E4.6 Angles

Syllabus
0580–2028–2029
Topic
E4.6
Level
Extended

Learning objectives

Build angle chains from basic facts

An angle chain finds one unknown at a time and states the exact geometric fact that fixes each step.

Configuration Angle fact Reason to state
angles around one point sum to 360360^\circ angles at a point
adjacent angles on a straight line sum to 180180^\circ angles on a straight line
opposite angles where two lines cross are equal vertically opposite angles
three interior angles of a triangle sum to 180180^\circ angles in a triangle
four interior angles of a quadrilateral sum to 360360^\circ angles in a quadrilateral

Mark every known angle, choose the smallest shape or line containing one unknown, write its angle equation, solve it, then transfer that value to the next step. For an isosceles triangle, first mark the equal base angles only after confirming which sides are equal.

In isosceles triangle ABCABC, let AB=ACAB=AC and BAC=38\angle BAC=38^\circ. Then ABC=BCA=(18038)÷2=71\angle ABC=\angle BCA=(180^\circ-38^\circ)\div2=71^\circ. If BCBC is extended to DD, ACD=18071=109\angle ACD=180^\circ-71^\circ=109^\circ because angles on a straight line sum to 180180^\circ.

Do not use a fact because the diagram looks suitable: verify the straight line, intersection, equal sides or closed shape. A numerical answer without the requested geometric reason leaves the angle chain unsupported.

Use angles in parallel lines

When a transversal crosses parallel lines, its intersections repeat equal-angle positions and create supplementary interior pairs.

Relationship Position Fact
corresponding same relative corner at the two intersections equal
alternate inside the parallel lines on opposite sides of the transversal equal
co-interior inside the parallel lines on the same side of the transversal sum to 180180^\circ

Confirm the pair of lines is parallel, identify the one transversal that creates both angles, then classify their positions before calculating. Transfer an equal corresponding or alternate angle directly; subtract a co-interior angle from 180180^\circ. Combine these facts with vertically opposite, straight-line or triangle facts only in separate, reasoned steps.

If parallel lines ABAB and CDCD are cut by transversal EFEF and one acute angle is 3838^\circ, its alternate and corresponding acute angles are also 3838^\circ. Each adjacent obtuse angle is 18038=142180^\circ-38^\circ=142^\circ; the matching co-interior pair is supplementary.

Corresponding and alternate angles are equal only when the lines are parallel. Co-interior angles are not equal in general; they add to 180180^\circ. State the relationship by position, not by a memorised letter shape alone.

Calculate angles in polygons

An nn-sided polygon can be split from one vertex into n2n-2 triangles, so its interior-angle sum is controlled by the number of sides.

S_{\text{interior}}=(n-2)\times180^\circ,\qquad e_{\text{regular}}=\frac{360^\circ}{n},\qquad i_{\text{regular}}=180^\circ-e

For an irregular polygon, find the total (n2)×180(n-2)\times180^\circ and subtract the known interior angles. For a regular polygon, equal exterior angles make one full turn, so divide 360360^\circ by nn; the adjacent interior and exterior angles sum to 180180^\circ. To recover nn, use n=360/en=360^\circ/e and check that the answer is a whole number.

A hexagon has interior sum (62)×180=720(6-2)\times180^\circ=720^\circ. If five interior angles are each 115115^\circ, the sixth is 7205×115=145720^\circ-5\times115^\circ=145^\circ. A regular 24-gon has exterior angle 360÷24=15360^\circ\div24=15^\circ and interior angle 165165^\circ.

In ABC\angle ABC, the middle letter BB is the vertex. Do not divide an irregular polygon's total by nn unless all its interior angles are equal, and use precise reasons such as ‘exterior angles of a polygon sum to 360360^\circ’.