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IB Biology HL D2.3.10 Hl Solute and Pressure Potential Questions

Calculate unknown solute or pressure potentials with correct signs and interpret how plant-cell potentials change between solutions in IB Biology HL D2.3.10.

Syllabus
First assessment 2025
Course
Biology HL
Level
HL

Exam points

  • Apply Ψw = Ψs + Ψp to calculate an unknown solute or pressure potential, preserving the correct sign and kPa units.
  • Interpret movement between solutions to determine how water potential and pressure potential change inside a plant cell.

IB Biology HL D2.3.10 Hl Solute and Pressure Potential Questions question 1

[Maximum number: 1]

The water potential of a plant cell is -0.24 kPa . If the pressure potential of the cell is 0.46 kPa , what is the solute potential of that cell?

Ψw=Ψs+Ψp\Psi_{\mathrm{w}}=\Psi_{\mathrm{s}}+\Psi_{\mathrm{p}}
A

0.22 kPa

B

-0.22 kPa

C

0.70 kPa

D

-0.70 kPa

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