IB Physics SL A.2 Forces and Momentum Question Bank
Practise IB Physics SL A.2 by modelling forces, momentum and impulse with diagrams, equations and collision data.
- Syllabus
- First assessment 2025
- Course
- Physics SL
- Level
- SL
Practise IB Physics SL A.2 by modelling forces, momentum and impulse with diagrams, equations and collision data.
B3. This question is in two parts. Part 1 is about a collision. Part 2 is about electric current and resistance.
Part 1 A collision
Two identical blocks of mass 0.17 kg and length 0.050 m are travelling towards each other along a straight line through their centres as shown below. Assume that the surface is frictionless.

The initial distance between the centres of the blocks is 0.900 m and both blocks are moving at a speed of 0.18 m s−1 relative to the surface.
As a result of the collision, the blocks reverse their direction of motion and travel at the same speed as each other. During the collision, 20 % of the kinetic energy of the blocks is given off as thermal energy to the surroundings.
State and explain whether the collision is elastic or inelastic.
the collision is inelastic;
because kinetic energy is not conserved (although momentum is);
Show that the final speed of the blocks relative to the surface is 0.16 m s−1.
initial E_K = 1/2 x 0.17 x 0.18^2 = 0.002754 J;
final E_K = 0.80 x 0.002754 = 0.0022032 J;
State Newton's third law of motion.
if object A exerts a force on object B, then object B simultaneously exerts an equal and opposite force on object A / every action has an equal and opposite reaction / OWTTE;
During the collision of the blocks, the magnitude of the force that block A exerts on block B is FAB and the magnitude of the force that block B exerts on block A is FBA. On the diagram below, draw labelled arrows to represent the magnitude and direction of the forces FAB and FBA.
arrows of equal length; (judge by eye)
acting through centre of blocks;
correct labelling consistent with correct direction;

An elevator (lift) and its load accelerate vertically upwards.

Which statement is correct in this situation?
The net force on the load is zero.
The tension in the cable is equal but opposite to the combined weight of the elevator and its load.
The normal reaction force on the load is equal but opposite to the force on the elevator from the load.
The elevator and its load are in translational equilibrium.
C
A cylindrical cork of height H and cross-sectional area A is floating stationary in water. Its depth below the water surface is D.

Draw and label the forces acting on the cork.
Weight and Buoyancy drawn in proper directions (by eye) and correctly identified
Allow any sensible identification of the forces (e.g. mg for Fg )
Do not allow "gravity" for weight.
Show that
where ρc is the density of the cork and ρw is the density of water.
Weight =ρc⋅A⋅H⋅g
OR
Buoyancy =ρw⋅A⋅D⋅gρc⋅A⋅H⋅g=ρw⋅A⋅D⋅g
<<algebraic manipulation to show the relationship>>
An icebreaking ship is designed to withstand a collision with an iceberg, a large partially submerged body of ice freely floating in water. The designers model the shape of the iceberg as a cylinder with an approximate cross-sectional area of 4200 m2 and height above sea level of 32 m .
The following data are available:
Show that the mass of the iceberg is about 1.2×109 kg.
The designers assume that the mass of the ship is about 401 the mass of the iceberg and is moving at 12 m s−1 when it collides with the iceberg. They stick together after the collision.
«(H -32) /H = 920 / 1030 so » H=300 《m》 OR D=268 "m" m=920×300×4200 OR 1.16×109 "kg"
Must see either full substitution or answer to 3 or more significant
figures.
Calculate the speed of the ship after the collision.
Ice in a still lake will usually form in a single layer on the surface.
401m12=(401m+m)vv=0.29⟨ m s−1⟩