CAIE A-Level Physics 10.2 Kirchhoff's Laws
Practise applying Kirchhoff’s laws, deriving series and parallel resistance formulae and solving multi-loop currents, potential differences and resistances.
- Syllabus
- 2028–2030
- Course
- Physics 9702
- Level
- AS
Practise applying Kirchhoff’s laws, deriving series and parallel resistance formulae and solving multi-loop currents, potential differences and resistances.
State Kirchhoff's first law.
sum of current(s) entering a junction = sum of current(s) leaving (the same junction)
or
(algebraic) sum of current (s) at a junction is zero
B1
A cell with internal resistance r is connected to two resistors of resistances R1 and R2 as shown in Fig. 6.1.

Fig. 6.1
The potential differences (p.d.s) across R1 and R2 are V1 and V2 respectively.
The terminal p.d. across the cell is V.
The current in the circuit is I.
Use Kirchhoff's laws to show that the total resistance RT of the external circuit is given by
(by Kirchhoff's second law) V=V1+V2
B1
so IRT=IR1+IR2( and cancelling I gives )RT=R1+R2
or
V/I=V1/I+V2/I (and substituting R gives) RT=R1+R2
B1
A resistor of resistance R3 is added to the circuit in Fig. 6.1, so that the circuit is as shown in Fig. 6.2.

Fig. 6.2
State and explain the effect, if any, of this change on:
the current in the cell
the (total) resistance (of the circuit) has decreased (and e.m.f. is unchanged)
M1
(the current (in the cell) will) increase
A1
State Kirchhoff's second law.
sum of e.m.f.(s) = sum of p.d.(s)
or (algebraic) sum of e.m.f.(s) and p.d.(s) is zero
M1
around a loop / around a closed circuit
A1