CAIE A-Level Mathematics 3.3 Trigonometry Question Bank

CAIE A-Level Mathematics 3.3 Trigonometry Question Bank
Cambridge International AS & A Level Mathematics 9709 syllabus for exams in 2028, 2029 and 20302028–2030

Practise selecting compound-, double-angle, reciprocal and R-form identities to prove results, simplify expressions and solve every valid angle in a stated interval.

Exam points

  • select compound- or double-angle identities that reduce the expression to one useful form
  • write a sin x + b cos x as R sin(x ± α) or R cos(x ± α), finding exact R and α
  • solve the transformed equation and generate all interval solutions without introducing extra roots

Question 6(d)

[Maximum number: 3]

The polynomials f(x) and g(x) are defined by

f(x)=4x3+ax2+8x+15 and g(x)=x2+bx+18\mathrm{f}(x)=4 x^{3}+a x^{2}+8 x+15 \quad \text { and } \quad \mathrm{g}(x)=x^{2}+b x+18

where a and b are constants.

Hence solve the equation f(cosecθ)g(cosecθ)=0\mathrm{f}(\operatorname{cosec} \theta)-\mathrm{g}(\operatorname{cosec} \theta)=0 for 0<θ<2π0<\theta<2 \pi.

Question 7

Question 7(a)

(a)

Prove that cos(θ+30)cos(θ+60)14312sin2θ\cos \left(\theta+30^{\circ}\right) \cos \left(\theta+60^{\circ}\right) \equiv \frac{1}{4} \sqrt{3}-\frac{1}{2} \sin 2 \theta.

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Question 7(b)

(b)

Solve the equation 5cos(2α+30)cos(2α+60)=15 \cos \left(2 \alpha+30^{\circ}\right) \cos \left(2 \alpha+60^{\circ}\right)=1 for 0<α<900^{\circ}<\alpha<90^{\circ}.

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Question 7(c)

(c)

Show that the exact value of cos20cos50+cos40cos70\cos 20^{\circ} \cos 50^{\circ}+\cos 40^{\circ} \cos 70^{\circ} is 123\frac{1}{2} \sqrt{3}.

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