Edexcel IGCSE Chemistry G Acids Bases and Salt Preparations Questions

Practise acids-bases-salts questions by applying proton definitions, choosing salt reagents and sequencing crystal preparation.

Syllabus
First assessment 2019
Course
Chemistry 4CH1

Exam points

  • Link acids to proton donation and bases to proton acceptance in reaction statements.
  • Use solubility rules to choose reagents and predict precipitates in salt preparations.
  • Describe filtering, evaporating, crystallising and drying to obtain pure salts.

Question 1

[Maximum number: 1]

This question is about Group 2 elements and their compounds.

Which of these compounds is an insoluble solid?

A

calcium nitrate

B

calcium sulfate

C

magnesium nitrate

D

magnesium sulfate

Question 2

[Maximum number: 6]

This question is about salts.

Question (a)

(a)

Soluble salts can be prepared by the reaction between a metal oxide and an acid.

The equation for this type of reaction is

metal oxide + acid → salt + water
[ 1 ]

Question (i)

(i)

State, in terms of protons, what happens in this reaction.

[ 1 ]

Question (b)

(b)

A student is given 50 cm350 \mathrm{~cm}^{3} of dilute sulfuric acid and a bottle of solid copper(II) carbonate.

Describe the method that the student should use to prepare a saturated solution of copper(II) sulfate.

In your answer, refer to the pieces of apparatus that the student should use.

[ 5 ]

Question 3

[Maximum number: 1]

Sodium hydroxide dissolves in water, forming a strongly alkaline solution.
Ammonia dissolves in water, forming a slightly less alkaline solution.

When ammonia solution reacts with sulfuric acid, a neutralisation reaction occurs and ammonium sulfate forms.

How does the sulfuric acid act in this reaction?

A

as a neutron donor

B

as a neutron acceptor

C

as a proton donor

D

as a proton acceptor

Question 4

[Maximum number: 1]

This question is about salts.

Soluble salts can be prepared by the reaction between a metal oxide and an acid.

The equation for this type of reaction is

metal oxide + acid → salt + water

State, in terms of protons, what happens in this reaction.

Question 5

[Maximum number: 1]

A student uses this apparatus to investigate the rate of reaction between marble chips and dilute hydrochloric acid.

Figure for Question 5 — Edexcel IGCSE Chemistry

The equation for the reaction is

CaCO3+2HCl→CaCl2+H2O+CO2\mathrm{CaCO}_{3}+2 \mathrm{HCl} \rightarrow \mathrm{CaCl}_{2}+\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2}

During the reaction the mass of the contents of the flask decreases.

State why the mass of the contents of the flask decreases.

Question 6

[Maximum number: 1]

This question is about magnesium metal and its compounds.

A student uses this method to make a solution of magnesium chloride.

Step 1. measure 25 cm325 \mathrm{~cm}^{3} of dilute hydrochloric acid into a beaker
Step 2 add magnesium powder a little at a time
Step 3 keep adding magnesium powder until it is in excess
Step 4 remove the excess magnesium powder by filtration

This is the equation for the reaction.

Figure for Question 6 — Edexcel IGCSE Chemistry

Give a reason why the student adds an excess of magnesium in step 3.

Question 7

[Maximum number: 4]

Sodium sulfate can be prepared by the reaction between sodium hydroxide solution and sodium hydrogensulfate ( NaHSO4\mathrm{NaHSO}_{4} ) solution.

This is the equation for the reaction.

NaOH(aq)+NaHSO4(aq)→Na2SO4(aq)+H2O(l)\mathrm{NaOH}(\mathrm{aq})+\mathrm{NaHSO}_{4}(\mathrm{aq}) \rightarrow \mathrm{Na}_{2} \mathrm{SO}_{4}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l})

Sodium hydrogensulfate solution is acidic.
A student adds 25.0 cm325.0 \mathrm{~cm}^{3} of sodium hydroxide solution to a conical flask and adds two drops of indicator.

The student does a titration.

The student repeats the titration without the indicator and forms a solution of sodium sulfate.

Describe how the student can obtain pure, dry crystals of hydrated sodium sulfate from the solution.

Question 8

[Maximum number: 3]

A scientist reacts lead(II) nitrate solution with sodium bromide solution.

This is the equation for the reaction.

Pb(NO3)2(aq)+2NaBr(aq)→PbBr2( s)+2NaNO3(aq)\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})+2 \mathrm{NaBr}(\mathrm{aq}) \rightarrow \mathrm{PbBr}_{2}(\mathrm{~s})+2 \mathrm{NaNO}_{3}(\mathrm{aq})

Describe how the scientist could obtain a pure dry sample of lead(II) bromide (PbBr2)\left(\mathrm{PbBr}_{2}\right) from the reaction mixture.

Question 9

[Maximum number: 9]

A salt can be made by reacting an acid with an insoluble base.
A student has a sample of copper(II) oxide.

Stage 1 pour 50 cm350 \mathrm{~cm}^{3} of dilute sulfuric acid into a beaker
Stage 2 warm the acid using a Bunsen burner
Stage 3 add a small amount of copper(II) oxide to the warm acid and stir the mixture
Stage 4 add further amounts of copper(II) oxide until copper(II) oxide is in excess
Stage 5 filter the mixture
Stage 6 obtain crystals from the filtrate

Question (a)

(a)

State why the acid is warmed in stage 2.

[ 1 ]

Question (b)

(b)

State how the student would know that the copper(II) oxide is in excess in stage 4.

[ 1 ]

Question (c)

(c)

State why the mixture is filtered in stage 5.

[ 1 ]

Question (d)

(d)

State the colour of the filtrate obtained in stage 5.

[ 1 ]

Question (e)

(e)

Describe how the student could obtain a pure, dry sample of hydrated copper(II) sulfate crystals from the filtrate in stage 6.

[ 5 ]

Question 10

[Maximum number: 3]

This question is about soluble salts and insoluble salts.

When solutions of lead nitrate and sodium sulfate are mixed, one product is solid lead sulfate.

This is the equation for the reaction.

Pb(NO3)2(aq)+Na2SO4(aq)→PbSO4( s)+2NaNO3(aq)\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(\mathrm{aq})+\mathrm{Na}_{2} \mathrm{SO}_{4}(\mathrm{aq}) \rightarrow \mathrm{PbSO}_{4}(\mathrm{~s})+2 \mathrm{NaNO}_{3}(\mathrm{aq})

Describe how a pure, dry sample of solid lead sulfate can be obtained from the mixture.

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