or constant room temperature
d. all samples in solution for same length of time
e. all samples from same plant (to minimize variability)
f. use a range of solutions of the same solute
g. constant method of removing excess fluid before weigh tissue samples
Data was collected on rabbit red blood cells that were exposed to sodium chloride (NaCl) and scorpion venom. Under some osmotic conditions red blood cells swell and burst, releasing hemoglobin (hemolysis). The graph shows the response of red blood cells to different concentrations of sodium chloride, with and without scorpion venom.
Outline the effect of the venom on the hemolysis of red blood cells.
a. in NaCl concentrations between 0.3 to 0.5 % venom increases the percentage of hemolysis/more cells lyse
b. venom has no effect below 0.3 % and above 0.55 % NaCl OR
Venom has no effect at very low or very high NaCl concentrations
Plants have cell walls composed of cellulose.
Hydrostatic pressure was measured in onion (Allium cepa) epidermis cells bathed in pure water. The mean pressure inside the cells was 250 kPa . Atmospheric pressure is usually close to 100 kPa .
Outline how pressures higher than atmospheric pressure develop inside plant cells.
a. entry of water by osmosis;
b. because solute concentration is higher inside (the cell) / because solute/water potential is more negative inside / because the bathing medium is hypotonic;
c. because cell wall does not expand / cell wall prevents the cell from increasing in volume / cell wall allows high pressure/turgor pressure to build up (without the cell bursting);
Marking guidance:
Reject statements that the cell wall
can prevent water leaving the cell.
State the importance of cellulose to the plant when the pressure is higher inside the cell than outside.
prevents bursting;
Marking guidance:
Do not accept 'prevents collapsing'
Living organisms have mechanisms for preventing or reducing change.
Explain the need for isotonic conditions in human blood plasma and tissue fluid.
a. isotonic is same water potential/solute potential/osmotic potential/solute concentration;
b. (isotonic conditions) prevent (net) movement of water by osmosis;
c. hypotonic plasma/tissue fluid causes water entry to blood/body cells;
d. swelling/bursting of cells in (hypotonic plasma/tissue fluid);
e. hypertonic plasma/tissue fluid causes water to exit cells;
f. shrinkage/crenation/loss of volume/OWTTE;
g. blood cells bathed in plasma;
h. tissue fluid released by capillaries and then reabsorbed/flows between cells in tissues;
Marking guidance:
In mark point c and mark point e
accept 'higher/less negative
water potential' instead of
hypotonic and accept
'lower/more negative water
potential’ instead of hypertonic.
The water potential of a plant cell is -0.24 kPa . If the pressure potential of the cell is 0.46 kPa , what is the solute potential of that cell?
0.22 kPa
-0.22 kPa
0.70 kPa
-0.70 kPa
D
(a) Explain how the pressure potential and solute potential change inside a plant root cell when it is placed into a solution that is more hypotonic than the cell's cytoplasm.
Explain how the pressure potential and solute potential change inside a plant root cell when it is placed into a solution that is more hypotonic than the cell's cytoplasm.
a. (when cell is placed in a hypotonic solution) surrounding/outside (of the root hair cell) is more dilute / has higher water potential
OR
water will enter the root hair cell
OR
water moves from high water potential to low water potential;
b. (positive) pressure potential will increase / become more positive;
c. (negative) solute/osmotic potential will increase / become less negative;
d. water potential inside the cell will increase / become less negative;
e. Ψw=Ψs+Ψp;
f. when cell's water potential equals that of the solution, (net) water movement stops;
For e. allow word equation:
Ψw= water potential
Ψs= solute potential
Ψp= pressure potential