Edexcel IGCSE Physics (b) Movement & position

[Maximum number: 7]

The diagram shows a velocity-time graph for a car from the time the driver sees an obstacle in the road until the car comes to rest.

Figure for Question 1 — Edexcel IGCSE Physics

(a)

Calculate the acceleration of the car between 1.8 and 8.0 seconds.

acceleration = ............ m/s^2

[ 3 ]

Marking points:
- use of acceleration $=\frac{\text{change in velocity}}{\text{time}}$
- substitution
- evaluation

Example:
$\text{acceleration}=\frac{-30}{6.2}$ $\text{acceleration}=-4.8\ \mathrm{m\,s^{-2}}$

Accept:
- clear indication that acceleration is gradient
- -4.8 to $-5.0\ \mathrm{m\,s^{-2}}$

Ignore:
- minus sign

(b)

Calculate the braking distance of the car.

braking distance = ............ m

[ 3 ]

(c)

Which of these represents the distance-time graph for the car?

A

Figure for Question (c) — Edexcel IGCSE Physics — Option A

B

Figure for Question (c) — Edexcel IGCSE Physics — Option B

C

Figure for Question (c) — Edexcel IGCSE Physics — Option C

D

Figure for Question (c) — Edexcel IGCSE Physics — Option D

[ 1 ]

[Maximum number: 3]

The photograph shows infrared heating lamps being used to harden fresh paint on a car.

Figure for Question 2 — Edexcel IGCSE Physics

The infrared heating lamps are placed 1.5 m from the car.

Calculate the time taken for infrared waves emitted from a lamp to reach the car.

[for infrared waves, speed = 3.0 x 10^8 m/s]

time = ............ s

Marking points:
- substitution into $\text{speed}=\frac{\text{distance}}{\text{time}}$
- rearrangement
- evaluation

Example:
$3.0\times10^{8}=\frac{1.5}{t}$ $t=\frac{1.5}{3.0\times10^{8}}$ $t=5.0\times10^{-9}\ \mathrm{s}$

Accept:
- $5\times10^{-9}\ \mathrm{s}$
- $0.000000005\ \mathrm{s}$

Marking guidance:
- Deduct 1 mark for power-of-ten error.

[Maximum number: 3]

The photograph shows a toy called a marble run.

Figure for Question 3 — Edexcel IGCSE Physics

A student lifts a marble from the table to the top of the marble run at point A. They release the marble from point A and it rolls through pipes to reach the bottom of the marble run at point B.

The marble leaves the marble run at point B and rolls across the table.
As the marble rolls, energy is transferred due to the different forces acting on the marble.

The student wants to measure how much energy the marble loses as it moves from point A to point B .

The student needs to measure the speed of the marble as it leaves the marble run at point B .

Describe a method the student could use to measure this speed.

[Maximum number: 1]

The diagram shows a velocity-time graph for a car from the time the driver sees an obstacle in the road until the car comes to rest.

Figure for Question 4 — Edexcel IGCSE Physics

Which of these represents the distance-time graph for the car?

A

Figure for Question 4 — Edexcel IGCSE Physics — Option A

B

Figure for Question 4 — Edexcel IGCSE Physics — Option B

C

Figure for Question 4 — Edexcel IGCSE Physics — Option C

D

Figure for Question 4 — Edexcel IGCSE Physics — Option D

[Maximum number: 2]

A student does an experiment to determine the acceleration due to gravity, g.
The diagram shows the apparatus used.

Figure for Question 5 — Edexcel IGCSE Physics

This is the student's method.
- connect both light gates to a data logger
- drop a steel ball from rest at the top of the transparent tube
- record the speed of the ball at each light gate
- record the time taken for the ball to fall from light gate A to light gate B

The box shows the data recorded by the data logger.
speed at A $=1.45 \mathrm{~m} / \mathrm{s}$
speed at B $=4.20 \mathrm{~m} / \mathrm{s}$
time from A to $\mathrm{B}=0.286 \mathrm{~s}$

Show that the acceleration of the steel ball is approximately 9.6 m/s^2.

acceleration = ............ m/s^2

[Maximum number: 3]

A student does an experiment to determine the acceleration due to gravity, g.
The diagram shows the apparatus used.

Figure for Question 6 — Edexcel IGCSE Physics

This is the student's method.
- connect both light gates to a data logger
- drop a steel ball from rest at the top of the transparent tube
- record the speed of the ball at each light gate
- record the time taken for the ball to fall from light gate A to light gate B

The student changes the distance between the light gates by varying the position of light gate B.

The student measures the time taken for the steel ball to fall from light gate A to light gate B when the light gates are different distances apart.

The table shows the student's results.

Table for Question 6 — Edexcel IGCSE Physics

Explain how the graph shows that the steel ball is accelerating as it falls.

[Maximum number: 3]

The diagram shows a velocity-time graph for a car from the time the driver sees an obstacle in the road until the car comes to rest.

Figure for Question 7 — Edexcel IGCSE Physics

Calculate the acceleration of the car between 1.8 and 8.0 seconds.

acceleration = ............ m/s^2

Marking points:
- use of acceleration $=\frac{\text{change in velocity}}{\text{time}}$
- substitution
- evaluation

Example:
$\text{acceleration}=\frac{-30}{6.2}$ $\text{acceleration}=-4.8\ \mathrm{m\,s^{-2}}$

Accept:
- clear indication that acceleration is gradient
- -4.8 to $-5.0\ \mathrm{m\,s^{-2}}$

Ignore:
- minus sign

[Maximum number: 3]

The diagram shows a velocity-time graph for a car from the time the driver sees an obstacle in the road until the car comes to rest.

Figure for Question 8 — Edexcel IGCSE Physics

Calculate the braking distance of the car.

braking distance = ............ m

[Maximum number: 4]

A student stretches a rubber band.

The student stretches the rubber band and then releases it. The band moves vertically upwards.

The band travels with an initial speed of 13 m/s.

When the band reaches its maximum height above the student's hand, the band has a speed of 0 m/s.

Calculate the maximum height that the band reaches.
Give your answer to 2 significant figures.

height = ............ m

Marking points:
- substitution into the given equation $v^{2}=u^{2}+2as$
- rearrangement
- evaluation
- answer to 2 significant figures

Example:
$0^{2}=13^{2}+(2\times-10\times s)$ $\text{height}=\frac{169}{20}$ $\text{height}=8.45\ \mathrm{m}$ $\text{height}=8.5\ \mathrm{m}$

Accept:
- $mgh=\frac12mv^{2}$

Ignore:
- sign

Marking guidance:
- Answer to 2 significant figures is an independent mark.

Edexcel IGCSE Physics B Movement and Position Questions

Exam points

Covered syllabus points

Covered syllabus points

Question 1

Question (a)

Question (b)

Question (c)

Question 2

Question 3

Question 4

Question 5

Question 6

Question 7

Question 8

Question 9