Question 1[Maximum number: 2]The radius of a nucleus of 82207 Pb{ }_{82}^{207} \mathrm{~Pb}82207 Pb is 7.1×10−15 m7.1 \times 10^{-15} \mathrm{~m}7.1×10−15 m. Suggest why there will be no deviations from Rutherford scattering in the experiment in (b)(i).Show AnswerThe closest approach is «significantly» larger than the radius of the nucleus / far away from the nucleus/OWTTE.«Therefore» the strong nuclear force will not act on the alpha particle. Add to Test