CAIE IGCSE Physics 4.2.3 Electromotive Force and Potential Difference Topic Practice

Question 1

[Maximum number: 2]

The electromotive force (e.m.f.) of a battery is 7.5 V .

Define the term electromotive force.

Question 2

[Maximum number: 2]

The unit of the two electrical quantities electromotive force (e.m.f.) and potential difference (p.d.) is the volt (V).

Question (a)

(a)

State one other similarity between e.m.f. and p.d.

[ 1 ]

Question (b)

(b)

State one difference between e.m.f. and p.d.

[ 1 ]

Question 3

[Maximum number: 5]

Question (a)

(a)

Define potential difference (p.d.).

[ 2 ]

Question (b)

(b)

State the equation which defines electromotive force (e.m.f.) E.

[ 1 ]

Question (c)

(c)

The e.m.f. of a battery is 9.0 V . The battery is in a circuit.

Calculate the work done by the battery when it moves a charge of 30 C around a complete circuit.

work done =
[ 2 ]

Question 4

[Maximum number: 1]

The unit of the two electrical quantities electromotive force (e.m.f.) and potential difference (p.d.) is the volt (V).

State one other similarity between e.m.f. and p.d.

Question 5

[Maximum number: 2]

Define potential difference (p.d.).

Question 6

[Maximum number: 1]

What is the unit of potential difference (p.d.)?

A

ampere

B

coulomb

C

coulomb / second

D

volt

Question 7

[Maximum number: 1]

Fig. 8.1 shows a circuit.

Fig. 8.1

Fig. 8.1

The potential difference (p.d.) across component Y is measured with a voltmeter.

On Fig. 8.1, draw the symbol for the voltmeter and its connections to the circuit.

Question 8

[Maximum number: 2]

Fig. 7.1 shows two charged metal plates. X marks the position of the centre of the space between the plates.

Fig. 7.1

Fig. 7.1

During a thunderstorm, an electric field is set up between a cloud and the ground. Charges on the cloud and on the ground are shown in Fig. 7.2.

Fig. 7.2

Fig. 7.2

The lightning shown in Fig. 7.2 discharges a current of 28000 A for 0.0012 s .

The lightning transfers 1.2×108 J1.2 \times 10^{8} \mathrm{~J} of energy.

Calculate the potential difference between the base of the cloud and the ground.
potential difference =
[Total: 7]

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