Question 6(b)[Maximum number: 4]Hence show that ∫14π13π(cosec2θ−cot2θ)dθ=12ln2\int_{\frac{1}{4} \pi}^{\frac{1}{3} \pi}(\operatorname{cosec} 2 \theta-\cot 2 \theta) \mathrm{d} \theta=\frac{1}{2} \ln 2∫41π31π(cosec2θ−cot2θ)dθ=21ln2.Show AnswerAdd to Test