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A-Level CAIE Mathematics A23.3 TrigonometryQuestion Bank

[Maximum number: 3]

Prove the identity cotxtanxcotx+tanxcos2x\frac{\cot x-\tan x}{\cot x+\tan x} \equiv \cos 2 x.

[Maximum number: 5]

Solve the equation cos(θ60)=3sinθ\cos \left(\theta-60^{\circ}\right)=3 \sin \theta, for 0θ3600^{\circ} \leqslant \theta \leqslant 360^{\circ}.

[Maximum number: 5]

Showing all necessary working, solve the equation cotθ+cot(θ+45)=2\cot \theta+\cot \left(\theta+45^{\circ}\right)=2, for 0<θ<1800^{\circ}<\theta<180^{\circ}.

[Maximum number: 5]

Solve the equation 5tan2θ=4cotθ5 \tan 2 \theta=4 \cot \theta for 0<θ<1800^{\circ}<\theta<180^{\circ}.

(a)

Given that tan2θcotθ=8\tan 2 \theta \cot \theta=8, show that tan2θ=34\tan ^{2} \theta=\frac{3}{4}.

[ 3 ]
(a)

Express 24sinθ7cosθ24 \sin \theta-7 \cos \theta in the form Rsin(θα)R \sin (\theta-\alpha), where R>0 and 0<α<900^{\circ}<\alpha<90^{\circ}. Give the value of α\alpha correct to 2 decimal places.

[ 3 ]
(b)

Hence find the smallest positive value of θ\theta satisfying the equation

24sinθ7cosθ=1724 \sin \theta-7 \cos \theta=17
[Maximum number: 5]

Express the equation secθ=3cosθ+tanθ\sec \theta=3 \cos \theta+\tan \theta as a quadratic equation in sinθ\sin \theta. Hence solve this equation for 90<θ<90-90^{\circ}<\theta<90^{\circ}.

[Maximum number: 6]

By first expressing the equation tan(x+45)=2cotx+1\tan \left(x+45^{\circ}\right)=2 \cot x+1 as a quadratic equation in tanx\tan x, solve the equation for 0<x<1800^{\circ}<x<180^{\circ}.

[Maximum number: 5]

Showing all necessary working, solve the equation cot2θ=2tanθ\cot 2 \theta=2 \tan \theta for 0<θ<1800^{\circ}<\theta<180^{\circ}.

(a)

Show that 12sin2xcos2x32(1cos4x)12 \sin ^{2} x \cos ^{2} x \equiv \frac{3}{2}(1-\cos 4 x).

[ 3 ]
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