1.4.5—Molar concentration
- Syllabus
- First assessment 2025
- Objective
- 1.4.5
- Level
- HL
Molar concentration is the amount of solute in moles per cubic decimetre of solution. Square brackets can denote molar concentration.
n=VCthereforeC=n/V
Use V in dm³ when calculating C in mol dm⁻³. Rearrange the same relationship to find amount or volume, and keep the solution volume distinct from the solute mass.
Convert volume before substitution: 500 cm³ = 0.500 dm³, so 0.250 mol in that solution gives C = 0.500 mol dm⁻³. The denominator is the final solution volume, not the volume or mass of solute alone.
Fordilutionwithnosolutelossorreaction:nbefore=nafter,soc1V1=c2V2
Adding solvent increases the final solution volume while the amount of solute stays constant, so concentration decreases. Use the final solution volume—not the solvent volume added—and do not apply c₁V₁ = c₂V₂ when solute reacts or is removed.
Questions calculate concentration from solute amount and solution volume, including a titration context.
calculate
Obtain moles when needed, divide by the stated equivalence or solution volume in dm³, and report mol dm⁻³ with the correct significant figures.
Using cm³ without conversion to dm³, or dividing by solute mass instead of solution volume.
Representative question
Calculate the molar concentration of the resulting solution of lithium hydroxide.
n(Li)=6.94 g mol−10.200 g=0.0288 moln(LiOH)=n(Li)=0.0288 mol[LiOH]=0.5000 dm30.0288 mol=0.0576 mol dm−3
Award [2] for the correct final answer.
Retrieve the quantitative chain: count entities with mN_A, sum relative masses from formulae, convert mass with n=m/M, derive formula ratios, use n=VC for solutions, and apply gas-volume ratios at the same temperature and pressure.
Before finalising, check the requested entity, formula subscripts, units, dm³ conversion, balanced-equation coefficients, and any limiting reactant.