Question 1
A car has a weight of 13000 N . The car is supported by 4 tyres. The area of each tyre in contact with the road is .
Calculate the pressure on the road due to the weight of the car.
A car has a weight of 13000 N . The car is supported by 4 tyres. The area of each tyre in contact with the road is 0.016 m2.
Calculate the pressure on the road due to the weight of the car.
2.0×105 Pa OR 200000 Pa OR 200 kPa
( P= ) F / A OR 13000/(0.016×4)
Fig. 3.1 shows a person moving across an ice-covered pond to reach a ball on the ice.
Fig. 3.1
Explain why this way of moving across the ice is safer than walking. Use your understanding of pressure in your answer.
(force of gravity / weight of person is spread over a much) greater area
p=F/AORp∝1/A
(force is same so) pressure is lower (so ice is less likely to crack)
Fig. 3.2 shows a side view of the pond with a layer of ice floating freely on the water.
Fig. 3.2
The surface area of the pond is 5.0 m2.
The mass of the ice is 690 kg.
The density of water is 1000 kg/m3.
Point X is 0.45 m below the ice.
Calculate the pressure at point X due to the ice and the water.
pressure =
5.8×103 Pa
p (due to water) =ρgh R(p=)ρgh R(p=)1000×9.8×0.45 OR(p=)4410W=mgOR(W=)mgOR(W=)(690×9.8)OR(W=)6762OR(p( due to ice )=) 1352.4
(pressure =) candidate's calculated pressure due to water + candidate's calculated pressure due to ice
OR total pressure =[1000×9.8×0.45]+[(690×9.8)/5.0]
OR total pressure =4410+1352.4
Which row describes how the pressure beneath the surface of a liquid depends on the depth below the surface and on the density of the liquid?
depth below surface
density of liquid
pressure decreases with increasing depth
pressure decreases with increasing density
pressure decreases with increasing depth
pressure increases with increasing density
pressure increases with increasing depth
pressure decreases with increasing density
pressure increases with increasing depth
pressure increases with increasing density
D