E4.6 Angles
- Syllabus
- 0580–2028–2029
- Topic
- E4.6
- Level
- Extended
An angle chain finds one unknown at a time and states the exact geometric fact that fixes each step.
| Configuration | Angle fact | Reason to state |
|---|---|---|
| angles around one point | sum to 360∘ | angles at a point |
| adjacent angles on a straight line | sum to 180∘ | angles on a straight line |
| opposite angles where two lines cross | are equal | vertically opposite angles |
| three interior angles of a triangle | sum to 180∘ | angles in a triangle |
| four interior angles of a quadrilateral | sum to 360∘ | angles in a quadrilateral |
Mark every known angle, choose the smallest shape or line containing one unknown, write its angle equation, solve it, then transfer that value to the next step. For an isosceles triangle, first mark the equal base angles only after confirming which sides are equal.
In isosceles triangle ABC, let AB=AC and ∠BAC=38∘. Then ∠ABC=∠BCA=(180∘−38∘)÷2=71∘. If BC is extended to D, ∠ACD=180∘−71∘=109∘ because angles on a straight line sum to 180∘.
Do not use a fact because the diagram looks suitable: verify the straight line, intersection, equal sides or closed shape. A numerical answer without the requested geometric reason leaves the angle chain unsupported.
When a transversal crosses parallel lines, its intersections repeat equal-angle positions and create supplementary interior pairs.
| Relationship | Position | Fact |
|---|---|---|
| corresponding | same relative corner at the two intersections | equal |
| alternate | inside the parallel lines on opposite sides of the transversal | equal |
| co-interior | inside the parallel lines on the same side of the transversal | sum to 180∘ |
Confirm the pair of lines is parallel, identify the one transversal that creates both angles, then classify their positions before calculating. Transfer an equal corresponding or alternate angle directly; subtract a co-interior angle from 180∘. Combine these facts with vertically opposite, straight-line or triangle facts only in separate, reasoned steps.
If parallel lines AB and CD are cut by transversal EF and one acute angle is 38∘, its alternate and corresponding acute angles are also 38∘. Each adjacent obtuse angle is 180∘−38∘=142∘; the matching co-interior pair is supplementary.
Corresponding and alternate angles are equal only when the lines are parallel. Co-interior angles are not equal in general; they add to 180∘. State the relationship by position, not by a memorised letter shape alone.
An n-sided polygon can be split from one vertex into n−2 triangles, so its interior-angle sum is controlled by the number of sides.
S_{\text{interior}}=(n-2)\times180^\circ,\qquad e_{\text{regular}}=\frac{360^\circ}{n},\qquad i_{\text{regular}}=180^\circ-e
For an irregular polygon, find the total (n−2)×180∘ and subtract the known interior angles. For a regular polygon, equal exterior angles make one full turn, so divide 360∘ by n; the adjacent interior and exterior angles sum to 180∘. To recover n, use n=360∘/e and check that the answer is a whole number.
A hexagon has interior sum (6−2)×180∘=720∘. If five interior angles are each 115∘, the sixth is 720∘−5×115∘=145∘. A regular 24-gon has exterior angle 360∘÷24=15∘ and interior angle 165∘.
In ∠ABC, the middle letter B is the vertex. Do not divide an irregular polygon's total by n unless all its interior angles are equal, and use precise reasons such as ‘exterior angles of a polygon sum to 360∘’.