Edexcel IGCSE Chemistry: Chemical Formulae, Equations & Calculations Question Bank
Practise balancing equations and using formulae, Mr and mole ratios for reacting masses, yields and composition.
- Syllabus
- First assessment 2019
- Course
- Chemistry 4CH1
Practise balancing equations and using formulae, Mr and mole ratios for reacting masses, yields and composition.
This question is about magnesium metal and its compounds.
Magnesium burns in oxygen gas to form solid magnesium oxide.
Complete the chemical equation for the reaction by balancing the equation and adding the state symbols.

2Mg(s)+OX2(g)2MgO(s)
Marking guidance:
- 1 mark for balancing.
- 1 mark for state symbols.
- Allow multiples or fractions, but OX2 must also be changed to score the balancing mark.
A student uses this method to make a solution of magnesium chloride.
Step 1. measure 25 cm3 of dilute hydrochloric acid into a beaker
Step 2 add magnesium powder a little at a time
Step 3 keep adding magnesium powder until it is in excess
Step 4 remove the excess magnesium powder by filtration
This is the equation for the reaction.

Calculate the minimum mass of magnesium needed to react with 25.0 cm3 of 2.00 mol/dm3 hydrochloric acid.
[for Mg,Ar=24 ]
mass = g
- amount of HCl = (25 x 2) / 1000 = 0.050 mol
- amount of magnesium = 0.050 / 2 = 0.025 mol
- mass of magnesium = 0.025 x 24 = 0.60 g / 0.6 g
Allow:
- ECF from amount of HCl divided by 2
- ECF from amount of magnesium multiplied by 24
Marking guidance:
- Answer of 0.60 g without working scores 3.
- Answer of 1.20 g with working scores 2.
Crude oil is a mixture of hydrocarbons.
One of the hydrocarbons in the refinery gas fraction is an alkane with the structural formula CH3CH2CH2CH3
Calculate the relative molecular mass (Mr) of this alkane.
(Mr = 4 x 12 + 10 x 1 =) 58
The diagram shows the positions of some elements in part of the Periodic Table.
Na Al S Cl
K Xe
In

A teacher adds a small piece of sodium to a glass trough containing water and universal indicator.
The universal indicator changes colour.
The equation for the reaction is
The reaction with sodium produces 0.036 g of hydrogen gas.
One mole of hydrogen gas contains 6.0×1023 molecules.
Calculate the number of molecules of hydrogen gas produced in the reaction with sodium.
Give your answer to two significant figures.
number of molecules of hydrogen gas =
- moles of hydrogen = 0.036 / 2 = 0.018 mol
- number of molecules = 0.018 x 6.0 x 10^23 = 1.08 x 10^22
- to two significant figures = 1.1 x 10^22
Allow:
- error carried forward from the mole calculation multiplied by 6.0 x 10^23
- error carried forward from the number of molecules, but the answer must be to 2 significant figures
Marking guidance:
- Correct answer with no working scores 3.
- 2.16 x 10^22 scores 1.
- 2.2 x 10^22 scores 2.