Practise calculating scalar products to find 3D angles, impose perpendicular conditions and locate the foot from a point to a line before deriving exact lengths or areas.
Syllabus
2028–2030
Course
Mathematics 9709
Level
A2
Exam points
calculate a·b and divide by |a||b|, using an absolute value for an acute line angle
set the displacement to a general line point perpendicular to its direction vector
solve the resulting parameter and use the foot, cosine or side lengths for exact geometry
3.7.6—Scalar product question 1
[Maximum number: 6]
9 Two lines l and m have equations r=3 i+2 j+5 k+s(4 i-j+3 k) and r=i-j-2 k+t(-i+2 j+2 k) respectively.
Question (a)
(a)
Show that l and m are perpendicular.
[ 2 ]
Use correct method to evaluate the scalar product of relevant vectors M1 ( -4-2+6 ) Obtain answer zero and deduce the given statement A1 Need a conclusion or a statement in advance that the scalar product will be zero.
Question (b)
(b)
Show that the length of the perpendicular from the origin to the line m is 315.
[ 4 ]
Taking a general point P on m, form an equation in t by either equating a relevant scalar product to zero, or equating the derivative of ∣OP∣ to zero, or taking a specific point Q on m, e.g. (1,-1,-2), using Pythagoras in triangle O P Q *M1 e.g. (1−t−1+2t−2+2t)⋅(−122)=0 Obtain t=97 A1 Carry out correct method to find O P DM1 Obtain 35 A1 Obtain the given answer from full and correct working. Alternative method for question 9(c) Take a specific point Q on m, e.g. ( -1,3,2 ) and use a scalar product to find Q N, the projection of O Q on m *M1 Obtain QN=311, or equivalent A1 Use Pythagoras to obtain O N DM1 Obtain the given answer correctly A1