CAIE IGCSE Physics Effects of Forces Question Bank
Practise resultant forces, friction, drag, springs and circular motion, linking force to deformation, acceleration, equilibrium and changes in velocity.
- Syllabus
- 2026–2028
- Course
- Physics 0625
Practise resultant forces, friction, drag, springs and circular motion, linking force to deformation, acceleration, equilibrium and changes in velocity.
A resultant force is applied to an object moving with a velocity v in a straight line.
State two different changes to the motion that the resultant force may cause.
1
2
direction (changes)
B1
any one from:
- magnitude of the velocity (changes)
- speed (changes)
- (there is) acceleration
B1
State one other way that forces may change a stationary object.
any one from:
- (change) size
- (change) shape
B1
A force is a vector quantity.
A student suspends a spring from a clamp stand and measures the length l0 of the spring.
Fig. 2.1 shows the apparatus.

Fig. 2.1 (not to scale)
The student then suspends loads of different weights from the spring and measures the length of the spring for each load. He then plots a graph of the length of the spring against weight.
Fig. 2.2 is the graph that the student plots.

Fig. 2.2
Using Fig. 2.2, determine the initial length l0 of the spring.
0.12 m
B1
State what is meant by the limit of proportionality and, using Fig. 2.2, determine the weight of the load that causes this spring just to reach the limit of proportionality.
limit of proportionality
weight =
B2
beyond where the extension is not directly proportional to the load or (point) where extension stops being directly proportional to the load or point up to which extension is directly proportional to the load
B1
10.4 N⩽ weight ⩽10.9 N
B1
Using Fig. 2.2, determine the spring constant of this spring.
spring constant =
22 N/m ≤ k ≤ 25 N/m
A3
clear subtraction of 0.12 from a length that is in Hooke’s law region e.g. 0.54 – 0.12
C1
k = F/x in any form OR k = W/x in any form OR k = 1/gradient
C1
A 20 N force and a 15 N force act at the same time on an object of mass 14 kg .
Calculate
the maximum possible force on the object due to these two forces,
force =
35 N
B1
the acceleration caused by a resultant force equal to this maximum force.
acceleration =
(a=)F÷m or 35÷14 (e.c.f.(i)) 2.5 m/s2 (e.c.f.(i))
C1
A1