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A-Level CAIE Mathematics A23.6 Numerical solution of equationsQuestion Bank

(a)

By sketching suitable graphs, show that the equation e12x=4x2\mathrm{e}^{-\frac{1}{2} x}=4-x^{2} has one positive root and one negative root.

[ 2 ]
(b)

Verify by calculation that the negative root lies between -1 and -1.5 .

[ 2 ]
(c)

Use the iterative formula xn+1=(4e12xn)x_{n+1}=-\sqrt{ }\left(4-e^{-\frac{1}{2} x_{n}}\right) to determine this root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

[ 3 ]
[Maximum number: 6]

The equation x53x3+x24=0x^{5}-3 x^{3}+x^{2}-4=0 has one positive root.

(a)

Verify by calculation that this root lies between 1 and 2 .

[ 2 ]
(b)

Show that the equation can be rearranged in the form

x=(33x+4x21)\left.x=\sqrt[3]{( } 3 x+\frac{4}{x^{2}}-1\right)
[ 1 ]
(c)

Use an iterative formula based on this rearrangement to determine the positive root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

[ 3 ]
(a)

By sketching suitable graphs, show that the equation

4x21=cotx4 x^{2}-1=\cot x

has only one root in the interval 0<x<12π0<x<\frac{1}{2} \pi.

[ 2 ]
(b)

Verify by calculation that this root lies between 0.6 and 1 .

[ 2 ]
(c)

Use the iterative formula

xn+1=12(1+cotxn)x_{n+1}=\frac{1}{2} \sqrt{ }\left(1+\cot x_{n}\right)

to determine the root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

[ 3 ]
[Maximum number: 2]

A curve has parametric equations

x=t2+3t+1,y=t4+1x=t^{2}+3 t+1, \quad y=t^{4}+1

The point P on the curve has parameter p. It is given that the gradient of the curve at P is 4 .

(a)

Verify by calculation that the value of p lies between 1.8 and 2.0.

[ 2 ]
(b)

Use an iterative formula based on the equation in part (i) to find the value of p correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

(a)

By sketching a suitable pair of graphs, show that the equation secx=212x\sec x=2-\frac{1}{2} x has exactly one root in the interval 0x<12π0 \leqslant x<\frac{1}{2} \pi.

[ 2 ]
(b)

Verify by calculation that this root lies between 0.8 and 1 .

[ 2 ]
(c)

Use the iterative formula xn+1=cos1(24xn)x_{n+1}=\cos ^{-1}\left(\frac{2}{4-x_{n}}\right) to determine the root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

[ 3 ]
(a)

The sequence of values given by the iterative formula

xn+1=πsin1(1e12xn+1),x_{n+1}=\pi-\sin ^{-1}\left(\frac{1}{\mathrm{e}^{-\frac{1}{2} x_{n}}+1}\right),

with initial value x1=2x_{1}=2, converges to one of these roots.
Use the formula to determine this root correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

[ 3 ]
[Maximum number: 5]

The curve with equation

y=5e2x8x220y=5 \mathrm{e}^{2 x}-8 x^{2}-20

crosses the x-axis at only one point. This point has coordinates (p, 0).

(a)

Show by calculation that 0.75<p<0.85.

[ 2 ]
(b)

Use an iterative formula based on the equation in part (i) to find the value of p correct to 5 significant figures. Give the result of each iteration to 7 significant figures.

[ 3 ]
[Maximum number: 7]

The equation x=10e2x1x=\frac{10}{\mathrm{e}^{2 x}-1} has one positive real root, denoted by α\alpha.

(a)

Show that α\alpha lies between x=1 and x=2.

[ 2 ]
(b)

Show that if a sequence of positive values given by the iterative formula

xn+1=12ln(1+10xn)x_{n+1}=\frac{1}{2} \ln \left(1+\frac{10}{x_{n}}\right)

converges, then it converges to α\alpha.

[ 2 ]
(c)

Use this iterative formula to determine α\alpha correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

[ 3 ]
[Maximum number: 3]
Question image

The diagram shows a semicircle A C B with centre O and radius r. The tangent at C meets A B produced at T. The angle B O C is x radians. The area of the shaded region is equal to the area of the semicircle.

(a)

Use the iterative formula xn+1=tan1(xn+π)x_{n+1}=\tan ^{-1}\left(x_{n}+\pi\right) to determine x correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

[ 3 ]
[Maximum number: 3]
Question image

The diagram shows the curve y=sinxxy=\frac{\sin x}{x} for 0<x2π0<x \leqslant 2 \pi, and its minimum point M.

(a)

The iterative formula

xn+1=tan1(xn)+πx_{n+1}=\tan ^{-1}\left(x_{n}\right)+\pi

can be used to determine the x-coordinate of M. Use this formula to determine the x-coordinate of M correct to 2 decimal places. Give the result of each iteration to 4 decimal places.

[ 3 ]
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