IB Physics HL D: Fields
Practise IB Physics HL fields through shared-core and HL electric, gravitational and magnetic problems, interpreting diagrams and measured data.
- Syllabus
- First assessment 2025
- Course
- Physics HL
- Level
- HL
Practise IB Physics HL fields through shared-core and HL electric, gravitational and magnetic problems, interpreting diagrams and measured data.
This question is in two parts. Part 1 is about gravitational force fields. Part 2 is about properties of a gas.
State Newton's universal law of gravitation.
the (attractive) force between two (point) masses is directly proportional to the product of the masses;
and inversely proportional to the square of the distance (between their centres of mass);
Use of equation is acceptable:
Marking guidance:
Award [2] if all five quantities defined. Award [1] if four quantities defined.
A satellite of mass m orbits a planet of mass M. Derive the following relationship between the period of the satellite T and the radius of its orbit R (Kepler's third law).
GR2Mm=Rmv2 so v2=RGm;
v=T2πR;(v2=)T24π2R2=RGm;
or
GR2Mm=mω2R;ω2=T24π2;T24π2=R3GM;
Marking guidance:
Award [3] to a clear response with a missing step.
A polar orbiting satellite has an orbit which passes above both of the Earth's poles. One polar orbiting satellite used for Earth observation has an orbital period of 6.00×103 s.
Using the relationship in (b), show that the average height above the surface of the Earth for this satellite is about 800 km .
R3=4×π26.67×10−11×5.97×1024×60002;
Award [3] for an answer of 740 with π taken as 3.14.
The satellite moves from an orbit of radius 1200 km above the Earth to one of radius 2500 km . The mass of the satellite is 45 kg .
Calculate the change in the gravitational potential energy of the satellite.
clear use of ΔV=mΔE and V=−rGm or ΔE=GMm(r11−r21);
one value of potential energy calculated (2.37×109 or 2.02×109);
Marking guidance:
Award [3] for a bald correct answer.
Explain whether the gravitational potential energy has increased, decreased or stayed the same when the orbit changes, as in (c)(ii).
increased; further from Earth / closer to infinity / smaller negative value;
Part 2 Properties of a gas
(a) ( Q ) energy transferred between two objects (at different temperatures);
( U ) (total) potential energy and (random) kinetic energy of the molecules/particles (of the gas);
(b) (i) use of area within cycle;
each large square has work value of 250 J ;
estimate (16×250=)4000 J; (allow 3600 - 4100)
(ii) (work is done by the gas because) area under expansion is greater than that under compression/pressure during expansion is greater than during compression;
(iii) clear attempt to compare two P V values; evaluate two P V values correctly eg 75×80=6000 and 200×30=6000;
(iv) use of P V=n R T or equivalent;
1350/1330 K;
(v) both changes are isochoric/isovolumetric/constant volume changes;
B: temperature/internal energy increases, D: temperature/internal energy decreases;
B: thermal energy/heat input (to system), D: thermal energy/heat output (from system);
B: pressure increases, D: pressure decreases;
Ion-thrust engines can power spacecraft. In this type of engine, ions are created in a chamber and expelled from the spacecraft. The spacecraft is in outer space when the propulsion system is turned on. The spacecraft starts from rest.

The mass of ions ejected each second is 6.6×10−6 kg and the speed of each ion is 5.2×104 m s−1. The initial total mass of the spacecraft and its fuel is 740 kg . Assume that the ions travel away from the spacecraft parallel to its direction of motion.
In practice, the ions leave the spacecraft at a range of angles as shown.

Outline why the ions are likely to spread out.
ions have same (sign of) charge ions repel each other
This question is in two parts. Part 1 is about photoelectricity. Part 2 is about electrical and magnetic force fields.
Part 1 Photoelectricity
Define electric field strength.
(a) force per unit charge; on a positive test charge / on a positive small charge;
(b) The diagram shows a pair of horizontal metal plates. Electrons can be deflected vertically using an electric field between the plates.

Label, on the diagram, the polarity of the metal plates which would cause an electron positioned between the plates to accelerate upwards.
(b) (i) top plate positive and bottom negative (or +/- and ground);
Draw the shape and direction of the electric field between the plates on the diagram.

uniform (by eye) line spacing and edge effect, field lines touching both plates; downward arrows (minimum of one and none upward);
Calculate the force on an electron between the plates when the electric field strength has a value of 2.5×103NC−1.
F=2.5×103×1.6×10−19;
4.0×10−16 N;
Marking guidance:
Award [2] for a bald correct answer.
The diagram shows two isolated electrons, X and Y , initially at rest in a vacuum. The initial separation of the electrons is 5.0 mm . The electrons subsequently move apart in the directions shown.

Show that the initial electric force acting on each electron due to the other electron is approximately 9×10−24 N.
(c) (i) use of F=4πε0(5.0×10−3)2(1.60×10−19)2 or F=(5.0×10−3)2(1.60×10−19)2×8.99×109;
9.2×10−24 N;
Discuss the motion of one electron after it begins to move.
electron will continue to accelerate;
speed increases with acceleration; acceleration reduces with separation;
when outside the field no further acceleration/constant speed;
any reference to accelerated charge radiating and losing (kinetic) energy;
The diagram shows Y as seen from X , at one instant. Y is moving into the plane of the paper. For this instant, draw on the diagram the shape and direction of the magnetic field produced by Y .
minimum of two concentric circles centred on Y ;
anti-clockwise;
B3. Alternative energy supplies
A conducting rod of length L is moved with speed v at right angles to a uniform magnetic field of flux density B. The field is directed into the plane of the page.

Show, using Faraday's law or otherwise, that the potential difference, V, established between the ends of the rod is V=v B L.
ALTERNATE 1
In time Δt, rod moves a distance vΔt
Flux increases by B(LvΔt)
«By Faraday» induced emf is the rate of change of flux: ΔtBLvΔt
«=BLv»
ALTERNATE 2
<<From ε=−ΔtNΔΦ≫
Recognition that Φ=BA
Recognition that N = 1
Recognition that ΔtΔA=Lv∨
<<Leading to V=vBL OR ε=BLv>
ALTERNATE 3
«In steady state» electrons stop drifting and so net force is zero q v B=q E
Substitution of E=LV to get result
ALT 1: Correct MP2 scores MP1
ALT2:
V and ε are interchangeable. Ignore negative sign.
[3]
A coil is rotating in a region of magnetic field with angular speed 12.56rads−1. At t=0, the field is parallel to the surface of the coil.

State the magnetic flux linkage through the coil at t=0.
Zerov
[1]
Draw, on the axes, a graph to show the variation with time of the induced emf in the loop. (No numbers are required on the vertical axis.)
emf

emf

Cosine OR negative cosine function
Period 0.5 s
[2]