E4.8 Circle theorems II
- Syllabus
- 0580–2028–2029
- Topic
- E4.8
- Level
- Extended
A circle is symmetric about every line through its centre, so matching chords or tangents create equal lengths and perpendicular bisectors that can be used as exact geometric reasons.
| Configuration to recognise | Property to use | Useful conclusion |
|---|---|---|
| two equal chords in the same circle | equal chords are equidistant from the centre | perpendicular distances from the centre to the chords are equal |
| a chord and its perpendicular bisector | the perpendicular bisector of a chord passes through the centre | joining the centre to the chord's midpoint gives a right angle to the chord |
| two tangents drawn from one external point | tangents from an external point are equal in length | the two tangent segments form an isosceles triangle |
For a chord, the perpendicular from the centre splits it into two equal halves: the two right triangles contain equal radii and matching half-chords, so the distance from the centre is fixed. For tangents TP and TQ, radii OP and OQ are perpendicular to the tangents; right triangles OPT and OQT share hypotenuse OT and have OP=OQ, so congruence gives TP=TQ.
Mark the centre, chord midpoints, perpendicular signs, radii, tangent contact points and the common external point. State the circle property first, then use congruence, Pythagoras or ordinary angle facts only as separate justified steps.
In one circle, equal chords AB and CD have perpendicular distances OM=5 cm and ON from centre O. Then ON=5 cm because equal chords are equidistant from the centre. If tangents from T touch at P and Q and TP=8 cm, then TQ=8 cm because tangents from the same external point are equal.
Distance from the centre to a chord means the perpendicular distance, not a sloping segment to an endpoint. Tangent lengths are equal only when both tangents start from the same external point, and a chord's perpendicular bisector—not every perpendicular line—must pass through the centre.